/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 The value of \(\left[\mathrm{H}^... [FREE SOLUTION] | 91Ó°ÊÓ

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The value of \(\left[\mathrm{H}^{+}\right]\) in the reaction described by the equation $$ \begin{aligned} \mathrm{CH}_{3} \mathrm{OH}(a q)+\mathrm{H}^{+}(a q)+\mathrm{Cl}^{-}(a q) & \rightarrow \\ \mathrm{CH}_{3} \mathrm{Cl}(a q)+\mathrm{H}_{2} \mathrm{O}(l) \end{aligned} $$ was measured over a period of time: \begin{tabular}{cc} \hline \(\boldsymbol{t} / \mathrm{s}\) & {\(\left[\mathbf{H}^{+}\right] / \mathbf{M}\)} \\ \hline 0 & \(2.12\) \\ 31 & \(1.90\) \\ 61 & \(1.78\) \\ 121 & \(1.61\) \\ \hline \end{tabular} Find the average rate of disappearance of \(\mathrm{H}^{+}(a q)\) for the time interval between each measurement. What is the average rate of disappearance of \(\mathrm{CH}_{3} \mathrm{OH}(a q)\) and what is the average rate of appearance of \(\mathrm{CH}_{3} \mathrm{Cl}(a q)\) for the same time intervals?

Short Answer

Expert verified
The rates for both \( \mathrm{CH}_3\mathrm{OH} \) disappearance and \( \mathrm{CH}_3\mathrm{Cl} \) appearance are equal to the \( \mathrm{H}^+ \) disappearance rates for each interval. For example, at \( t = 0\) to \( t = 31 s \), the rate is \(-0.0071\ \mathrm{M/s}\) for \( \mathrm{CH}_3\mathrm{OH} \) and \(0.0071\ \mathrm{M/s} \) for \( \mathrm{CH}_3\mathrm{Cl} \).

Step by step solution

01

Calculate the Change in Concentration of H+

Calculate the change in concentration of \( \mathrm{H}^{+}\) between each time interval. This is done by subtracting the concentration at the end of the interval from the concentration at the beginning of the interval: - From \( t = 0 \) to \( t = 31 s \): \( 1.90 - 2.12 = -0.22 \)- From \( t = 31 \) to \( t = 61 s \): \( 1.78 - 1.90 = -0.12 \)- From \( t = 61 \) to \( t = 121 s \): \( 1.61 - 1.78 = -0.17 \)
02

Calculate the Average Rate of Disappearance of H+

The average rate of disappearance of \( \mathrm{H}^{+} \) is given by the change in concentration divided by the change in time for each interval:- From \( t = 0 \) to \( t = 31 s \): \( \frac{-0.22}{31} = -0.0071 \ \mathrm{M/s} \)- From \( t = 31 \) to \( t = 61 s \): \( \frac{-0.12}{30} = -0.0040 \ \mathrm{M/s} \)- From \( t = 61 \) to \( t = 121 s \): \( \frac{-0.17}{60} = -0.0028 \ \mathrm{M/s} \)
03

Relate Rates of Reactants and Products

The reaction stoichiometry shows a 1:1:1 ratio between \(\mathrm{CH}_3\mathrm{OH}(aq)\), \(\mathrm{H}^{+}(aq)\), and \(\mathrm{CH}_3\mathrm{Cl}(aq)\). Therefore, the rate of disappearance of \( \mathrm{CH}_3\mathrm{OH}(aq) \) is the same as \( \mathrm{H}^{+}(aq) \), and the rate of appearance of \( \mathrm{CH}_3\mathrm{Cl}(aq) \) is the same as the disappearance of \( \mathrm{H}^{+}(aq) \).
04

Calculate Average Rates for CH3OH and CH3Cl

Since the rates are equal by stoichiometry:- For \( t = 0 \) to \( t = 31 s \): - Disappearance of \( \mathrm{CH}_3\mathrm{OH}(aq)\): \( -0.0071 \ \mathrm{M/s} \) - Appearance of \( \mathrm{CH}_3\mathrm{Cl}(aq)\): \( -(-0.0071) = 0.0071 \ \mathrm{M/s} \)- For \( t = 31 \) to \( t = 61 s \): - Disappearance of \( \mathrm{CH}_3\mathrm{OH}(aq)\): \( -0.0040 \ \mathrm{M/s} \) - Appearance of \( \mathrm{CH}_3\mathrm{Cl}(aq)\): \( -(-0.0040) = 0.0040 \ \mathrm{M/s} \)- For \( t = 61 \) to \( t = 121 s \): - Disappearance of \( \mathrm{CH}_3\mathrm{OH}(aq)\): \( -0.0028 \ \mathrm{M/s} \) - Appearance of \( \mathrm{CH}_3\mathrm{Cl}(aq)\): \( -(-0.0028) = 0.0028 \ \mathrm{M/s} \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reaction Stoichiometry
In chemistry, reaction stoichiometry is all about understanding the proportions in which reactants and products participate in a chemical reaction. It's like a recipe, where each ingredient must be used in just the right amount to make the perfect product.
For the reaction at hand, given by the equation: \[ \mathrm{CH}_3\mathrm{OH}(aq) + \mathrm{H}^{+}(aq) + \mathrm{Cl}^{-}(aq) \rightarrow \mathrm{CH}_3\mathrm{Cl}(aq) + \mathrm{H}_2\mathrm{O}(l) \] The stoichiometry is straightforward; there’s a 1:1:1 ratio between \(\mathrm{CH}_3\mathrm{OH}(aq)\), \(\mathrm{H}^{+}(aq)\), and \(\mathrm{CH}_3\mathrm{Cl}(aq)\).
This means for every molecule of \(\mathrm{CH}_3\mathrm{OH}\) that reacts, one \(\mathrm{H}^+\) and one \(\mathrm{Cl}^-\) are consumed, resulting in one molecule of \(\mathrm{CH}_3\mathrm{Cl}\) formed.
This is useful information! It tells us that the rate of disappearance of reactants \(\mathrm{CH}_3\mathrm{OH}\) and \(\mathrm{H}^+\) is equal, as is the rate of appearance of the product \(\mathrm{CH}_3\mathrm{Cl}\). Thus, by observing the change in concentration of \(\mathrm{H}^+\), we can directly infer the rates of the entire reaction.
Average Rate of Reaction
The average rate of reaction is a measure of how quickly reactants are consumed or products are formed over time. In simpler terms, it tells how fast or slow a reaction is occurring.
For the given reaction, we focus on the average rate of disappearance of \(\mathrm{H}^{+}(aq)\) due to its role in the equation:
  • From \( t = 0 \) to \( t = 31 \text{ s} \), concentration changes by \(-0.22 \text{ M} \), giving an average rate of \(-0.0071 \text{ M/s}\).
  • From \( t = 31 \) to \( t = 61 \text{ s} \), the change is \(-0.12 \text{ M} \), with a rate of \(-0.0040 \text{ M/s}\).
  • From \( t = 61 \) to \( t = 121 \text{ s} \), the concentration changes by \(-0.17 \text{ M} \), leading to a rate of \(-0.0028 \text{ M/s}\).
These calculations show that the reaction rate decreases over time, meaning the reaction slows as it progresses. This information is crucial for controlling reactions in a lab or industrial setting since it helps determine the best conditions for an efficient reaction.
Concentration Change
Concentration change is the key to understanding reaction progress. In chemical reactions, the concentration of reactants typically decreases over time as they are consumed, while the concentration of products increases as they are formed.
 
To measure these changes, one needs to monitor the concentration of at least one component over time. In our case, it's \(\mathrm{H}^{+}(aq)\) whose concentration is tracked at different times:
  • Initially, the concentration of \(\mathrm{H}^{+}\) is high at \(2.12 \text{ M}\) and decreases with time, indicating its consumption during the reaction.
  • The changes from \(2.12 \text{ M to 1.90 \text{ M}, 1.78 \text{ M}, \) and \(1.61 \text{ M}\) highlight the utilization of \(\mathrm{H}^{+}\) in the reaction process.
Concentration change helps us understand not just when a reaction is proceeding but how fast it goes during various stages. Keeping track of these changes aids scientists and engineers in optimizing reactions for various applications, from pharmaceutical manufacturing to food processing. By grasping concentration changes, one can develop strategies to maximize product yield efficiently.

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