Chapter 15: Problem 69
Buffered solutions are mixtures of a weak acid and its conjugate base. Explain why a mixture of a strong acid and its conjugate base (such as \(\mathrm{HCl}\) and \(\mathrm{Cl}^{-}\) ) is not buffered.
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Chapter 15: Problem 69
Buffered solutions are mixtures of a weak acid and its conjugate base. Explain why a mixture of a strong acid and its conjugate base (such as \(\mathrm{HCl}\) and \(\mathrm{Cl}^{-}\) ) is not buffered.
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Which of the following bases have relatively strong conjugate acids? a. \(\mathrm{F}^{-}\) b. \(\mathrm{Cl}^{-}\) c. \(\mathrm{HSO}_{4}^{-}\) d. \(\mathrm{NO}_{3}^{-}\)
An acid such as \(\mathrm{HCl}\) that strongly conducts an electric current when dissolved in water is said to be \(a(n)\) _____ acid.
For each pair of concentrations, tell which represents the more basic solution. a. \(\left[\mathrm{H}^{+}\right]=1.59 \times 10^{-7} \mathrm{M}\) or \(\left[\mathrm{H}^{+}\right]=1.04 \times 10^{-8} \mathrm{M}\) b. \(\left[\mathrm{H}^{+}\right]=5.69 \times 10^{-8} \mathrm{M}\) or \(\left[\mathrm{OH}^{-}\right]=4.49 \times 10^{-6} \mathrm{M}\) c. \(\left[\mathrm{H}^{+}\right]=5.99 \times 10^{-8} \mathrm{M}\) or \(\left[\mathrm{OH}^{-}\right]=6.01 \times 10^{-7} \mathrm{M}\)
For each pair of concentrations, tell which represents the more acidic solution. a. \(\left[\mathrm{H}^{+}\right]=1.2 \times 10^{-3} \mathrm{M}\) or \(\left[\mathrm{H}^{+}\right]=4.5 \times 10^{-4} \mathrm{M}\) b. \(\left[\mathrm{H}^{+}\right]=2.6 \times 10^{-6} \mathrm{M}\) or \(\left[\mathrm{H}^{+}\right]=4.3 \times 10^{-8} \mathrm{M}\) c. \(\left[\mathrm{H}^{+}\right]=0.000010 \mathrm{M}\) or \(\left[\mathrm{H}^{+}\right]=0.0000010 \mathrm{M}\)
Calculate the \(\left[\mathrm{OH}^{-}\right]\) in each of the following solutions, and indicate whether the solution is acidic or basic. a. \(\left[\mathrm{H}^{+}\right]=1.34 \times 10^{-2} \mathrm{M}\) b. \(\left[\mathrm{H}^{+}\right]=6.99 \times 10^{-7} \mathrm{M}\) c. \(\left[\mathrm{H}^{+}\right]=4.01 \times 10^{-9} \mathrm{M}\) d. \(\left[\mathrm{H}^{+}\right]=4.02 \times 10^{-13} \mathrm{M}\)
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