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When 2.16 g of mercuric oxide is heated, it decomposes to yield 2.00 g of mercury and 0.16 g of oxygen. Which law is supported by this experiment?

Short Answer

Expert verified
The experiment supports the Law of Conservation of Mass.

Step by step solution

01

Identify the Elements in the Chemical Reaction

In the experiment, mercuric oxide decomposes into mercury and oxygen. We start by noting the elements involved: Mercury (Hg) and Oxygen (O).
02

Analyze the Mass of Substances

The total mass of the reactant (mercuric oxide) is 2.16 grams. After decomposition, we have 2.00 grams of mercury and 0.16 grams of oxygen.
03

Apply the Law of Conservation of Mass

The Law of Conservation of Mass states that mass in a closed system must remain constant over time. Compare the initial and final masses: 2.16 g (initial mass) = 2.00 g (mercury) + 0.16 g (oxygen) (final mass).
04

Conclusion

Since the total mass before and after the reaction are equal, this supports the Law of Conservation of Mass, which dictates that mass is neither created nor destroyed in a chemical reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reaction
A chemical reaction is a process where substances, known as reactants, are transformed into different substances, known as products. These reactions involve the breaking and forming of chemical bonds, which alter the arrangement of atoms. In our example, the chemical reaction of interest is the decomposition of mercuric oxide. When mercuric oxide is heated, it breaks down into mercury and oxygen. This is a type of chemical reaction known as decomposition, where a single compound breaks down into two or more simpler substances. This transformation is typical in chemical reactions, allowing elements to rearrange into new compounds, often accompanied by observable changes such as emission of gas, temperature change, or color change. Chemical reactions follow certain conservation laws, one of which is the Law of Conservation of Mass, ensuring that the mass of reactants equals the mass of products.
Mercuric Oxide Decomposition
The decomposition of mercuric oxide provides a textbook example of how chemical reactions adhere to conservation laws. Mercuric oxide (\( HgO \)) is a compound composed of mercury and oxygen. Upon heating, it decomposes into two distinct elements: mercury (\( Hg \)) and oxygen (\( O_2 \)). This decomposition reaction can be represented by the equation:\[2 \text{ HgO} \rightarrow 2 \text{ Hg} + \text{ O}_2\] When mercuric oxide is heated, the chemical bonds between mercury and oxygen break, freeing the mercury atoms and releasing oxygen molecules as a gas. In the example given, 2.16 grams of mercuric oxide yield 2.00 grams of mercury and 0.16 grams of oxygen. This measurement demonstrates the practical application of the Law of Conservation of Mass since the total mass of the reactants equals the total mass of the products.
Elements in a Reaction
Every chemical reaction involves elements or compounds interacting and transforming into different chemical substances. It is essential to recognize the elements and compounds undergoing change during a reaction. In the decomposition of mercuric oxide, the elements involved are:
  • Mercury (Hg): A metallic element that occurs naturally and is commonly found in the compound mercuric oxide.
  • Oxygen (O): A highly reactive non-metal essential for the oxidation processes, released as a diatomic gas (\( O_2 \)) in this reaction.
Understanding these elements and how they rearrange provides insight into the reaction itself. By identifying each element's role, we can better understand the process that follows. In this instance, the decomposition reaction results in mercury being freed as a liquid metal, while oxygen forms into oxygen gas, emphasizing the transformation nature of chemical reactions.

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Most popular questions from this chapter

Answer true or false. (a) Ionization energy is the energy required to remove the most loosely held electron from an atom in the gas phase. (b) When an atom loses an electron, it becomes a positively charged ion. (c) Ionization energy is a periodic property because ground-state electron configuration is a periodic property. (d) Ionization energy generally increases going from left to right across a period of the Periodic Table. (e) Ionization energy generally increases in going from top to bottom within a column in the Periodic Table. (f) The sign of an ionization energy is always positive.

Name and give the symbol of the element with the given characteristic. (a) Largest atomic radius in Group \(2 \mathrm{A}\) (b) Smallest atomic radius in Group 2 A. (c) Largest atomic radius in the second period. (d) Smallest atomic radius in the second period. (e) Largest ionization energy in Group 7 A. (f) Lowest ionization energy in Group 7A.

The average atomic weight of lithium is 6.941 amu. The two naturally occurring isotopes of lithium have the following masses: \(^{6} \mathrm{Li}, 6.01512 \mathrm{amu} ;^{7} \mathrm{Li}, 7.01600\) amu. Calculate the percent abundance of \(^{6} \mathrm{Li}\) and \(^{7} \mathrm{Li}\) in naturally occurring lithium.

The elements game, Part I. Name and give the symbol of the element that is named for each person. (a) Niels Bohr \((1885-1962),\) Nobel Prize for Physics in 1922 (b) Pierre and Marie Curie, Nobel Prize for Chemistry in 1903 (c) Albert Einstein \((1879-1955),\) Nobel Prize for Physics in 1921 (d) Enrico Fermi \((1901-1954),\) Nobel Prize for Physics in 1938 (e) Ernest Lawrence \((1901-1958),\) Nobel Prize for Physics in 1939 (f) Lise Meitner \((1868-1968),\) codiscoverer of nuclear fission (g) Dmitri Mendeleyev \((1834-1907),\) first person to formulate a workable Periodic Table (h) Alfred Nobel \((1833-1896),\) discoverer of dynamite (i) Ernest Rutherford \((1871-1937),\) Nobel Prize for Chemistry in 1908. (j) Glenn Seaborg (1912-1999), Nobel Prize for Chemistry in 1951.

The elements game, Part II. Name and give the symbol of the element that is named for each geographic location. (a) The Americas (b) Berkeley, California (c) The state and University of California (d) Dubna, location in Russia of the Joint Institute of Nuclear Research (e) Europe (f) France (g) Gallia, the Latin name for ancient France (h) Germany (i) Hafnia, the Latin name for ancient Copenhagen (j) Hesse, a German state (k) Holmia, the Latin name for ancient Stockholm (1) Lutetia, the Latin name for ancient Paris \((\mathrm{m})\) Magnesia, a district in Thessaly (n) Poland, the native country of Marie Curie (o) Rhenus, the Latin name for the river Rhine (p) Ruthenia, the Latin name for ancient Russia (q) Scandia, the Latin name for ancient Scandinavia (r) Strontian, a town in Scotland (s) Ytterby, a village in Sweden (three elements) (t) Thule, the earliest name for Scandinavia

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