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Calculate the number of: (a) nitrogen atoms in \(25.0 \mathrm{g}\) of \(\mathrm{TNT}, \mathrm{C}_{7} \mathrm{H}_{5} \mathrm{N}_{3} \mathrm{O}_{6}\) (b) carbon atoms in \(40.0 \mathrm{g}\) of ethanol, \(\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\) (c) oxygen atoms in \(500 .\) mg of aspirin, \(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}\) (d) sodium atoms in \(2.40 \mathrm{g}\) of sodium dihydrogen phosphate, \(\mathrm{NaH}_{2} \mathrm{PO}_{4}\)

Short Answer

Expert verified
(a) \(1.99 \times 10^{23}\) N atoms; (b) \(1.04 \times 10^{24}\) C atoms; (c) \(6.70 \times 10^{21}\) O atoms; (d) \(1.20 \times 10^{22}\) Na atoms.

Step by step solution

01

Calculate Molar Mass of TNT

Using the formula for TNT, \( \mathrm{C}_7 \mathrm{H}_5 \mathrm{N}_3 \mathrm{O}_6 \), calculate its molar mass. The atomic masses are approximately: \( \mathrm{C} = 12.01 \), \( \mathrm{H} = 1.01 \), \( \mathrm{N} = 14.01 \), \( \mathrm{O} = 16.00 \). Hence, the molar mass is \( (7 \times 12.01) + (5 \times 1.01) + (3 \times 14.01) + (6 \times 16.00) = 227.13 \) g/mol.
02

Moles of TNT

Calculate the moles of TNT in 25.0 g using the formula: moles = mass / molar mass. Therefore, moles of TNT = \( \frac{25.0}{227.13} \approx 0.110 \) moles.
03

Number of Nitrogen Atoms in TNT

There are 3 nitrogen atoms per molecule of TNT. First calculate the molecules of TNT: moles \( \times \) Avogadro's number (\( 6.022 \times 10^{23} \)). So the number of nitrogen atoms = \( 0.110 \times 6.022 \times 10^{23} \times 3 \approx 1.99 \times 10^{23} \) atoms.
04

Calculate Molar Mass of Ethanol

Using the formula for ethanol, \( \mathrm{C}_2 \mathrm{H}_6 \mathrm{O} \), the molar mass is \( (2 \times 12.01) + (6 \times 1.01) + (1 \times 16.00) = 46.08 \) g/mol.
05

Moles of Ethanol

Calculate the moles of ethanol in 40.0 g: \( \frac{40.0}{46.08} \approx 0.867 \) moles.
06

Number of Carbon Atoms in Ethanol

Each molecule of ethanol contains 2 carbon atoms. Thus, number of carbon atoms = \( 0.867 \times 6.022 \times 10^{23} \times 2 \approx 1.04 \times 10^{24} \) atoms.
07

Calculate Molar Mass of Aspirin

For aspirin \( \mathrm{C}_9 \mathrm{H}_8 \mathrm{O}_4 \), its molar mass is \( (9 \times 12.01) + (8 \times 1.01) + (4 \times 16.00) = 180.17 \) g/mol.
08

Moles of Aspirin

Convert 500 mg of aspirin to grams (0.500 g) and then calculate moles: \( \frac{0.500}{180.17} \approx 0.00278 \) moles.
09

Number of Oxygen Atoms in Aspirin

Aspiring has 4 oxygen atoms per molecule. Number of oxygen atoms = \( 0.00278 \times 6.022 \times 10^{23} \times 4 \approx 6.70 \times 10^{21} \) atoms.
10

Calculate Molar Mass of Sodium Dihydrogen Phosphate

For \( \mathrm{NaH}_2 \mathrm{PO}_4 \), its molar mass is \( 22.99 + (2 \times 1.01) + 30.97 + (4 \times 16.00) = 119.98 \) g/mol.
11

Moles of Sodium Dihydrogen Phosphate

Calculate moles in 2.40 g: \( \frac{2.40}{119.98} \approx 0.0200 \) moles.
12

Number of Sodium Atoms

Each molecule contains 1 sodium atom. Therefore, number of sodium atoms = \( 0.0200 \times 6.022 \times 10^{23} \approx 1.20 \times 10^{22} \) atoms.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass Calculation
The molar mass of a compound is crucial for determining how much of the substance corresponds to one mole. This is calculated by summing the atomic masses from the periodic table for all the atoms present in the compound's chemical formula. For instance, the molar mass of TNT (\( \mathrm{C}_7 \mathrm{H}_5 \mathrm{N}_3 \mathrm{O}_6 \)), involves calculating:
  • Carbon (C): 7 atoms, each with an atomic mass of about 12.01
  • Hydrogen (H): 5 atoms, each 1.01
  • Nitrogen (N): 3 atoms, each 14.01
  • Oxygen (O): 6 atoms, each 16.00
This yields a molar mass of 227.13 g/mol for TNT. Similar calculations apply to find the molar masses of ethanol, aspirin, and sodium dihydrogen phosphate. Using atomic masses such as these helps you find how much mass one mole of each compound has, making it vital for establishing a connection between mass and amount of substance.
Number of Atoms Calculation
Finding the number of atoms in a given mass of a compound involves computing how many moles are present first. This is done by dividing the mass by its molar mass. Once you have the moles, you multiply by Avogadro's number to obtain the number of molecules. For example, if you want to determine the number of nitrogen atoms in 25.0 g of TNT:
  • First, find moles: \( 25.0 \, \mathrm{g} \div 227.13 \, \mathrm{g/mol} \approx 0.110 \) moles.
  • Next, calculate molecules: \( 0.110 \times 6.022 \times 10^{23}\).
  • Then, since each TNT molecule has 3 nitrogen atoms, multiply by 3 to find total nitrogen atoms.
This method applies similarly to other elements in various compounds once you isolate the element of interest from the overall molecule.
Avogadro's Number
Avogadro's number, \(6.022 \times 10^{23}\), represents the number of particles, usually atoms or molecules, in one mole of a substance. It acts as a bridge between the macroscopic scale (what we can measure) and the microscopic scale (individual atoms and molecules). Consider converting a mass of substance to the number of particles: converting 0.100 moles of a substance to atoms/molecules involves multiplying by Avogadro's number. This provides a manageable way to comprehend quantities of particles typically too small to measure individually. Thus, when you have moles, use Avogadro's number to transition from moles to individual atomic or molecular counts, like in the exercise where you needed the number of nitrogen, carbon, oxygen, and sodium atoms in different substances.
Chemical Formula Interpretation
A chemical formula reveals the ratio of atoms in a compound, informing how many atoms of each element are present in a single molecule. Take ethanol, \( \mathrm{C}_2 \mathrm{H}_6 \mathrm{O} \), as an example:
  • C: Two carbon atoms per molecule
  • H: Six hydrogen atoms
  • O: One oxygen atom
The subscripts denote the number of each type of atom. This information is crucial for understanding how a specific mass of compound translates into moles of each type of atom, like the calculation of 2 carbon atoms per molecule in 40.0 g of ethanol. Thoroughly interpreting a chemical formula allows you to accurately perform molar mass calculations and subsequently derive numbers of specific atoms from a given mass of material.

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Most popular questions from this chapter

A solar cell generates \(500 .\) k.J of energy per hour. To keep a refrigerator at \(4^{\circ} \mathrm{C}\), one needs \(250 . \mathrm{kcal} / \mathrm{h}\). Can the solar cell supply sufficient energy per hour to maintain the temperature of the refrigerator?

Solid ammonium carbonate, \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{CO}_{3},\) decomposes at room temperature to form gaseous ammonia, carbon dioxide, and water. Because of the ease of decomposition and the penetrating odor of ammonia, ammonium carbonate can be used as smelling salts. Write a balanced equation for this decomposition.

The active ingredient in an analgesic tablet is \(488 \mathrm{mg}\) of aspirin, \(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{5}\). How many moles of aspirin does the tablet contain?

Answer true or false. (a) Stoichiometry is the study of mass relationships in chemical reactions. (b) To determine mass relationships in a chemical reaction, you first need to know the balanced chemical equation for the reaction. (c) To convert from grams to moles and vice versa, use Avogadro's number as a conversion factor. (d) To convert from grams to moles and vice versa, use molar mass as a conversion factor. (e) A limiting reagent is the reagent that is used up first. (f) Suppose a chemical reaction between A and B requires 1 mol of \(A\) and 2 mol of \(B\). If 1 mol of each is present, then \(\mathrm{B}\) is the limiting reagent. (g) Theoretical yield is the yield of product that should be obtained according to the balanced chemical equation. (h) Theoretical yield is the yield of product that should be obtained if all limiting reagent is converted to product. (i) Percent yield is the number of grams of product divided by the number of grams of the limiting reagent times 100 (j) To calculate percent yield, divide the mass of product formed by the theoretical yield and multiply by 100

If \(7.0 \mathrm{kg}\) of \(\mathrm{N}_{2}\) is added to \(11.0 \mathrm{kg}\) of \(\mathrm{H}_{2}\) to form \(\mathrm{NH}_{3}\) which reactant is in excess? \(\mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) \longrightarrow 2 \mathrm{NH}_{3}(\mathrm{g})\)

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