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Although not a transition metal, lead can form \(\mathrm{Pb}^{2+}\) and \(\mathrm{Pb}^{4+}\) ions. Write the formula for the compound formed between each of these lead ions and the following anions: (a) Chloride ion (b) Hydroxide ion (c) Oxide ion

Short Answer

Expert verified
\(\mathrm{PbCl}_2\), \(\mathrm{PbCl}_4\), \(\mathrm{Pb(OH)}_2\), \(\mathrm{Pb(OH)}_4\), \(\mathrm{PbO}\), and \(\mathrm{PbO}_2\).

Step by step solution

01

Understanding Lead Ions

Lead can exist as \(\mathrm{Pb}^{2+}\) and \(\mathrm{Pb}^{4+}\), which means it can form compounds with different oxidation states.
02

Chloride Ion with Pb虏鈦

The chloride ion ( \mathrm{Cl}^{-}) carries a -1 charge. To balance this charge with \(\mathrm{Pb}^{2+}\), we need two chloride ions. The formula is \mathrm{PbCl}_2.
03

Chloride Ion with Pb鈦粹伜

The chloride ion ( \mathrm{Cl}^{-}) still carries a -1 charge. To balance four positive charges from \(\mathrm{Pb}^{4+}\), we need four chloride ions. The formula is \mathrm{PbCl}_4.
04

Hydroxide Ion with Pb虏鈦

The hydroxide ion ( \mathrm{OH}^{-}) has a -1 charge. To balance \(\mathrm{Pb}^{2+}\), we need two hydroxide ions. The formula is \mathrm{Pb(OH)}_2.
05

Hydroxide Ion with Pb鈦粹伜

The hydroxide ion ( \mathrm{OH}^{-}) still carries a -1 charge. To balance the \(\mathrm{Pb}^{4+}\), we need four hydroxide ions. The formula is \mathrm{Pb(OH)}_4.
06

Oxide Ion with Pb虏鈦

The oxide ion ( \mathrm{O}^{2-}) has a -2 charge, which matches with the \(\mathrm{Pb}^{2+}\). Therefore, only one oxide ion is needed. The formula is \mathrm{PbO}.
07

Oxide Ion with Pb鈦粹伜

The oxide ion ( \mathrm{O}^{2-}) has a -2 charge, so two of these ions will balance with \(\mathrm{Pb}^{4+}\). The formula is \mathrm{PbO}_2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oxidation States
Lead is an interesting element because it exhibits multiple oxidation states, commonly \(+2\) and \(+4\). The oxidation state indicates the charge of an ion when electrons are lost, gained, or shared. In the case of lead, this flexibility allows for the formation of various compounds. The \(\mathrm{Pb}^{2+}\eq\mathrm{Pb}^{4+}\) ions can form when lead either loses two or four electrons.
This results in different reactions and compound formations depending on the lead ion involved.
  • \(\text{Oxidation state of +2:}\) When lead loses two electrons, it forms the ion \(\mathrm{Pb}^{2+}\).
  • \(\text{Oxidation state of +4:}\) When lead loses four electrons, it forms the ion \(\mathrm{Pb}^{4+}\).
The ability to form these ions is critical in determining what anions lead can combine with, producing compounds that range in different chemical properties.
Chemical Formulas
Chemical formulas are essential tools for understanding how different elements and ions interact to form compounds. Each chemical formula conveys vital information about the elements involved and their proportions. For example, the chemical formula \(\mathrm{PbCl}_2\) conveys the ratio of lead to chloride ions required to maintain a neutral charge.
When determining a chemical formula, the principal goal is to achieve neutrality, meaning the positive and negative charges balance each other out.To construct a chemical formula, follow these simple steps:
  • Identify the ions involved: Determine the positive (cation) and negative (anion) ions and their charges.
  • Balance the total charge: Select the number of each ion needed to ensure the total positive charge equals the total negative charge.
  • Write the formula: Use subscripts to indicate the number of each ion required. The subscript is not needed when only one ion is present.
These steps lead to accurate representation of compounds, such as \(\mathrm{Pb(OH)}_2\) and \(\mathrm{PbO}\), based on lead's different oxidation states and interactions with anions.
Anion Interactions
Interactions between lead ions and anions are fundamental in forming various lead compounds. Anions are negatively charged ions, and when they pair with lead's positively charged ions, they create stable compounds. Each anion has a specific charge, which influences how many of them are needed to maintain charge balance with lead ions.
  • Chloride Ion (\(\mathrm{Cl}^{-}\)): When paired with \(\mathrm{Pb}^{2+}\), two chloride ions are needed (as in \(\mathrm{PbCl}_2\)) to balance the charge. For \(\mathrm{Pb}^{4+}\), four chloride ions are required, forming \(\mathrm{PbCl}_4\).
  • Hydroxide Ion (\(\mathrm{OH}^{-}\)): This ion acts similarly to chloride in charge, leading to compounds \(\mathrm{Pb(OH)}_2\) with \(\mathrm{Pb}^{2+}\) and \(\mathrm{Pb(OH)}_4\) when paired with \(\mathrm{Pb}^{4+}\).
  • Oxide Ion (\(\mathrm{O}^{2-}\)): With a different charge, only one oxide ion is enough to balance with \(\mathrm{Pb}^{2+}\), but two are needed to balance with \(\mathrm{Pb}^{4+}\), forming compounds like \(\mathrm{PbO}\) and \(\mathrm{PbO}_2\).
Understanding these interactions is crucial for predicting and balancing chemical equations properly. It highlights the significance of selecting the correct ratio of ions based on their respective charges.

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Most popular questions from this chapter

Draw a Lewis structure of a covalent compound in which nitrogen has: (a) Three single bonds and one unshared pair of electrons (b) One single bond, one double bond, and one unshared pair of electrons (c) One triple bond and one unshared pair of electrons

Use the valence-shell electron-pair repulsion model to predict the shape of a molecule in which a central atom is surrounded by five regions of electron density-as, for example, in phosphorus pentafluoride, \(\mathrm{PF}_{5} .\) (Hint: Use molecular models or if you do not have a set handy, use marshmallows or gumdrops and toothpicks.)

Answer true or false. (a) For Group 1A and Group 2A elements, the name of the ion each forms is simply the name of the element followed by the word ion; for example, \(\mathrm{Mg}^{2+}\) is named magnesium ion. (b) \(\mathrm{H}^{-}\) is named hydride ion. (c) The nucleus of \(\mathrm{H}^{+}\) consists of one proton and one neutron. (d) Many transition and inner transition elements form more than one positively charged ion. (e) In naming metal cations with two different charges, the suffix -ous refers to the ion with a charge of +1 and -ic refers to the ion with a charge of +2 (f) \(\mathrm{Fe}^{3+}\) may be named either iron(III) ion or ferric ion. (g) The anion derived from a bromine atom is named bromine ion. (h) The anion derived from an oxygen atom is named oxide ion. (i) \(\quad \mathrm{HCO}_{3}^{-}\) is named hydrogen carbonate ion. (j) The prefix \(b i-\) in the name "bicarbonate" ion indicates that this ion has a charge of -2 (k) The hydrogen phosphate ion has a charge of +1 and the dihydrogen phosphate ion has a charge of +2 (l) The phosphate ion is \(\mathrm{PO}_{3}^{4-}\) \((\mathrm{m})\) The nitrite ion is \(\mathrm{NO}_{2}^{-},\) and the nitrate ion is \(\mathrm{NO}_{3}^{-}\) (n) The carbonate ion is \(\mathrm{CO}_{3}^{2-},\) and the hydrogen carbonate ion is \(\mathrm{HCO}_{3}^{-}\)

Knowing what you do about covalent bonding in compounds of carbon, nitrogen, and oxygen and given the fact that silicon is just below carbon in the Periodic Table, phosphorus is just below nitrogen, and sulfur is just below oxygen, predict the molecular formula for the compound formed by (a) silicon and chlorine, (b) phosphorus and hydrogen, and (c) sulfur and hydrogen.

Table 3.2 shows the following ions of copper: \(\mathrm{Cu}^{+}\) and \(\mathrm{Cu}^{2+} .\) Do these violate the octet rule? Explain.

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