/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 What is the belt of stability?... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 21: Problem 8

What is the belt of stability?

Short Answer

Expert verified
The Belt of Stability is a region on a graph where the number of neutrons is plotted against the number of protons in stable isotopes. It demonstrates which combinations of these particles will create a stable nucleus. In stable nuclei, ratios of neutrons to protons increase as the atomic number (number of protons in an atom's nucleus) increases

Step by step solution

01

Defining the Belt of Stability

The Belt of Stability is a term in nuclear physics. It refers to the area on a graph that plots the number of neutrons against the number of protons in stable isotopes (Isotopes are variants of a particular chemical element which differ in neutron number).
02

Explaining how the Belt of Stability works

The 'belt' shows which combinations of neutrons and protons will make a stable nucleus. When observations or data of nuclei are plotted, a clear, narrow 'belt' or region of stable (non-radioactive) nuclei can be identified. For nuclei with a low atomic number, the ratio of neutrons to protons in stable nuclei is approximately 1:1. However, as the atomic number increases, stable nuclei usually have more neutrons than protons.
03

Identifying the importance of the Belt of Stability

Understanding the Belt of Stability is important because it helps scientists predict whether a certain isotope will be stable or radioactive. If a nucleus has too many or too few neutrons for the number of protons, it will be outside this belt and will therefore be radioactive.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Tritium, \({ }^{3} \mathrm{H},\) is radioactive and decays by electron emission. Its half-life is 12.5 yr. In ordinary water the ratio of \({ }^{1} \mathrm{H}\) to \({ }^{3} \mathrm{H}\) atoms is \(1.0 \times 10^{17}\) to \(1 .\) (a) Write a balanced nuclear equation for tritium decay. (b) How many disintegrations will be observed per minute in a \(1.00-\mathrm{kg}\) sample of water?

How does a Geiger counter work?

Define nuclear binding energy, mass defect, and nucleon.

A freshly isolated sample of \(90 \mathrm{Y}\) was found to have an activity of \(9.8 \times 10^{5}\) disintegrations per minute at 1: 00 P.M. on December \(3,2000 .\) At 2: 15 P.M. on December \(17,2000,\) its activity was redetermined and found to be \(2.6 \times 10^{4}\) disintegrations per minute. Calculate the half-life of \(90 \mathrm{Y}\).

Each molecule of hemoglobin, the oxygen carrier in blood, contains four Fe atoms. Explain how you would use the radioactive \({ }_{26}^{59} \mathrm{Fe}\left(t_{\frac{1}{2}}=46\right.\) days) to show that the iron in a certain food is converted into hemoglobin.
See all solutions

Recommended explanations on Chemistry Textbooks

The Earths Atmosphere

Read Explanation

Organic Chemistry

Read Explanation

Physical Chemistry

Read Explanation

Kinetics

Read Explanation

Chemical Analysis

Read Explanation

Inorganic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.