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Using solubility rules, predict the solubility in water of the following ionic compounds. (a) \(\mathrm{PbS}\) (b) \(\mathrm{AgNO}_{3}\) (c) \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) (d) \(\mathrm{CaI}_{2}\)

Short Answer

Expert verified
(a) Insoluble; (b) Soluble; (c) Soluble; (d) Soluble.

Step by step solution

01

Understanding solubility rules

Before predicting solubility, recall these general solubility rules: Most nitrates (NO鈧冣伝), acetates (CH鈧僀OO鈦), and alkali metal salts are soluble. Most sulfides (S虏鈦) and carbonates (CO鈧兟测伝) are insoluble unless paired with alkali metals or ammonium. Most chlorides (Cl鈦), bromides (Br鈦), and iodides (I鈦) are soluble except those of silver, lead, and mercury.
02

Analysis of compound (a) - PbS

Lead(II) sulfide is a sulfide compound. According to the solubility rules, most sulfides are insoluble, and lead is not an exception to this rule. Therefore, PbS is insoluble in water.
03

Analysis of compound (b) - AgNO鈧

Silver nitrate is a nitrate compound. Nitrates are generally soluble in water, and silver nitrate specifically follows this rule. Thus, AgNO鈧 is soluble in water.
04

Analysis of compound (c) - Na鈧侰O鈧

Sodium carbonate contains the carbonate ion, which is usually insoluble. However, sodium is an alkali metal; compounds of alkali metals are exceptions and are generally soluble. Therefore, Na鈧侰O鈧 is soluble in water.
05

Analysis of compound (d) - CaI鈧

Calcium iodide contains iodide ions, which are typically soluble. Calcium is not part of the exceptions with iodides, as exceptions typically include lead, silver, and mercury. Therefore, CaI鈧 is soluble in water.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic Compounds
Ionic compounds are formed when positive and negative ions come together and bond to create a neutral entity. These compounds are often comprised of metal and non-metal ions. The metal gives up electrons to become a positive ion, while the non-metal gains electrons to become a negative ion. This transfer of electrons creates the ionic bond.
For instance, sodium carbonate (\( \text{Na}_2\text{CO}_3 \)) and lead sulfide (\( \text{PbS} \)) are both examples of ionic compounds as they consist of metal cations (positive ions) and anions (negative ions).
Ionic compounds generally form crystalline solids with high melting points and are known for conducting electricity when dissolved in water.
Solubility in Water
Solubility in water refers to the ability of a substance to dissolve in water. This depends on the attractive forces between the ions in the compound and those between the ions and the water molecules.
When ionic compounds dissolve, they dissociate into their individual ions. For example, when sodium chloride dissolves in water, it splits into sodium and chloride ions.
  • Soluble compounds easily dissolve, while insoluble ones do not.
  • Understanding solubility in water is key for predicting whether a compound will dissolve.
This process is heavily influenced by the intrinsic solubility rules of different ions.
Nitrates and Carbonates Solubility
Nitrates, such as silver nitrate (\( \text{AgNO}_3 \)), are typically soluble in water. This is because nitrate ions (\( \text{NO}_3^- \)) can interact favorably with water molecules, facilitating easy dissolution.
On the contrary, carbonates (\( \text{CO}_3^{2-} \)) are usually insoluble, except when combined with alkali metals or ammonium ions. For example, sodium carbonate (\( \text{Na}_2\text{CO}_3 \)) is soluble because sodium is an alkali metal, which provides an exception to the general rule of insolubility for carbonates.
  • Most nitrates dissolve readily in water without exception.
  • Most carbonates need ammonia or alkali metals to dissolve.
Chlorides, Bromides, and Iodides Solubility
These halides are generally soluble, meaning compounds like calcium iodide (\( \text{CaI}_2 \)) dissolve in water. However, exceptions exist, mainly involving silver, lead, and mercury. For example, silver chloride, lead chloride, and mercury iodide are insoluble.
  • Chlorides, bromides, and iodides dissolve easily unless paired with specific metals.
  • Understanding these exceptions helps in predicting solubility accurately.

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Most popular questions from this chapter

Mercury(II) nitrate is treated with hydrogen sulfide, \(\mathrm{H}_{2} \mathrm{~S},\) forming a precipitate and a solution. Write the molecular equation and the net ionic equation for the reaction. An acid is formed; is it strong or weak? Name each of the products. If \(81.15 \mathrm{~g}\) of mercury(II) nitrate and \(8.52 \mathrm{~g}\) of hydrogen sulfide are mixed in \(550.0 \mathrm{~g}\) of water to form \(58.16 \mathrm{~g}\) of precipitate, what is the mass of the solution after the reaction?

A soluble iodide was dissolved in water. Then an excess of silver nitrate, \(\mathrm{AgNO}_{3}\), was added to precipitate all of the iodide ion as silver iodide, AgI. If \(1.545 \mathrm{~g}\) of the soluble iodide gave \(2.185 \mathrm{~g}\) of silver iodide, how many grams of iodine are in the sample of soluble iodide? What is the mass percentage of iodine, I, in the compound?

A solution contains \(6.00 \%\) (by mass) \(\mathrm{NaBr}\) (sodium bromide). The density of the solution is \(1.046 \mathrm{~g} / \mathrm{cm}^{3} .\) What is the molarity of \(\mathrm{NaBr}\) ?

Aluminum metal reacts with perchloric acid to produce hydrogen gas and a solution of aluminum perchlorate. Write the molecular equation for this reaction. Then write the corresponding net ionic equation.

Calculate the concentrations of each ion present in a solution that results from mixing \(50.0 \mathrm{~mL}\) of a \(0.20 \mathrm{M}\) \(\mathrm{NaClO}_{3}(a q)\) solution with \(25.0 \mathrm{~mL}\) of a \(0.20 \mathrm{M} \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)\) solution. Assume that the volumes are additive.

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