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What is meant by the common-ion effect? Give an example.

Short Answer

Expert verified
The common-ion effect reduces solubility when a solution already contains an ion from the solute. For example, adding NaF to a CaF_2 solution lowers CaF_2 solubility.

Step by step solution

01

Understand the Concept

The common-ion effect describes the decrease in the solubility of an ionic compound when it is dissolved in a solution that already contains one of the ions present in the compound. This happens due to Le Chatelier's principle, which dictates that the equilibrium will shift to counteract the change imposed on the system when an additional common ion is introduced.
02

Identify the Le Chatelier's Principle Involvement

Le Chatelier's principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to counteract the change. In the context of the common-ion effect, adding an ion common to the solute shifts the equilibrium towards decreased solubility to restore balance, typically resulting in precipitation or reduced dissolution.
03

Provide an Example for Clarification

Consider a saturated solution of calcium fluoride, CaF_2. This solution dissociates into Ca^{2+} and F^- ions. Now, if sodium fluoride (NaF) is added to this solution, it introduces additional F^- ions. According to the common-ion effect, the increased concentration of F^- ions will shift the dissolution equilibrium of CaF_2, and more CaF_2 will precipitate out, reducing the overall solubility of CaF_2 in the solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solubility
Solubility is a key concept in chemistry that refers to the ability of a substance, called the solute, to dissolve in a solvent to form a homogeneous solution. The solubility of a substance depends on several factors, such as temperature, pressure, and the nature of both the solute and the solvent. For ionic compounds, solubility involves the dissociation of the compound into its individual ions.
When it comes to ionic compounds, solubility can be influenced by the presence of common ions. This effect is crucial in understanding solutions and reactions in aqueous environments.
  • Temperature: Generally, higher temperatures increase solubility for solids in liquids, though gases typically become less soluble.
  • Pressure: More significant for gases, where increased pressure enhances solubility in liquids.
  • Common-ion effect: This effect can significantly reduce the solubility of an ionic compound, as detailed with the common-ion effect.
Understanding solubility allows chemists to predict how substances will interact in solutions.
Le Chatelier's Principle
Le Chatelier's principle is a foundational concept in chemistry that helps predict the behavior of a system in dynamic equilibrium when it undergoes a change in concentration, temperature, or pressure. This principle states that if any of these factors change, the equilibrium position will adjust in a way to minimize that change.
In the context of the common-ion effect, when an additional ion that is part of the dissolved ionic compound (a common ion) is added to the solution, the equilibrium shifts. Le Chatelier's principle explains how this addition leads to a new balance in the system.
  • Response to changes: If the concentration of a reactant in an equilibrium system increases, the system will shift to consume the added reactants and restore balance.
  • Temperature impact: Although temperature changes can shift equilibrium, in the case of common ions, concentration changes are more relevant.
  • Common-ion effect: With the addition of a common ion, the relevant equilibrium shifts towards decreasing the solubility of the ionic compound.
This principle is widely applied in predicting how different reactions and processes will respond to external changes.
Equilibrium Shift
An equilibrium shift refers to the change in the position of an equilibrium in response to a perturbation of the system. In the setting of the common-ion effect, an equilibrium shift occurs when a common ion is introduced to a solution.
For example, when NaF is added to a solution of CaF\(_2\), the additional fluoride ions cause the equilibrium position to move towards the side of the undissolved solid, thereby decreasing the solubility of CaF\(_2\). This shift ultimately leads to more of the CaF\(_2\) precipitating out of the solution.
  • Factors affecting shifts: The introduction of common ions, changes in temperature, or pressure can lead to an equilibrium shift.
  • Direction of shift: According to Le Chatelier's principle, the system will adjust to counteract the change; thus, shifts in solubility often lead to precipitation or less dissolution of solutes.
  • Practical implications: This understanding is crucial in designing chemical processes and in explaining natural phenomena like the formation of scale in pipes.
The concept of equilibrium shift is essential in controlling and altering chemical equilibria for desired outcomes.
Ionic Compounds
Ionic compounds are a class of chemical compounds composed of ions held together by electrostatic forces known as ionic bonds. These compounds typically form between metals and non-metals, where one atom donates electrons to another, resulting in positively and negatively charged ions.
In aqueous solutions, ionic compounds can dissociate into their respective ions, which significantly influences their behavior in water and other solvents.
  • Properties: Ionic compounds generally have high melting and boiling points due to strong ionic bonds.
  • Conductivity: In solution, they can conduct electricity as the ions are free to move.
  • Solubility factors: The presence of common ions can alter their usual solubility patterns, known as the common-ion effect.
Recognizing these properties aids in comprehending a range of chemical reactions and behaviors, especially in solution chemistry.

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Most popular questions from this chapter

A 25.00-mL sample contains \(0.562 \mathrm{~g}\) of \(\mathrm{NaHCO}_{3}\). This sample is used to standardize an NaOH solution. At the equivalence point, \(42.36 \mathrm{~mL}\) of \(\mathrm{NaOH}\) has been added. a. What was the concentration of the \(\mathrm{NaOH}\) ? b. What is the \(\mathrm{pH}\) at the equivalence point? C. Which indicator, bromthymol blue, methyl violet, or alizarin yellow R, should be used in the titration? Why?

\(K_{a}\) for acetic acid is \(1.7 \times 10^{-5}\) at \(25^{\circ} \mathrm{C}\). A buffer solution is made by mixing \(52.1 \mathrm{~mL}\) of \(0.122 M\) acetic acid with \(46.1\) \(\mathrm{mL}\) of \(0.182 M\) sodium acetate. Calculate the \(\mathrm{pH}\) of this solution at \(25^{\circ} \mathrm{C}\) after the addition of \(5.82 \mathrm{~mL}\) of \(0.125 \mathrm{MaOH}\).

Each of the following statements concerns a \(0.010 M\) solution of a weak acid, HA. Briefly describe why each statement is either true or false. a. \([\mathrm{HA}]\) is approximately equal to \(0.010 \mathrm{M}\). b. \([\mathrm{HA}]\) is much greater than \(\left[\mathrm{A}^{-}\right]\). c. \(\left[\mathrm{OH}^{-}\right]\) is approximately equal to \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\). d. The \(\mathrm{pH}\) is 2 . e. The \(\mathrm{H}_{3} \mathrm{O}^{+}\) concentration is \(0.010 \mathrm{M}\). f. \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) is approximately equal to \(\left[\mathrm{A}^{-}\right]\).

You have the following solutions, all of the same molar concentration: \(\mathrm{KBr}, \mathrm{HBr}, \mathrm{CH}_{3} \mathrm{NH}_{2}\), and \(\mathrm{NH}_{4} \mathrm{Cl}\). Rank them from the lowest to the highest hydroxide-ion concentration.

A 0.239-g sample of unknown organic base is dissolved in water and titrated with a \(0.135 M\) hydrochloric acid solution. After the addition of \(18.35 \mathrm{~mL}\) of acid, a pH of \(10.73\) is recorded. The equivalence point is reached when a total of \(39.24 \mathrm{~mL}\) of \(\mathrm{HCl}\) is added. The base and acid combine in a 1:1 ratio. a. What is the molar mass of the organic base? b. What is the \(K_{b}\) value for the base? The \(K_{b}\) value could have been determined very easily if a pH measurement had been made after the addition of \(19.62 \mathrm{~mL}\) of HCl. Why?

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