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When a solution of hydrochloric acid, HCl, is added to a solution of sodium sulfite, \(\mathrm{Na}_{2} \mathrm{SO}_{3},\) sulfur dioxide gas is released from the solution. Write a net ionic equation for this reaction. An aqueous solution of HC contains \(\mathrm{H}^{+}\) and \(\mathrm{Cl}^{-}\) ions, and \(\mathrm{Na}_{2} \mathrm{SO}_{3}\) exists as dissociated ions in aqueous solution.

Short Answer

Expert verified
The net ionic equation is \(2\mathrm{H}^+ (aq) + \mathrm{SO}_3^{2-} (aq) \rightarrow \mathrm{SO}_2 (g) + \mathrm{H}_2\mathrm{O} (l)\).

Step by step solution

01

Understand the Reactants and Products

Identify the reactants as hydrochloric acid (HCl) and sodium sulfite (\(\mathrm{Na}_2\mathrm{SO}_3\)). Next, recognize that hydrochloric acid dissociates in water to form \(\mathrm{H}^+\) and \(\mathrm{Cl}^-\) ions, while \(\mathrm{Na}_2\mathrm{SO}_3\) dissociates into \(2\ \mathrm{Na}^+\) and \(\mathrm{SO}_3^{2-}\) ions. The products are sodium chloride (\(\mathrm{NaCl}\)) and sulfur dioxide (\(\mathrm{SO}_2\)) gas.
02

Write Balanced Molecular Equation

Combine the reactants to form the products: \(\mathrm{HCl} (aq) + \mathrm{Na}_2\mathrm{SO}_3 (aq) \rightarrow \mathrm{NaCl} (aq) + \mathrm{SO}_2 (g) + \mathrm{H}_2\mathrm{O} (l)\). Ensure the equation is balanced, adjusting coefficients as needed: \(2\mathrm{HCl} + \mathrm{Na}_2\mathrm{SO}_3 \rightarrow 2\mathrm{NaCl} + \mathrm{SO}_2 + \mathrm{H}_2\mathrm{O}\).
03

Convert Molecular Equation to Complete Ionic Equation

Write the ionic forms of all aqueous substances: \(2\mathrm{H}^+ (aq) + 2\mathrm{Cl}^- (aq) + 2\mathrm{Na}^+ (aq) + \mathrm{SO}_3^{2-} (aq) \rightarrow 2\mathrm{Na}^+ (aq) + 2\mathrm{Cl}^- (aq) + \mathrm{SO}_2 (g) + \mathrm{H}_2\mathrm{O} (l)\).
04

Identify and Remove Spectator Ions

Look for ions that appear unchanged on both sides of the equation. These are spectator ions. Here, \(2\mathrm{Na}^+\) and \(2\mathrm{Cl}^-\) are spectator ions as they appear in the same form on both sides of the equation.
05

Write the Net Ionic Equation

After removing the spectator ions from the complete ionic equation, you're left with the net ionic equation: \(2\mathrm{H}^+ (aq) + \mathrm{SO}_3^{2-} (aq) \rightarrow \mathrm{SO}_2 (g) + \mathrm{H}_2\mathrm{O} (l)\). This represents only the ions involved in the chemical change.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spectator Ions
In chemical reactions, particularly those involving ions in aqueous solutions, not all ions participate in the actual chemical change. These non-participating ions are called spectator ions. They are present in the solution but do not change their form during the reaction. Instead, they "watch" the relevant reactants transform into products.
For example, consider the reaction between hydrochloric acid and sodium sulfite. Here, spectator ions are present that do not affect the formation of sulfur dioxide and water.
  • In our example, \(2\mathrm{Na}^+\) and \(2\mathrm{Cl}^-\) ions are spectator ions.
  • They appear unchanged in the ionic equation.
  • Identifying these ions helps simplify the equation to highlight the actual reaction.
By removing these spectator ions, we can write the net ionic equation, which shows only the substances that participate in the chemical change. This simplification helps in understanding the core components of a reaction.
Acid-Base Reaction
Acid-base reactions are a fundamental type of chemical reaction that involves the transfer of protons (\(\mathrm{H}^+\)) from an acid to a base. This is a common process in many chemical reactions where acids and bases interact to form products.
In the exercise we see hydrochloric acid (HCl), a strong acid, reacting with sodium sulfite (\(\mathrm{Na}_2\mathrm{SO}_3\)), the base in this scenario. This type of reaction often produces water and another product—in this case, sulfur dioxide gas (\(\mathrm{SO}_2\)).
Understanding how to balance these reactions is crucial. Reactants must be equal on both sides of the equation to satisfy the law of conservation of mass.
  • The balanced molecular equation becomes \(2\mathrm{HCl} + \mathrm{Na}_2\mathrm{SO}_3 \rightarrow 2\mathrm{NaCl} + \mathrm{SO}_2 + \mathrm{H}_2\mathrm{O}\).
  • This highlights the proton transfer that typifies an acid-base reaction.
Through understanding acid-base reactions, students can better comprehend how various compounds interact and change.
Chemical Equations
Chemical equations are a shorthand way of depicting chemical reactions. They represent how substances interact and what products are formed.
The balanced chemical equation in a reaction provides important information about the quantity and types of atoms participating.
  • In a balanced equation, the number of atoms of every element is the same on both sides of the equation.
  • Equations may be expressed in different forms like molecular, complete ionic, and net ionic equations.
In our exercise scenario, we start by writing a molecular equation, detailing reactants and products in simple terms. Next, by expressing aqueous compounds as their ions, we create the complete ionic equation.
Finally, by removing spectator ions, we derive the net ionic equation to emphasize essential chemical changes. This progression helps students visually track each component in the reaction and see everything from a big-picture perspective down to the specific changes.

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Most popular questions from this chapter

Reaction of pentane, \(\mathrm{C}_{5} \mathrm{H}_{12},\) with oxygen, \(\mathrm{O}_{2},\) gives carbon dioxide and water. (a) Write a balanced equation for this reaction. (b) In this reaction, what is oxidized and what is reduced? (c) What is the oxidizing agent, and what is the reducing agent?

The oxidation of glucose, \(C_{6} H_{12} O_{6},\) to carbon dioxide and water is exothermic. The heat liberated is the same whether glucose is metabolized in the body or burned in air. \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}+6 \mathrm{O}_{2} \longrightarrow 6 \mathrm{CO}_{2}+6 \mathrm{H}_{2} \mathrm{O}+670 \mathrm{kcal}\) Calculate the heat liberated when \(15.0 \mathrm{g}\) of glucose is metabolized to carbon dioxide and water in the body.

Calculate the number of: (a) nitrogen atoms in \(25.0 \mathrm{g}\) of \(\mathrm{TNT}, \mathrm{C}_{7} \mathrm{H}_{5} \mathrm{N}_{3} \mathrm{O}_{6}\) (b) carbon atoms in \(40.0 \mathrm{g}\) of ethanol, \(\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\) (c) oxygen atoms in \(500 .\) mg of aspirin, \(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}\) (d) sodium atoms in \(2.40 \mathrm{g}\) of sodium dihydrogen phosphate, \(\mathrm{NaH}_{2} \mathrm{PO}_{4}\)

In the chemical test for arsenic, the gas arsine, AsH prepared. When arsine is decomposed by heating, arsenic metal deposits as a mirror-like coating on the surface of a glass container and hydrogen gas, \(\mathrm{H}_{2}\), is given off. Write a balanced equation for the decomposition of arsine.

When a solution of sodium hydroxide is added to a solution of ammonium carbonate, \(\mathrm{H}_{2} \mathrm{O}\) is formed and ammonia gas, \(\mathrm{NH}_{3}\), is released when the solution is heated. Write a net ionic equation for this reaction. Both \(\mathrm{NaOH}\) and \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{CO}_{3}\) exist as dissociated ions in aqueous solution.

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