Chapter 16: Problem 140
The \(K_{b}\) for \(\mathrm{NH}_{3}\) is \(1.8 \times 10^{-5}\) at \(25^{\circ} \mathrm{C}\). Calculate the \(\mathrm{pH}\) of a buffer solution made by mixing \(65.1 \mathrm{~mL}\) of \(0.142 \mathrm{M} \mathrm{NH}_{3}\) with \(39.2 \mathrm{~mL}\) of \(0.172 M \mathrm{NH}_{4} \mathrm{Cl}\) at \(25^{\circ} \mathrm{C}\). Assume that the volumes of the solutions are additive.
Short Answer
Step by step solution
Understand Reaction and Definitions
Calculate Initial Moles
Total Volume of Solution
Calculate Concentrations in Buffer
Determine K_a from K_b
Use Henderson-Hasselbalch Equation
Calculate Final pH
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Henderson-Hasselbalch equation
- \(\text{pH}\) is the measure of acidity or basicity of the solution.
- \(\text{pK}_a\) is the negative logarithm of the acid dissociation constant.
- The term \([\text{Salt}]\) refers to the concentration of the base (NH鈧 in this case).
- \([\text{Acid}]\) refers to the concentration of the conjugate acid (NH鈧勨伜 in this buffer).
Weak acids and bases
- Weak bases, like NH鈧, only partially dissociate, resulting in a relatively higher pH than neutral water.
- The equilibrium established in solution produces a small but significant concentration of OH鈦 ions, leading to basic characteristics.
Buffer systems in chemistry
- Adding an acidic component: The base (NH鈧) reacts with the additional H鈦 ions to form more NH鈧勨伜, minimizing changes in pH.
- Adding a basic component: The conjugate acid (NH鈧勨伜) reacts with OH鈦 ions to form more NH鈧 and water, stabilizing the pH.