/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 11 Sulfuryl chloride decomposes acc... [FREE SOLUTION] | 91Ó°ÊÓ

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Sulfuryl chloride decomposes according to the equation \(\mathrm{SO}_{2} \mathrm{Cl}_{2}(g) \rightarrow \mathrm{SO}_{2}(g)+\mathrm{Cl}_{2}(g)\) Using the following initial-rate data, determine the order of the reaction with respect to \(\mathrm{SO}_{2} \mathrm{Cl}_{2}:\) \begin{tabular}{cc} \hline & \multicolumn{2}{l} { Initial rate of reaction of } \\ {\(\left[\mathrm{SO}_{2} \mathrm{Cl}_{2}\right]_{0} / \mathrm{mol} \cdot \mathrm{L}^{-1}\)} & \(\mathrm{SO}_{2} \mathrm{Cl}_{2}(g) / \mathrm{mol} \cdot \mathrm{L}^{-1} \cdot \mathrm{s}^{-1}\) \\ \hline \(0.10\) & \(2.2 \times 10^{-6}\) \\ \(0.20\) & \(4.4 \times 10^{-6}\) \\ \(0.30\) & \(6.6 \times 10^{-6}\) \\ \(0.40\) & \(8.8 \times 10^{-6}\) \\ \hline \end{tabular} Calculate the value of the rate constant.

Short Answer

Expert verified
The reaction is first-order with a rate constant of \( k = 2.2 \times 10^{-5} \text{ s}^{-1} \).

Step by step solution

01

Identify the Rate Law

For the reaction \( \mathrm{SO}_{2} \mathrm{Cl}_{2}(g) \rightarrow \mathrm{SO}_{2}(g) + \mathrm{Cl}_{2}(g) \), the rate law can be expressed as \( \text{Rate} = k [\mathrm{SO}_{2} \mathrm{Cl}_{2}]^n \), where \( n \) is the order of the reaction with respect to \( \mathrm{SO}_{2} \mathrm{Cl}_{2} \).
02

Determine the Order of Reaction

Looking at the data, as the concentration of \( \mathrm{SO}_{2} \mathrm{Cl}_{2} \) doubles or triples, the rate also doubles or triples respectively. This indicates a first-order reaction since the rate is directly proportional to the concentration.
03

Write the Rate Equation for First-Order

Since the reaction is first-order, the rate equation will be \( \text{Rate} = k [\mathrm{SO}_{2} \mathrm{Cl}_{2}] \).
04

Calculate the Rate Constant (k)

Using the initial rate and concentration from one of the experiments, such as the first, we use \( k = \frac{\text{Rate}}{[\mathrm{SO}_{2} \mathrm{Cl}_{2}]} = \frac{2.2 \times 10^{-6} \text{ mol L}^{-1} \text{ s}^{-1}}{0.10 \text{ mol L}^{-1}} = 2.2 \times 10^{-5} \text{ s}^{-1} \).
05

Verify Consistency

Repeat the calculation of \( k \) for other data points to ensure consistency. For \( 0.20 \text{ mol L}^{-1} \), \( k = \frac{4.4 \times 10^{-6}}{0.20} = 2.2 \times 10^{-5} \text{ s}^{-1} \), which confirms the consistency of the calculation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Reaction Order
Reaction order is a fundamental concept in chemical kinetics. It describes how the rate of a reaction depends on the concentration of the reactants. More specifically, it indicates how the concentration affects the speed at which the reactants disappear and the products are formed. In a rate law, the reaction order is determined by the exponent to which the concentration of a reactant is raised.
For example, in the rate law expression for sulfuryl chloride decomposition, \( \text{Rate} = k [\mathrm{SO}_{2} \mathrm{Cl}_{2}]^n \), the term \( n \) represents the reaction order. If the order is 1, it means the reaction is first-order with respect to sulfuryl chloride. The data given demonstrates this: as the concentration of \( \mathrm{SO}_{2} \mathrm{Cl}_{2} \) doubles, the rate also doubles, which is a classic indicator of first-order kinetics.
In summary:
  • First-order: Rate increases linearly with concentration.
  • Second-order: Rate increases more than proportionally with concentration.
Understanding the reaction order is crucial for predicting how changes in concentration can affect reaction rates.
What is the Rate Constant?
The rate constant, denoted as \( k \), is a crucial parameter in the rate law equation, providing the proportionality factor that links the reaction rate to the concentrations of the reactants. It is a measure of how fast a reaction proceeds and is constant for a given reaction at a certain temperature.
In sulfuryl chloride decomposition, the rate constant informs us about the intrinsic speed of the reaction. The rate law equation \( \text{Rate} = k [\mathrm{SO}_{2} \mathrm{Cl}_{2}] \) shows that knowing the concentration of sulfuryl chloride and the reaction order allows us to calculate \( k \).
The value of \( k \) can vary significantly between different reactions and is dependent on several factors:
  • Temperature: \( k \) typically increases with temperature.
  • Presence of a catalyst: Catalysts can increase \( k \) by providing an alternative pathway with a lower activation energy.
In the given exercise, calculating \( k = 2.2 \times 10^{-5} \text{ s}^{-1} \) confirms the first-order nature of the reaction and provides a measure to compare with other similar reactions.
Sulfuryl Chloride Decomposition and Its Dynamics
Sulfuryl chloride \( (\mathrm{SO}_{2} \mathrm{Cl}_{2}) \) is a chemical compound that can decompose into sulfur dioxide \((\mathrm{SO}_{2})\) and chlorine \((\mathrm{Cl}_{2})\) gases. This decomposition is a straightforward reaction, well-suited for studying basic principles of reaction kinetics.
Sulfuryl chloride decomposition is represented by the reaction \( \mathrm{SO}_{2} \mathrm{Cl}_{2}(g) \rightarrow \mathrm{SO}_{2}(g) + \mathrm{Cl}_{2}(g) \). The process is especially interesting because it provides a clear example of a gas-phase reaction where both the reactant and products are gases, simplifying the analysis of concentration changes.
This reaction also sheds light on:
  • The significance of reaction order and its determination through experimental data.
  • The way the rate constant, \( k \), reflects the reaction's behavior under varying conditions.
Sulfuryl chloride decomposition serves as a fundamental case study in chemical kinetics, illustrating the key concepts and mathematical relationships that govern reaction rates.

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The following initial-rate data were obtained for the decomposition of \(\mathrm{N}_{2} \mathrm{O}_{3}(g)\) as described by the equation $$ \mathrm{N}_{2} \mathrm{O}_{3}(g) \rightarrow \mathrm{NO}(g)+\mathrm{NO}_{2}(g) $$ \begin{tabular}{ccc} \hline Run & Initial pressure of \(P_{\mathrm{N}_{2} \mathrm{O}_{3}} /\) Torr & Initial rate of formation of \(\mathrm{NO}_{2}(g) /\) Torr \(\cdot \mathrm{s}^{-1}\) \\ \hline 1 & \(0.91\) & \(5.5\) \\ 2 & \(1.4\) & \(8.4\) \\ 3 & \(2.1\) & 13 \\ \hline \end{tabular} Determine the rate law for the reaction, expressed in terms of \(P_{\mathrm{N}_{2} \mathrm{o}_{3}}\) rather than \(\left[\mathrm{N}_{2} \mathrm{O}_{3}\right] .\) Calculate the value of the rate constant for the reaction.

How does doubling the concentration of a reactant change the rate of a reaction that is first order in that reactant? How does it change the rate of a reaction that is second order in that reactant?

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