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Nickel(II) sulfate solution reacts with lithium hydroxide solution to produce a precipitate of nickel(II) hydroxide and a solution of lithium sulfate. Write the molecular equation for this reaction. Then write the corresponding net ionic equation.

Short Answer

Expert verified
Molecular Equation: \( \text{NiSO}_4 (aq) + 2\text{LiOH} (aq) \rightarrow \text{Ni(OH)}_2 (s) + \text{Li}_2\text{SO}_4 (aq) \). Net Ionic Equation: \( \text{Ni}^{2+} (aq) + 2\text{OH}^- (aq) \rightarrow \text{Ni(OH)}_2 (s) \).

Step by step solution

01

Identify Reactants and Products

The reaction involves Nickel(II) sulfate \((\text{NiSO}_4)\) and Lithium hydroxide \((\text{LiOH})\). These react to form Nickel(II) hydroxide \((\text{Ni(OH)}_2)\) as a precipitate, and Lithium sulfate \((\text{Li}_2\text{SO}_4)\) as a product in solution.
02

Write the Molecular Equation

Write the balanced molecular equation for the reaction:\[ \text{NiSO}_4 (aq) + 2\text{LiOH} (aq) \rightarrow \text{Ni(OH)}_2 (s) + \text{Li}_2\text{SO}_4 (aq) \]
03

Separate into Ions

Identify the dissociated ions in the aqueous solutions to prepare for the net ionic equation. - Nickel(II) sulfate dissociates into \(\text{Ni}^{2+} \) and \(\text{SO}_4^{2-} \) in solution.- Lithium hydroxide dissociates into \(\text{Li}^+ \) and \(\text{OH}^- \) in solution.- Lithium sulfate dissociates into \(\text{Li}^+ \) and \(\text{SO}_4^{2-} \) in solution.
04

Identify the Spectator Ions

Spectator ions do not change during the reaction and appear unchanged on both sides of the equation:- \(\text{Li}^+\) and \(\text{SO}_4^{2-}\) ions are spectator ions in this reaction.
05

Write the Net Ionic Equation

Remove the spectator ions and write the net ionic equation, showing only the ions and compounds that participate in the reaction:\[ \text{Ni}^{2+} (aq) + 2\text{OH}^- (aq) \rightarrow \text{Ni(OH)}_2 (s) \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Net Ionic Equation
In chemistry, the net ionic equation is a way to simplify the analysis of a chemical reaction. It shows only the chemical species that are actually involved and directly changing during the chemical reaction, highlighting the key components which are active participants in forming the product.
The purpose of the net ionic equation is to strip away the "extra" ions that do not participate in the reaction, leaving only the substances that do. For precipitation reactions, this means mainly focusing on the formation of the solid precipitate.
To write a net ionic equation, follow these steps:
  • Write down the balanced molecular equation for the reaction.
  • Dissociate all the strong electrolytes into their constituent ions.
  • Identify and remove the ions that appear on both sides of the equation in the same form, known as spectator ions.
The resulting net ionic equation will provide a clearer picture of the reaction. For example, when nickel(II) sulfate reacts with lithium hydroxide, the net ionic equation focuses solely on the ions involved in forming nickel(II) hydroxide, leaving out those that do not change.
Chemical Equations
Chemical equations are symbolic representations of chemical reactions. They provide a concise way to depict what happens during a reaction, showcasing reactants transforming into products. Understanding chemical equations is fundamental for grasping how chemical reactions occur and are represented.
The first step is writing a balanced molecular equation. This involves using chemical formulas to denote reactants and products, ensuring that the number of atoms of each element is the same on both sides. This respects the law of conservation of mass, which asserts that mass is neither created nor destroyed in a chemical reaction.
Key aspects of chemical equations include:
  • Aqueous substances (like nickel(II) sulfate) are denoted as \((aq)\), indicating they are dissolved in water.
  • Solids formed during a reaction (such as nickel(II) hydroxide) are denoted as \((s)\).
  • Coefficients are used to balance the number of molecules or moles involved.
In this exercise, writing the balanced equation successfully conveys the transformation, linking reactants to products through chemical identifiers and symbols.
Spectator Ions
Spectator ions are ions present in a reaction mixture that do not participate directly in a chemical change. They appear on both the reactant and product sides of a chemical equation in the same form, indicating that they don’t undergo any transformation during the reaction.
In the reaction between nickel(II) sulfate and lithium hydroxide, spectator ions include \(\text{Li}^+\) and \(\text{SO}_4^{2-}\). These ions are dissociated in the solution but do not contribute to the formation of the precipitate, nickel(II) hydroxide.
To identify spectator ions, you should:
  • Write the full ionic equation, showing all dissociated ions.
  • Compare ions on the reactant side to those on the product side.
  • Identify ions that remain unchanged in both the reactant and product sides – these are your spectator ions.
The removal of spectator ions to form the net ionic equation helps to simplify the reaction. This focus highlights the essence of the chemical change taking place, making it easier to understand and analyze the actual interaction happening among reactants. This clarity is essential for deeper chemistry comprehension and effectively communicating reactions.

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