Chapter 18: Problem 5
Calculate the oxidation number for nitrogen in the following compounds: (a) \(\mathrm{NH}_{3}\) (b) \(\mathrm{N}_{2} \mathrm{O}_{4}\) (c) \(\mathrm{Li}_{3} \mathrm{~N}\) (d) \(\mathrm{KNO}_{3}\)
Short Answer
Expert verified
(a) -3, (b) +4, (c) -3, (d) +5.
Step by step solution
01
Understand the Basic Rules
To calculate the oxidation number of nitrogen, we need to apply these rules:1. The oxidation number of a pure element (e.g., \( ext{N}_2\)) is 0.2. The sum of the oxidation numbers for all atoms in a neutral compound is 0. 3. In compounds, hydrogen generally has an oxidation number of +1, and oxygen has -2.4. Alkali metals (like K) have an oxidation number of +1, and alkaline earth metals (like Li) have +2.
02
Calculate for \\(\mathrm{NH}_3\\)
In ammonia, \( ext{NH}_3\), the oxidation number of hydrogen (H) is +1. Since there are three hydrogen atoms, their total contribution is +3. The compound is neutral, which means the sum of oxidation numbers is 0. Let the oxidation number of nitrogen be \( ext{x}\). The equation is:\[x + 3(+1) = 0\]\[x + 3 = 0\]Solving for \( ext{x}\), we get \( ext{x} = -3\).Thus, the oxidation number of nitrogen in \( ext{NH}_3\) is -3.
03
Calculate for \\(\mathrm{N}_2\mathrm{O}_4\\)
In the compound \(\mathrm{N}_2\mathrm{O}_4\), the oxidation number of oxygen (O) is -2. There are four oxygens, so the total contribution is -8. The molecule is neutral, so the sum of the oxidation numbers must be 0. Let the oxidation number of nitrogen be \(\text{y}\).\[2(\text{y}) + 4(-2) = 0\]\[2\text{y} - 8 = 0\]Solving for \(\text{y}\), we find \(\text{y} = +4\).Thus, the oxidation number of nitrogen in \(\mathrm{N}_2\mathrm{O}_4\) is +4.
04
Calculate for \\(\mathrm{Li}_3\mathrm{N}\\)
In lithium nitride, \(\mathrm{Li}_3\mathrm{N}\), lithium (Li) has an oxidation number of +1. With three lithium atoms, their total contribution is +3. The compound is neutral, so the sum of the oxidation numbers is 0. If \(\text{z}\) is the oxidation number of nitrogen:\[3(\text{+1}) + \text{z} = 0\]\[3 + \text{z} = 0\]Solving for \(\text{z}\), we obtain \(\text{z} = -3\).Therefore, the oxidation number of nitrogen in \(\mathrm{Li}_3\mathrm{N}\) is -3.
05
Calculate for \\(\mathrm{KNO}_3\\)
In potassium nitrate, \(\mathrm{KNO}_3\), potassium (K) contributes +1, each oxygen contributes -2 (for a total of -6 from three oxygens), and the compound as a whole is neutral. Let \(\text{w}\) be the oxidation number of nitrogen:\[\text{+1} + \text{w} + 3(-2) = 0\]\[1 + \text{w} - 6 = 0\]\[\text{w} - 5 = 0\]Solving for \(\text{w}\), we find \(\text{w} = +5\).Thus, the oxidation number of nitrogen in \(\mathrm{KNO}_3\) is +5.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ammonia
Ammonia, represented chemically as \( \mathrm{NH}_3 \), is a simple compound consisting of one nitrogen atom bonded to three hydrogen atoms. It is a colorless gas with a pungent smell and is widely used in fertilizers, cleaning products, and as an industrial chemical. The key aspect of ammonia from a chemical perspective is understanding its structure as a combination of nitrogen and hydrogen. In terms of molecular geometry, ammonia has a trigonal pyramidal shape due to the lone pair of electrons on nitrogen. This shape plays a crucial role in the molecule's reactivity and interactions.
- Ammonia is composed of three hydrogen atoms, each contributing an oxidation number of \(+1\).
- Because the compound is neutral, the total oxidation state sums up to zero.
- To balance the positive charge contributed by hydrogen, the oxidation number of nitrogen in ammonia is \(-3\).
Nitrogen
Nitrogen, with the chemical symbol \( N \), is a non-metal present in Group 15 of the periodic table. It is a key component of amino acids, proteins, and nucleic acids, which are crucial for life. Elemental nitrogen exists as a diatomic molecule \( \mathrm{N}_2 \) and is abundant in Earth's atmosphere, comprising about 78% by volume.
- Nitrogen can show different oxidation states, ranging from \(-3\) to \(+5\).
- This wide range is due to the ability of nitrogen to bond with various elements and form complex compounds.
- In ammonia \((\mathrm{NH}_3)\), nitrogen has an oxidation number of \(-3\).
Oxidation Rules
Oxidation rules are the guidelines used to assign oxidation numbers to atoms in compounds. These numbers help chemists understand how electrons are distributed among the atoms in a molecule, predicting reactivity and chemical reactions. The key rules are:
- The oxidation number of an element in its pure form is always zero (e.g., \( \mathrm{N}_2 \))
- The oxidation number of a monatomic ion equals its charge.
- Alkali metals (like \( \mathrm{K} \)) always have an oxidation number of \(+1\), while alkaline earth metals like \( \mathrm{Li} \) have \(+2\).
- Hydrogen generally has an oxidation number of \(+1\) when bonded to non-metals.
- Oxygen typically has an oxidation number of \(-2\).
- The sum of oxidation numbers in a neutral compound is zero.
Neutral Compound
A neutral compound is defined by the total electric charge being zero, meaning the sum of all positive and negative charges in the molecule equals zero. This is a fundamental rule in chemistry that holds for most stable, non-ionic compounds.
- If a molecule is composed of atoms with oxidation numbers, the sum must be zero to maintain neutrality.
- In ammonia \( (\mathrm{NH}_3) \), the nitrogen and hydrogen atoms have oxidation numbers that balance each other to result in a net charge of zero.
- Neutrality ensures that compounds like ammonia are stable under normal conditions.