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If one mole of the following compounds were each placed into separate beakers containing the same amount of water, rank the \(\mathrm{Cl}^{-}(a q)\) concentrations from highest to lowest (some may be equivalent): \(\mathrm{KCl}, \mathrm{AlCl}_{3}, \mathrm{PbCl}_{2}, \mathrm{NaCl}\) \(\mathrm{HCl}, \mathrm{NH}_{3}, \mathrm{KOH},\) and \(\mathrm{HCN}\)

Short Answer

Expert verified
The ranking is: \(\mathrm{AlCl}_3 > \mathrm{KCl} \approx \mathrm{NaCl} \approx \mathrm{HCl} > \mathrm{PbCl}_2\).

Step by step solution

01

Identifying Ionic Substances

To determine the chloride ion concentrations, first identify which of these compounds will dissolve in water to provide chloride ions. The compounds are: \(\mathrm{KCl}, \mathrm{AlCl}_3, \mathrm{PbCl}_2, \mathrm{NaCl}, \mathrm{HCl}\) that contain chloride ions. \(\mathrm{NH}_3, \mathrm{KOH},\) and \(\mathrm{HCN}\) do not contain chloride ions.
02

Determining Dissociation in Water

Evaluate the dissociation of each chloride-containing compound in water. \(\mathrm{KCl}, \mathrm{NaCl}, \mathrm{AlCl}_3,\) and \(\mathrm{HCl}\) fully dissociate in water, while \(\mathrm{PbCl}_2\) is only partially soluble.
03

Calculating Chloride Ion Contribution

Calculate the number of chloride ions each compound contributes upon full dissociation:\(\mathrm{KCl} \to \mathrm{K}^+ + \mathrm{Cl}^-\) gives 1 \(\mathrm{Cl}^-\), \(\mathrm{NaCl} \to \mathrm{Na}^+ + \mathrm{Cl}^-\) gives 1 \(\mathrm{Cl}^-\), \(\mathrm{AlCl}_3 \to \mathrm{Al}^{3+} + 3\mathrm{Cl}^-\) gives 3 \(\mathrm{Cl}^-\), \(\mathrm{HCl} \to \mathrm{H}^+ + \mathrm{Cl}^-\) gives 1 \(\mathrm{Cl}^-\), and \(\mathrm{PbCl}_2\) when it dissolves yields \(\mathrm{Pb}^{2+} + 2\mathrm{Cl}^-\) but due to its low solubility, less \(\mathrm{Cl}^-\) is available.
04

Ranking the Concentrations

Based on the dissociation process, the number of chloride ions each compound provides can be ranked as follows: \(\mathrm{AlCl}_3 > \mathrm{KCl} \approx \mathrm{NaCl} \approx \mathrm{HCl} > \mathrm{PbCl}_2\). The highest concentration of chloride ions comes from \(\mathrm{AlCl}_3\) since it provides 3 moles of \(\mathrm{Cl}^-\) per mole, whereas \(\mathrm{PbCl}_2\)'s solubility limits its chloride ion concentration.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic Dissociation
Ionic dissociation is the process by which compounds separate into ions when dissolved in water. This occurs because the ionic bonds are broken by the polar nature of water molecules, allowing the compound to dissolve and exist as individual ions in solution.
When we consider a compound like KCl (potassium chloride), it dissociates into potassium ions (\( \mathrm{K}^+ \)) and chloride ions (\( \mathrm{Cl}^- \)) when placed in water. Each mole of KCl will yield one mole of chloride ions due to its simple 1:1 ratio.
Similarly, when NaCl (sodium chloride) is dissolved, it also separates into \( \mathrm{Na}^+ \) and \( \mathrm{Cl}^- \) ions. Compounds like AlCl鈧 (aluminum chloride) are interesting because they produce three moles of chloride ions for each mole of the compound that dissociates, due to its formula of one aluminum ion to three chloride ions.
However, some compounds, such as PbCl鈧 (lead(II) chloride), do not fully dissolve. While they will dissociate, they have low solubility in water, meaning not all of the compound dissolves, resulting in fewer ions available in solution.
Solubility
Solubility refers to a compound's ability to dissolve in a solvent, such as water. It determines how much of the compound dissolves to form a solution. A compound's solubility is impacted by temperature, pressure, and the nature of both the solute and solvent.
Highly soluble compounds like KCl, NaCl, and AlCl鈧 readily dissolve in water, fully dissociating into their respective ions. This means they have a high solubility, allowing them to contribute greatly to the chloride ion concentration in a solution.
  • KCl, NaCl, and AlCl鈧 fully dissociate, contributing significantly to the chloride ion concentration.
  • HCl (hydrochloric acid), although sometimes not considered a typical salt, ionizes completely in water to release hydrogen and chloride ions, adding to the chloride ion pool.
On the other hand, PbCl鈧 has low solubility in water. Even though it can release two chloride ions upon dissociation per mole, its limited dissolution means it contributes fewer chloride ions compared to the others.
Chemical Compounds
Chemical compounds are substances formed from two or more elements bonded together in fixed proportions. The compounds discussed here include both ionic compounds, like KCl and NaCl, and covalent ones, like NH鈧 (ammonia).
An ionic compound such as AlCl鈧 has more intricate chemical behavior due to its crystalline structure and the presence of metal and non-metal ions. The chemical composition determines how these compounds interact with water, leading to ionic dissociation.
On the contrary, NH鈧, and HCN do not provide chloride ions as they lack the Cl鈦 group in their structure. NH鈧 is a covalent compound that doesn鈥檛 produce ions in the same manner and primarily affects the solution's properties through interactions, not by contributing to ion concentration. Understanding these interactions is key to predicting the outcomes when different compounds are mixed with water.
Aqueous Solutions
An aqueous solution is one in which water acts as the solvent. This environment facilitates the dissociation of many ionic compounds, allowing chemical reactions to occur. Water is particularly effective here due to its polarity, meaning it has distinct partial positive and negative charges that attract ions.
When compounds like NaCl or HCl are added to water, they break apart into their component ions, each ion interacting with water molecules. This makes the ions available for potential chemical reactions.
  • Water's exceptional ability to solvate ions is what allows solutions to conduct electricity could bring significant industrial and laboratory applications.
  • In contrast, compounds that do not dissociate, like NH鈧, remain mostly in their molecular form, performing differently in an aqueous environment.
Through aqueous solutions, the study of ionic compounds, dissociation, and solubility becomes more tangible, enabling a deeper understanding of chemical processes.

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Most popular questions from this chapter

Bone was dissolved in hydrochloric acid, giving 50.0 \(\mathrm{mL}\) of solution containing calcium chloride, \(\mathrm{CaCl}_{2}\). To precipitate the calcium ion from the resulting solution, an excess of potassium oxalate was added. The precipitate of calcium oxalate, \(\mathrm{CaC}_{2} \mathrm{O}_{4}\), weighed \(1.437 \mathrm{~g}\). What was the molarity of \(\mathrm{CaCl}_{2}\) in the solution?

A barium mineral was dissolved in hydrochloric acid to give a solution of barium ion. An excess of potassium sulfate was added to \(50.0 \mathrm{~mL}\) of the solution, and 1.128 \(\mathrm{g}\) of barium sulfate precipitate formed. Assume that the original solution was barium chloride. What was the molarity of \(\mathrm{BaCl}_{2}\) in this solution?

A solution of hydrogen peroxide, \(\mathrm{H}_{2} \mathrm{O}_{2}\), is titrated with a solution of potassium permanganate, \(\mathrm{KMnO}_{4}\). The reaction is $$ \begin{array}{c} 5 \mathrm{H}_{2} \mathrm{O}_{2}(a q)+2 \mathrm{KMnO}_{4}(a q)+3 \mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow \\ 5 \mathrm{O}_{2}(g)+2 \mathrm{MnSO}_{4}(a q)+\mathrm{K}_{2} \mathrm{SO}_{4}(a q)+8 \mathrm{H}_{2} \mathrm{O}(l) \end{array} $$ It requires \(51.7 \mathrm{~mL}\) of \(0.145 \mathrm{M} \mathrm{KMnO}_{4}\) to titrate \(20.0 \mathrm{~g}\) of the solution of hydrogen peroxide. What is the mass percentage of \(\mathrm{H}_{2} \mathrm{O}_{2}\) in the solution?

A chemist added an excess of sodium sulfate to a solution of a soluble barium compound to precipitate all of the barium ion as barium sulfate, \(\mathrm{BaSO}_{4}\). How many grams of barium ion are in a 458 -mg sample of the barium compound if a solution of the sample gave \(513 \mathrm{mg} \mathrm{BaSO}_{4}\) precipitate? What is the mass percentage of barium in the compound?

Iron(III) chloride can be prepared by reacting iron metal with chlorine. What is the balanced equation for this reaction? How many grams of iron are required to make \(3.00 \mathrm{~L}\) of aqueous solution containing \(9.00 \%\) iron(III) chloride by mass? The density of the solution is \(1.067 \mathrm{~g} / \mathrm{mL}\).

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