/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 78 For the following pairs of ions,... [FREE SOLUTION] | 91影视

91影视

For the following pairs of ions, use the principle of electrical neutrality to predict the formula of the binary compound that the ions are most likely to form. a. \(\mathrm{Na}^{+}\) and \(\mathrm{S}^{2-}\) b. \(\mathrm{K}^{+}\) and \(\mathrm{Cl}^{-}\) c. \(B a^{2+}\) and \(O^{2-}\) d. \(\mathrm{Mg}^{2+}\) and \(\mathrm{Se}^{2-}\) e. \(\mathrm{Cu}^{2+}\) and \(\mathrm{Br}^{-}\) f. \(A l^{3+}\) and \(I^{-}\) g. \(A 1^{3+}\) and \(O^{2-}\) h. \(\mathrm{Ca}^{2+}\) and \(\mathrm{N}^{3-}\)

Short Answer

Expert verified
a. \(Na_2S\) b. \(KCl\) c. \(BaO\) d. \(MgSe\) e. \(CuBr_2\) f. \(AlI_3\) g. \(Al_2O_3\) h. \(Ca_3N_2\)

Step by step solution

01

a. Na鈦 and S虏鈦

To achieve electrical neutrality, one Na鈦 ion will combine with one S虏鈦 ion. This will balance the charges, since the positive and negative charges cancel out each other. So, the formula for this compound is \(Na_2S\).
02

b. K鈦 and Cl鈦

Each K鈦 ion carries a positive charge, and each Cl鈦 ion carries a negative charge. Electrical neutrality is achieved when one K鈦 ion combines with one Cl鈦 ion. The resulting compound is \(KCl\).
03

c. Ba虏鈦 and O虏鈦

The ions given are positively charged with a 2+ charge and negatively charged with a 2- charge. The ratio of ions needed to balance each other is 1:1. The resulting compound is \(BaO\).
04

d. Mg虏鈦 and Se虏鈦

The ions have charges of +2 and -2, respectively. The principle of electrical neutrality is achieved when one ion of each type joins together. The formula for this compound is \(MgSe\).
05

e. Cu虏鈦 and Br鈦

Cu虏鈦 has a charge of +2, while Br鈦 has a charge of -1. To achieve electrical neutrality, two Br鈦 ions will combine with one Cu虏鈦 ion. The formula for this compound is \(CuBr_2\).
06

f. Al鲁鈦 and I鈦

Al鲁鈦 has a charge of +3, and I鈦 has a charge of -1. To balance the charges, three I鈦 ions will combine with one Al鲁鈦 ion. The formula for this compound is \(AlI_3\).
07

g. Al鲁鈦 and O虏鈦

Al鲁鈦 carries a +3 charge, and O虏鈦 carries a -2 charge. To achieve electrical neutrality, two Al鲁鈦 ions will combine with three O虏鈦 ions. This makes the formula of the compound \(Al_2O_3\).
08

h. Ca虏鈦 and N鲁鈦

Ca虏鈦 has a charge of +2, and N鲁鈦 has a charge of -3. To achieve electrical neutrality, three Ca虏鈦 ions will combine with two N鲁鈦 ions. The formula for this compound is \(Ca_3N_2\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binary Compounds
Binary compounds are made from two different elements, typically consisting of a metal and a non-metal. These compounds form because elements tend to gain, lose, or share electrons in order to achieve a stable electronic configuration, often following the octet rule. This behavior results in the creation of ions that come together to form binary compounds.

For instance, in the pairing of \(\mathrm{Na}^+\) and \(\mathrm{S}^{2-}\), electrical neutrality is reached by combining two \(\mathrm{Na}^+\) ions with one \(\mathrm{S}^{2-}\) ion. This results in the binary compound \(\mathrm{Na}_2\mathrm{S}\). Each binary compound has a distinct and definite composition, leading to predictable chemical properties.
Ion Charges
Ion charges are the electrical charge that atoms carry when they gain or lose electrons. These charges are crucial for understanding how ionic compounds form, as they determine how ions will combine in binary compounds. Metals tend to lose electrons, forming positive ions (cations), while non-metals gain electrons, forming negative ions (anions).

For example:
  • \(\mathrm{Na}^+\) has a single positive charge.
  • \(\mathrm{S}^{2-}\) carries a -2 charge due to the gain of two electrons.
Balancing these charges is essential for forming neutral compounds, ensuring that the total positive and negative charges cancel each other out.
Molecular Formula
The molecular formula of a compound represents the specific number and types of atoms in a molecule. For ionic compounds like binary compounds, the formula reflects the smallest whole number ratio of ions that balance each other out to achieve electrical neutrality.

For instance, the compound formed between \(\mathrm{K}^+\) and \(\mathrm{Cl}^-\) is \(\mathrm{KCl}\). Here, the charges are already balanced with one positive charge from \(\mathrm{K}^+\) and one negative charge from \(\mathrm{Cl}^-\). Thus, the molecular formula simply combines one of each, reflecting this 1:1 ratio.
Ionic Bonding
Ionic bonding is the force that holds ions together in an ionic compound. This type of bond forms through the electrostatic attraction between oppositely charged ions. Ionic bonds are typically formed between metals and non-metals, where electrons are transferred from the metal to the non-metal.

In the case of \(\mathrm{Al}^{3+}\) and \(\mathrm{I}^-\), the \(\mathrm{Al}^{3+}\) ion donates electrons to three \(\mathrm{I}^-\) ions, forming \(\mathrm{AlI}_3\). The transfer of electrons results in a stable force of attraction, leading to the crystalline structure typical of ionic compounds. This strong bond explains the high melting and boiling points of these compounds.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.