Chapter 20: Problem 79
Find the change of mass (in grams) resulting from the release of heat when \(1 \mathrm{~mol} \mathrm{C}\) reacts with \(1 \mathrm{~mol} \mathrm{O}_{2}\). $$ \mathrm{C}(s)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{CO}_{2}(g) ; \Delta H=-393.5 \mathrm{~kJ} $$
Short Answer
Expert verified
The change in mass is approximately \( 4.37 \times 10^{-9} \text{ g} \).
Step by step solution
01
Understand the Reaction Given
The reaction between solid carbon (C) and oxygen gas \( \mathrm{O}_2 \) yields carbon dioxide \( \mathrm{CO}_2 \) with a given enthalpy change \( \Delta H = -393.5 \text{ kJ} \). \( \Delta H \) represents the heat released when 1 mole of carbon reacts with 1 mole of oxygen to form 1 mole of carbon dioxide.
02
Relate Energy and Mass
Use the mass-energy equivalence principle from Einstein's famous equation \( E = mc^2 \). This equation relates energy \( E \) to mass \( m \), with \( c \) being the speed of light in a vacuum \( (3 \times 10^8 \text{ m/s}) \). Here, \( E \) is the energy released during the reaction, which is 393.5 kJ.
03
Convert Energy from kJ to J
To use \( E = mc^2 \), we need \( E \) in joules (J). Convert 393.5 kJ to J: \[ 393.5 \text{ kJ} = 393.5 \times 10^3 \text{ J} = 393500 \text{ J} \]
04
Calculate the Change in Mass
Apply \( E = mc^2 \) to calculate the change in mass \( \Delta m \): \[ \Delta m = \frac{E}{c^2} = \frac{393500 \text{ J}}{(3 \times 10^8 \text{ m/s})^2} \] Simplify and calculate: \[ \Delta m \approx \frac{393500}{9 \times 10^{16}} \approx 4.37 \times 10^{-12} \text{ kg} \]
05
Convert Mass from kg to grams
Since mass is often expressed in grams, convert \( \Delta m \) from kilograms to grams: \[ 4.37 \times 10^{-12} \text{ kg} = 4.37 \times 10^{-12} \times 10^3 \text{ g} = 4.37 \times 10^{-9} \text{ g} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Mass-Energy Equivalence
The mass-energy equivalence principle is a crucial concept in understanding chemical reactions and energy transformations. This principle is elegantly summed up in Einstein's equation, \( E = mc^2 \), where:
- \( E \) represents energy in joules (J).
- \( m \) stands for mass in kilograms (kg).
- \( c \) is the speed of light, approximately \( 3 \times 10^8 \text{ m/s} \).
Reaction Heat
The concept of reaction heat, or enthalpy change \( \Delta H \), is essential to understanding energy transformations during chemical reactions. In our exercise, \( \Delta H = -393.5 \text{ kJ} \), indicates that the reaction between carbon and oxygen to form carbon dioxide is exothermic. This negative value signifies the release of energy as heat:
- **Exothermic Reaction:** Releases energy to the surroundings, thus having a negative \( \Delta H \).
- **Endothermic Reaction:** Absorbs energy from the surroundings, resulting in a positive \( \Delta H \).
Carbon Dioxide Formation
The formation of carbon dioxide \( \text{CO}_2 \) is central to understanding the chemical reaction discussed. When carbon and oxygen react, carbon dioxide is the primary product, implicating a direct carbon-to-oxygen interaction forming \( \text{CO}_2 \):
- **Carbon (C) + Oxygen (\( \text{O}_2 \)):** - Reacts to form \( \text{CO}_2 \). - This reaction is a complete combustion process.