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Arrange the following sets of elements in order of increasing atomic size. a. \(\mathrm{Sn}, \mathrm{Xe}, \mathrm{Rb}, \mathrm{Sr}\) b. \(\mathrm{Rn}, \mathrm{He}, \mathrm{Xe}, \mathrm{Kr}\) c. \(\mathrm{Pb}, \mathrm{Ba}, \mathrm{Cs}, \mathrm{At}\)

Short Answer

Expert verified
The ordered sets of elements in increasing atomic size are: a. \(\mathrm{Rb}, \mathrm{Sr}, \mathrm{Sn}, \mathrm{Xe}\) b. \(\mathrm{He}, \mathrm{Kr}, \mathrm{Xe}, \mathrm{Rn}\) c. \(\mathrm{At}, \mathrm{Pb}, \mathrm{Ba}, \mathrm{Cs}\)

Step by step solution

01

Identify the Elements in Each Set

For each set of elements, we need to identify their positions in the periodic table. Let's do this for each set: a. Sn (Tin), Xe (Xenon), Rb (Rubidium), Sr (Strontium) b. Rn (Radon), He (Helium), Xe (Xenon) and Kr (Krypton) c. Pb (Lead), Ba (Barium), Cs (Cesium), At (Astatine) ##Step 2: Determine the periodic trends for each set of elements##
02

Apply the Periodic Trends

Using the periodic trends, we can arrange the elements in each set in order of increasing atomic size. Remember that size increases down a group and decreases across a period. a. Sn is in Group 14, Period 5; Xe is in Group 18, Period 5; Rb is in Group 1, Period 5; Sr is in Group 2, Period 5 b. Rn is in Group 18, Period 6; He is in Group 18, Period 1; Xe is in Group 18, Period 5; Kr is in Group 18, Period 4 c. Pb is in Group 14, Period 6; Ba is in Group 2, Period 6; Cs is in Group 1, Period 6; At is in Group 17, Period 6 ##Step 3: Arrange the elements in the order of increasing atomic size##
03

Arrange the Elements

Based on the periodic trends and the positions of the elements in the periodic table, we can now arrange the elements in each set in order of increasing atomic size. a. Rb, Sr, Sn, Xe b. He, Kr, Xe, Rn c. At, Pb, Ba, Cs So the final ordered sets are: a. \(\mathrm{Rb}, \mathrm{Sr}, \mathrm{Sn}, \mathrm{Xe}\) b. \(\mathrm{He}, \mathrm{Kr}, \mathrm{Xe}, \mathrm{Rn}\) c. \(\mathrm{At}, \mathrm{Pb}, \mathrm{Ba}, \mathrm{Cs}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Atomic Size
Atomic size, also known as atomic radius, is a fundamental property of atoms that varies in a predictable way across the periodic table. The atomic size of an element is primarily determined by two key factors:
  • The number of electron shells, or energy levels, which increases as you move down a group in the periodic table.
  • The effective nuclear charge, which is the net positive charge experienced by valence electrons, decreases across a period as more protons are added to the nucleus.
Moving down a group, the atomic size increases because each subsequent element in a group has an additional energy level. These extra layers of electrons are further from the nucleus and lessen the overall pull of the nucleus on the outer electrons, resulting in a larger size.
Conversely, as you move from left to right across a period, the effective nuclear charge increases, pulling electrons closer to the nucleus and thus decreasing the size of the atom.
Understanding these trends helps predict how atomic size will change both down a group and across a period.
Periodic Table
The periodic table is a systematic arrangement of the chemical elements, ordered by their atomic numbers, electron configurations, and recurring chemical properties. It provides a valuable framework that illustrates periodic trends of the elements, including atomic size, as well as electronegativity and ionization energy. The table is structured into:
  • Periods: Horizontal rows that signify elements with the same number of electron shells.
  • Groups: Vertical columns where elements share similar chemical behaviors due to having the same number of electrons in their outermost shell.
The position of an element in the table reveals a wealth of information about its electronic configuration and the general trends it will exhibit. For example, elements on the left side of the periodic table typically have larger atomic sizes because they have fewer protons in their nuclei compared to those on the right, leading to a weaker attraction to the electrons.
Element Groups
Element groups are columns in the periodic table where elements have similar valence electron configurations and exhibit similar chemical properties. For instance, Group 1 contains alkali metals like lithium and sodium, while Group 18 consists of noble gases such as helium and neon. Each group has characteristics that define it:
  • Group 1 (Alkali Metals): Highly reactive with one valence electron. They tend to lose this electron easily, leading to a larger atomic size.
  • Group 2 (Alkaline Earth Metals): Slightly less reactive than Group 1 and possess two valence electrons.
  • Group 17 (Halogens): Reactive non-metals found in compounds rather than free elements.
  • Group 18 (Noble Gases): Known for their inertness due to having full valence electron shells, making them non-reactive.
By understanding which group an element belongs to, it's easier to predict its reactivity and the size of its atoms. For instance, elements in Group 1 not only react vigorously due to their large atomic size, but they also increase in size further down the group.

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Most popular questions from this chapter

In the text (Section 11.6 ) it was mentioned that current theories of atomic structure suggest that all matter and all energy demonstrate both particle- like and wave-like properties under the appropriate conditions, although the wave-like nature of matter becomes apparent only in very small and very fast- moving particles. The relationship between wavelength \((\lambda)\) observed for a particle and the mass and velocity of that particle is called the de Broglie relationship. It is $$ \lambda=h / m v $$ in which \(h\) is Planck's constant \(\left(6.63 \times 10^{-34} \mathrm{~J} \cdot \mathrm{s}\right), * m\) represents the mass of the particle in kilograms, and \(v\) represents the velocity of the particle in meters per second. Calculate the "de Broglie wavelength" for each of the following, and use your numerical answers to explain why macroscopic (large) objects are not ordinarily discussed in terms of their "wave-like" properties. a. an electron moving at 0.90 times the speed of light b. a \(150-\mathrm{g}\) ball moving at a speed of \(10 . \mathrm{m} / \mathrm{s}\) c. a 75 -kg person walking at a speed of \(2.0 \mathrm{~km} / \mathrm{h}\)

Based on the elements" locations on the periodic table, how many \(4 d\) electrons would be predicted for each of the following elements? a. ruthenium, \(Z=44\) b. palladium, \(Z=46\) c. tin, \(Z=50\) d. The \(f\) orbitals begin at the fourth principal energy level and can hold a maximum of 14 electrons for a given energy level. e. For each orbital, an electron orbits the nucleus around the outer edge according to the shape of that orbital. d. iron, \(Z=26\)

Without referring to your textbook or a periodic table, write the full electron configuration, the orbital box diagram, and the noble gas shorthand configuration for the elements with the following atomic numbers. a. \(Z=21\) b. \(Z=15\) c. \(Z=36\) d. \(Z=38\) e. \(Z=30\)

The portion of the electromagnetic spectrum between wavelengths of approximately 400 and 700 nanometers is called the

An unknown element is a nonmetal and has a valence-electron configuration of \(\mathrm{n} s^{2} \mathrm{n} p^{4}\) a. How many valence electrons does this element have? b. Possible identities for this element include which of the following? $$ \mathrm{Cl}, \mathrm{S}, \mathrm{Pb}, \mathrm{Se}, \mathrm{Cr} $$

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