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Consider the reducing agents \(\mathrm{Sn}^{2+}(a q), \mathrm{Cu}(s)\), and \(\mathrm{I}^{-}(a q) .\) Which is strongest? Which is weakest?

Short Answer

Expert verified
The strongest reducing agent is \(\mathrm{Sn}^{2+}\), and the weakest is \(\mathrm{I}^-\).

Step by step solution

01

Understanding Reducing Agents

A reducing agent is a substance that donates electrons to another species, being oxidized itself in the process. The strength of a reducing agent is determined by its ability to lose electrons easily.
02

Looking Up Standard Electrode Potentials

Refer to a standard electrode potential table to find the electrode potentials for the half-reactions involving the given reducing agents.- For \( \mathrm{Sn}^{2+}(aq) + 2e^- \rightarrow \mathrm{Sn}(s) \), the standard electrode potential \( E^0 \) is \(-0.14 \text{ V} \).- For \( \mathrm{Cu}^{2+}(aq) + 2e^- \rightarrow \mathrm{Cu}(s) \), the \( E^0 \) is \(+0.34 \text{ V} \).- For \( \mathrm{I}_2(s) + 2e^- \rightarrow 2 \mathrm{I}^- (aq)\), the \( E^0 \) is \(+0.54 \text{ V} \).
03

Analyzing Reduction Potentials

A species at the bottom of the reduction potential table acts as the best reducing agent. Evaluate which of the given agents has the most negative standard reduction potential.
04

Identify the Strongest Reducing Agent

Given the electrode potentials, \( Sn^{2+} \) with \( -0.14 \text{ V} \) is the most negative and thus the strongest reducing agent among the given options.
05

Identify the Weakest Reducing Agent

The weakest reducing agent is the one with the most positive electrode potential. \( I^- \) has the highest positive value \( +0.54 \text{ V} \), making it the weakest reducing agent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Electrode Potential
The standard electrode potential, often denoted as \(E^0\), is a measure used to predict the tendency of a chemical species to be reduced, or gain electrons, in an electrochemical cell. This value is determined under standard conditions, which include a temperature of 25°C, a 1 M concentration for each ion participating in the reaction, and a pressure of 1 atm for gaseous reactants.
Standard electrode potentials are crucial for comparing the energetics of different redox reactions.
  • A more positive \(E^0\) indicates a greater tendency to gain electrons and undergo reduction.
  • Conversely, a more negative \(E^0\) suggests a stronger tendency to lose electrons, acting as a reducing agent.
By consulting a table of standard electrode potentials, one can determine the feasibility and spontaneity of a reaction in an electrochemical cell. For instance, if we look at the potentials provided, we can see that the order of preference to act as reducing agents is reflected by their \(E^0\) values.
Oxidation-Reduction Reactions
Oxidation-reduction reactions, or redox reactions, are chemical processes involving the transfer of electrons between two species. These reactions consist of two half-reactions: oxidation and reduction.
The term "oxidation" refers to the loss of electrons, while "reduction" refers to the gain of electrons. These half-reactions occur simultaneously, as the electrons lost by one reactant are gained by another. This interplay is essential for the conduction of electricity in electrochemical cells.
  • An oxidizing agent accepts electrons and is reduced.
  • A reducing agent donates electrons and is oxidized.
In our example, the reducing agents \( \mathrm{Sn}^{2+} \), \( \mathrm{Cu} \), and \( \mathrm{I}^{-} \) undergo different half-reactions. The standard electrode potential values for these agents help us determine their place in a redox reaction's sequence.
Strength of Reducing Agents
The strength of a reducing agent is indicated by its ability to lose electrons easily. Reducing agents with more negative standard electrode potentials are stronger because they release electrons readily, enhancing their oxidative ability.
To identify the strongest reducing agent among the given examples, we compare the \(E^0\) values:
  • \( \mathrm{Sn}^{2+} \) has an \(E^0\) of \(-0.14\text{ V}\), indicating a strong tendency to donate electrons.
  • \( \mathrm{Cu} \) possesses an \(E^0\) of \(+0.34\text{ V}\).
  • \( \mathrm{I}^{-} \) has the most positive \(E^0\) at \(+0.54\text{ V}\), making it the weakest reducing agent.
Thus, \( \mathrm{Sn}^{2+} \) is the strongest reducing agent in this group. Recognizing these strengths is important for predicting reaction outcomes in electrochemical processes.

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Most popular questions from this chapter

A voltaic cell has an iron rod in \(0.30 M\) iron(III) chloride solution for the cathode and a zinc rod in \(0.40 M\) zinc sulfate solution for the anode. The half-cells are connected by a salt bridge. Write the notation for this cell.

What would you expect to happen when chlorine gas, \(\mathrm{Cl}_{2}\), at 1 atm pressure is bubbled into a solution containing \(1.0 M \mathrm{~F}^{-}\) and \(1.0 \mathrm{M} \mathrm{Br}^{-}\) at \(25^{\circ} \mathrm{C}\) ? Write a balanced equation for the reaction that occurs.

Describe the difference between a voltaic cell and an electrolytic cell.

Determine the emf of the following cell. $$ \mathrm{Pt}\left|\mathrm{H}_{2}(1.0 \mathrm{~atm})\right| \mathrm{H}^{+}(1.0 \mathrm{M}) \| \mathrm{Cl}^{-}(1.0 \mathrm{M}), \mathrm{AgCl}(s) \mid \mathrm{Ag} $$ The cathode is essentially a silver electrode, \(\mathrm{Ag}^{+}(a q) \mid \mathrm{Ag}\). However, the cathode solution is saturated with silver chloride, so that the silver-ion concentration is determined by the solubility product of \(\mathrm{AgCl}\left(K_{s p}=1.8 \times 10^{-10}\right)\).

Balance the following oxidation-reduction equations. The reactions occur in acidic solution. a. \(\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-}+\mathrm{C}_{2} \mathrm{O}_{4}^{2-} \longrightarrow \mathrm{Cr}^{3+}+\mathrm{CO}_{2}\) b. \(\mathrm{Cu}+\mathrm{NO}_{3}^{-} \longrightarrow \mathrm{Cu}^{2+}+\mathrm{NO}\) c. \(\mathrm{MnO}_{2}+\mathrm{HNO}_{2} \longrightarrow \mathrm{Mn}^{2+}+\mathrm{NO}_{3}^{-}\) d. \(\mathrm{PbO}_{2}+\mathrm{Mn}^{2+}+\mathrm{SO}_{4}{ }^{2-} \longrightarrow \mathrm{PbSO}_{4}+\mathrm{MnO}_{4}^{-}\) e. \(\mathrm{HNO}_{2}+\mathrm{Cr}_{2} \mathrm{O}_{7}^{2-} \longrightarrow \mathrm{Cr}^{3+}+\mathrm{NO}_{3}^{-}\)

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