/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Describe the interaction between... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 20: Problem 10

Describe the interaction between a donor atom and a metal atom in terms of a Lewis acid-base reaction.

Short Answer

Expert verified
A donor atom, which is a Lewis base, donates a pair of nonbonding electrons to the metal atom, acting as a Lewis acid, which accepts the electron pair. This results in a Lewis acid-base complex.

Step by step solution

01

Defining Lewis Acid and Lewis Base

Lewis Acids and Bases are defined contrary to the traditional acidic and basic substances. A Lewis base is any substance, such as the OH- ion, that can donate a pair of nonbonding electrons. A Lewis acid is any substance, like the H+ ion, that can accept a pair of nonbonding electrons.
02

Identifying the Donor Atom

According to the Lewis base definition given in step 1, a donor atom must be a Lewis base. This is because Lewis bases are known to donate a pair of nonbonding electrons.
03

Identifying the Metal Atom

The metal atom in this interaction would be considered as a Lewis acid. This is because metals have few valence electrons and have the capacity to accept additional electron pairs from a base.
04

Describing the Interaction

In terms of a Lewis acid-base reaction, a donor atom (Lewis base) donates a pair of nonbonding electrons, which are accepted by the metal atom (Lewis acid). This results in the creation of a Lewis acid-base complex.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What are the systematic names for these ions and compounds: (a) \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{4} \mathrm{Cl}_{2}\right]^{+},\) (b) \(\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3},\) (c) \(\left[\mathrm{Co}(\mathrm{en})_{2} \mathrm{Br}_{2}\right]^{+},\) (d) \(\mathrm{Fe}(\mathrm{CO})_{5} ?\)

What factors determine whether a given complex will be diamagnetic or paramagnetic?

Give the oxidation numbers of the metals in these species: (a) \(\mathrm{Na}_{2} \mathrm{MoO}_{4}\) (b) \(\mathrm{MgWO}_{4}\), (c) \(\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]\)

Draw qualitative diagrams for the crystal-field splittings in (a) a linear complex ion \(\mathrm{ML}_{2},\) (b) a trigonalplanar complex ion \(\mathrm{ML}_{3},\) and \((\mathrm{c})\) a trigonalbipyramidal complex ion ML \(_{5}\).

The \(\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-}\) ion, which has a square planar geometry, is diamagnetic, whereas the \(\left[\mathrm{NiCl}_{4}\right]^{2-}\) ion, which has a tetrahedral geometry, is paramagnetic. Show the crystal field splitting diagrams for those two complexes.
See all solutions

Recommended explanations on Chemistry Textbooks

Ionic and Molecular Compounds

Read Explanation

Organic Chemistry

Read Explanation

Chemical Analysis

Read Explanation

Inorganic Chemistry

Read Explanation

Chemistry Branches

Read Explanation

Nuclear Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.