/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 Based on the elements" locations... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Based on the elements" locations on the periodic table, how many \(4 d\) electrons would be predicted for each of the following elements? a. ruthenium, \(Z=44\) b. palladium, \(Z=46\) c. tin, \(Z=50\) d. The \(f\) orbitals begin at the fourth principal energy level and can hold a maximum of 14 electrons for a given energy level. e. For each orbital, an electron orbits the nucleus around the outer edge according to the shape of that orbital. d. iron, \(Z=26\)

Short Answer

Expert verified
In summary, the number of 4d electrons for each of the given elements are: a. Ruthenium (Ru): 7 electrons b. Palladium (Pd): 10 electrons c. Tin (Sn): 10 electrons d. Iron (Fe): 0 electrons

Step by step solution

01

Electron Configuration of Ruthenium, Z=44

Find the electron configuration of ruthenium (Ru) using the periodic table. The electron configuration is \([\text{Kr}] 4d^7 5s^1\). The element has 7 electrons in the 4d orbitals.
02

Electron Configuration of Palladium, Z=46

Find the electron configuration of palladium (Pd) using the periodic table. The electron configuration is \([\text{Kr}] 4d^{10}\). The element has 10 electrons in the 4d orbitals.
03

Electron Configuration of Tin, Z=50

Find the electron configuration of tin (Sn) using the periodic table. The electron configuration is \([\text{Kr}] 4d^{10} 5s^2 5p^2\). The element has 10 electrons in the 4d orbitals.
04

Electron Configuration of Iron, Z=26

Find the electron configuration of iron (Fe) using the periodic table. The electron configuration is \([\text{Ar}] 3d^6 4s^2\). The element has no electrons in the 4d orbitals since it's in the 3d orbitals. In summary, the number of 4d electrons for each of the given elements are: a. Ruthenium (Ru): 7 electrons b. Palladium (Pd): 10 electrons c. Tin (Sn): 10 electrons d. Iron (Fe): 0 electrons

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Periodic Table
The periodic table is an organized way of displaying elements, allowing us to predict various properties and behaviors of elements based on their positions. Each element is unique due to its atomic number, which represents the number of protons in its nucleus. The periodic table is arranged in rows called periods and columns called groups. Elements in the same group share similar chemical properties.

Understanding the periodic table is essential for determining the electron configuration of elements. As you move across a period from left to right, electrons are added to the same principal energy level. This systematic arrangement allows scientists to predict electron configurations, such as those seen in ruthenium, palladium, tin, and iron. These configurations help us in understanding the chemical behavior of each element.
Transition Metals
Transition metals are elements located in groups 3 through 12 of the periodic table. They are characterized by their ability to form stable cations with multiple oxidation states and typically have partially filled d orbitals. These metals, including ruthenium and palladium, display unique properties such as high melting points, and good electrical conductivity.

A significant feature of transition metals is their electron configurations. Electrons are added to the d subshell as we move horizontally across a period. For example, ruthenium has a 4d electron count, indicative of its position among transition metals. This intricate electron filling accounts for the complex chemistry associated with these elements. Understanding how electrons fill these d orbitals in transition metals is crucial for grasping their chemistry.
Atomic Orbitals
Atomic orbitals define regions around the nucleus where electrons are likely to be found. Each orbital type (s, p, d, f) has a distinct shape and orientation. The way electrons fill these orbitals is described by the Aufbau principle, Pauli exclusion principle, and Hund's rule.

* **s orbitals**: Spherical with the nucleus at the center - each energy level has one s orbital. * **p orbitals**: Dumbbell-shaped and oriented along three axes (x, y, z) - from the second energy level on, each energy level has three p orbitals. * **d orbitals**: Complex shapes and found starting from the third energy level. The 4d and 3d orbitals differentiate elements like palladium and iron. * **f orbitals**: More complex shapes and start from the fourth energy level, although not relevant to the elements in this example.
The varied shapes and orientations dictate how electrons are arranged around the nucleus, influencing the chemical properties and chemical bonding behaviour of elements.
Principal Energy Levels
Principal energy levels are fundamental concepts in atomic theory. They describe the major shells of an atom where electrons reside. These shells are denoted by an integer quantum number, n (n = 1, 2, 3, etc.), indicating the relative distance and energy of electrons from the nucleus.

Each energy level can hold a certain number of electrons:
  • 1st level (n=1): Holds up to 2 electrons
  • 2nd level (n=2): Holds up to 8 electrons
  • 3rd level (n=3): Holds up to 18 electrons
  • 4th level (n=4): Holds up to 32 electrons
As we move to higher principal energy levels, more complex orbitals (like the d and f orbitals) become available. Understanding these levels helps in predicting how electrons are organized in an atom, as demonstrated in the electron configurations of the elements discussed.
For instance, ruthenium and palladium have electrons filling the 4d orbitals, showing their position within the principal energy levels. This progression of electron filling is crucial for interpreting the chemical nature of various elements.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Compare the ionization energies of each pair of atoms. State the atom with the larger ionization energy for each pair.

Arrange the following sets of elements in order of increasing atomic size. a. \(\mathrm{Sn}, \mathrm{Xe}, \mathrm{Rb}, \mathrm{Sr}\) b. \(\mathrm{Rn}, \mathrm{He}, \mathrm{Xe}, \mathrm{Kr}\) c. \(\mathrm{Pb}, \mathrm{Ba}, \mathrm{Cs}, \mathrm{At}\)

In the text (Section 11.6 ) it was mentioned that current theories of atomic structure suggest that all matter and all energy demonstrate both particle- like and wave-like properties under the appropriate conditions, although the wave-like nature of matter becomes apparent only in very small and very fast- moving particles. The relationship between wavelength \((\lambda)\) observed for a particle and the mass and velocity of that particle is called the de Broglie relationship. It is $$ \lambda=h / m v $$ in which \(h\) is Planck's constant \(\left(6.63 \times 10^{-34} \mathrm{~J} \cdot \mathrm{s}\right), * m\) represents the mass of the particle in kilograms, and \(v\) represents the velocity of the particle in meters per second. Calculate the "de Broglie wavelength" for each of the following, and use your numerical answers to explain why macroscopic (large) objects are not ordinarily discussed in terms of their "wave-like" properties. a. an electron moving at 0.90 times the speed of light b. a \(150-\mathrm{g}\) ball moving at a speed of \(10 . \mathrm{m} / \mathrm{s}\) c. a 75 -kg person walking at a speed of \(2.0 \mathrm{~km} / \mathrm{h}\)

Which orbital is the first to be filled in any atom? Why?

What major assumption (that was analogous to what had already been demonstrated for electromagnetic radiation) did de Broglie and Schrödinger make about the motion of tiny particles?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.