Chapter 17: Problem 52
The \(K_{\text {sp }}\) values for \(\mathrm{MnCO}_{3}\) and \(\mathrm{Mn}(\mathrm{OH})_{2}\) are \(1.8 \times 10^{-11}\) and \(4.6 \times 10^{-14}\), respectively. In saturated solutions of \(\mathrm{MnCO}_{3}\) and \(\mathrm{Mn}(\mathrm{OH})_{2}\), which has the higher manganese(II) ion concentration?
Short Answer
Expert verified
The manganese(II) ion concentration is higher in the saturated solution of \( \text{Mn(OH)}_2 \).
Step by step solution
01
Understanding the Problem
We need to compare the manganese(II) ion concentration in saturated solutions of two compounds: \( \text{MnCO}_3 \) and \( \text{Mn(OH)}_2 \). The solubility products \( K_{sp} \) will help us calculate these concentrations.
02
Writing Solubility Product Expressions
For \( \text{MnCO}_3 \), dissociation in water can be represented as \( \text{MnCO}_3 (s) \rightleftharpoons \text{Mn}^{2+} (aq) + \text{CO}_3^{2-} (aq) \), so the \( K_{sp} \) expression is \( K_{sp} = [\text{Mn}^{2+}][\text{CO}_3^{2-}]. \) For \( \text{Mn(OH)}_2 \), dissociation is \( \text{Mn(OH)}_2 (s) \rightleftharpoons \text{Mn}^{2+} (aq) + 2\text{OH}^- (aq) \), thus \( K_{sp} = [\text{Mn}^{2+}][\text{OH}^-]^2. \)
03
Solving for Manganese(II) Ion Concentration in \( \text{MnCO}_3 \)
Let \( s \) be the solubility of \( \text{MnCO}_3 \) in mol/L, leading to \([\text{Mn}^{2+}] = s\) and \([\text{CO}_3^{2-}] = s\). Plugging into \( K_{sp} \), \( 1.8 \times 10^{-11} = s^2 \). Solving for \( s \), \( s = \sqrt{1.8 \times 10^{-11}} \approx 4.24 \times 10^{-6} \ M \).
04
Solving for Manganese(II) Ion Concentration in \( \text{Mn(OH)}_2 \)
Let \( s \) be the solubility of \( \text{Mn(OH)}_2 \) in mol/L. Then, \([\text{Mn}^{2+}] = s\), and \([\text{OH}^-] = 2s\). Thus, \( K_{sp} = s(2s)^2 = 4s^3 \). Solving \( 4s^3 = 4.6 \times 10^{-14} \), we find \( s = \sqrt[3]{\frac{4.6 \times 10^{-14}}{4}} \approx 2.16 \times 10^{-5} \ M \).
05
Comparison of Manganese(II) Ion Concentrations
The concentration of \( \text{Mn}^{2+} \) in \( \text{MnCO}_3 \) is \( 4.24 \times 10^{-6} \ M \), while in \( \text{Mn(OH)}_2 \), it is \( 2.16 \times 10^{-5} \ M \). Thus, the \( \text{Mn(OH)}_2 \) solution has a higher \( \text{Mn}^{2+} \) concentration.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
MnCO3
Manganese(II) carbonate, represented as \( \text{MnCO}_3 \), is a compound that slightly dissolves in water, leading to a saturated solution containing manganese(II) ions and carbonate ions. The dissolution process can be represented by the equation:
\[ \text{MnCO}_3 (s) \rightleftharpoons \text{Mn}^{2+} (aq) + \text{CO}_3^{2-} (aq) \]
The solubility product constant \( K_{sp} \) for \( \text{MnCO}_3 \) is given as \( 1.8 \times 10^{-11} \). This constant provides a mathematical expression of the saturated solution's equilibrium state:- \( K_{sp} = [\text{Mn}^{2+}][\text{CO}_3^{2-}] \)
In simpler terms, this means that the concentration of \( \text{Mn}^{2+} \) ions is equal to the concentration of \( \text{CO}_3^{2-} \) ions, both denoted by \( s \). To find the concentration of manganese(II) ions, we calculate \( s \) by solving the expression:
\[ s = \sqrt{1.8 \times 10^{-11}} \approx 4.24 \times 10^{-6} \, \text{M} \]
This shows that in a saturated \( \text{MnCO}_3 \) solution, the concentration of \( \text{Mn}^{2+} \) ions is very low.
\[ \text{MnCO}_3 (s) \rightleftharpoons \text{Mn}^{2+} (aq) + \text{CO}_3^{2-} (aq) \]
The solubility product constant \( K_{sp} \) for \( \text{MnCO}_3 \) is given as \( 1.8 \times 10^{-11} \). This constant provides a mathematical expression of the saturated solution's equilibrium state:- \( K_{sp} = [\text{Mn}^{2+}][\text{CO}_3^{2-}] \)
In simpler terms, this means that the concentration of \( \text{Mn}^{2+} \) ions is equal to the concentration of \( \text{CO}_3^{2-} \) ions, both denoted by \( s \). To find the concentration of manganese(II) ions, we calculate \( s \) by solving the expression:
\[ s = \sqrt{1.8 \times 10^{-11}} \approx 4.24 \times 10^{-6} \, \text{M} \]
This shows that in a saturated \( \text{MnCO}_3 \) solution, the concentration of \( \text{Mn}^{2+} \) ions is very low.
Mn(OH)2
Manganese(II) hydroxide, or \( \text{Mn(OH)}_2 \), also dissolves slightly in water. The dissociation process produces manganese ions and hydroxide ions as described by the chemical equation:
\[ \text{Mn(OH)}_2 (s) \rightleftharpoons \text{Mn}^{2+} (aq) + 2\text{OH}^- (aq) \]
The solubility product constant \( K_{sp} \) for \( \text{Mn(OH)}_2 \) is \( 4.6 \times 10^{-14} \), providing an equilibrium expression for its saturated solution:- \( K_{sp} = [\text{Mn}^{2+}][\text{OH}^-]^2 \)
In this case, if \( s \) is the solubility of \( \text{Mn(OH)}_2 \), the concentration of \( \text{Mn}^{2+} \) can be found by considering the equation as \( 4s^3 \). Solving this gives:
\[ s = \sqrt[3]{\frac{4.6 \times 10^{-14}}{4}} \approx 2.16 \times 10^{-5} \, \text{M} \]
The result indicates that the manganese(II) ion concentration in a saturated \( \text{Mn(OH)}_2 \) solution is higher than that of \( \text{MnCO}_3 \). This is due to the nature of the ions present and the different \( K_{sp} \) values.
\[ \text{Mn(OH)}_2 (s) \rightleftharpoons \text{Mn}^{2+} (aq) + 2\text{OH}^- (aq) \]
The solubility product constant \( K_{sp} \) for \( \text{Mn(OH)}_2 \) is \( 4.6 \times 10^{-14} \), providing an equilibrium expression for its saturated solution:- \( K_{sp} = [\text{Mn}^{2+}][\text{OH}^-]^2 \)
In this case, if \( s \) is the solubility of \( \text{Mn(OH)}_2 \), the concentration of \( \text{Mn}^{2+} \) can be found by considering the equation as \( 4s^3 \). Solving this gives:
\[ s = \sqrt[3]{\frac{4.6 \times 10^{-14}}{4}} \approx 2.16 \times 10^{-5} \, \text{M} \]
The result indicates that the manganese(II) ion concentration in a saturated \( \text{Mn(OH)}_2 \) solution is higher than that of \( \text{MnCO}_3 \). This is due to the nature of the ions present and the different \( K_{sp} \) values.
manganese(II) ion concentration
Manganese(II) ion concentration in a solution is crucial when dealing with saturations of manganese-based compounds like \( \text{MnCO}_3 \) and \( \text{Mn(OH)}_2 \). Solubility product constants \( K_{sp} \) are vital tools used to calculate these concentrations efficiently.
Each compound, when dissolved, reaches a state of dynamic equilibrium, where the rate of dissolution equals the rate of precipitation. This state lets us define the manganese(II) ion concentration using the \( K_{sp} \) values, which are unique for each compound.
For \( \text{MnCO}_3 \), \( K_{sp} = 1.8 \times 10^{-11} \), giving a manganese ion concentration of \( 4.24 \times 10^{-6} \, \text{M} \). On the other hand, \( \text{Mn(OH)}_2 \) with a \( K_{sp} = 4.6 \times 10^{-14} \), results in a concentration of \( 2.16 \times 10^{-5} \, \text{M} \).
This shows that \( \text{Mn(OH)}_2 \) not only dissolves to a greater extent but also results in a higher concentration of manganese(II) ions in its saturated solution.
Each compound, when dissolved, reaches a state of dynamic equilibrium, where the rate of dissolution equals the rate of precipitation. This state lets us define the manganese(II) ion concentration using the \( K_{sp} \) values, which are unique for each compound.
For \( \text{MnCO}_3 \), \( K_{sp} = 1.8 \times 10^{-11} \), giving a manganese ion concentration of \( 4.24 \times 10^{-6} \, \text{M} \). On the other hand, \( \text{Mn(OH)}_2 \) with a \( K_{sp} = 4.6 \times 10^{-14} \), results in a concentration of \( 2.16 \times 10^{-5} \, \text{M} \).
This shows that \( \text{Mn(OH)}_2 \) not only dissolves to a greater extent but also results in a higher concentration of manganese(II) ions in its saturated solution.