Chapter 20: Problem 104
Determine the emf of the following cell. $$ \mathrm{Pt}\left|\mathrm{H}_{2}(1.0 \mathrm{~atm})\right| \mathrm{H}^{+}(1.0 \mathrm{M}) \| \mathrm{Cl}^{-}(1.0 \mathrm{M}), \mathrm{AgCl}(s) \mid \mathrm{Ag} $$ The cathode is essentially a silver electrode, \(\mathrm{Ag}^{+}(a q) \mid \mathrm{Ag}\). However, the cathode solution is saturated with silver chloride, so that the silver-ion concentration is determined by the solubility product of \(\mathrm{AgCl}\left(K_{s p}=1.8 \times 10^{-10}\right)\).
Short Answer
Step by step solution
- Write down the cell reaction
- Calculate the standard potential of each half-cell
- Determine ion concentrations using solubility product
- Calculate the cell potential using the Nernst equation
- Solve for the cell potential
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electrochemical Cell
Nernst Equation
- \( E \) is the cell potential under non-standard conditions,
- \( E^0 \) is the standard cell potential,
- \( R \) is the universal gas constant (8.314 J/mol·K),
- \( T \) is the temperature in Kelvin,
- \( n \) is the number of moles of electrons transferred,
- \( F \) is Faraday's constant (96485 C/mol),
- \( Q \) is the reaction quotient.