Chapter 16: Problem 12
Write an equation for the acid-base equilibrium of: (a) Pyrrolidine and water (b) Pyridine and water Label each species in the equilibrium as either an acid or a base.
Short Answer
Expert verified
Pyrrolidine with water forms pyrrolidinium ion and hydroxide; pyridine forms pyridinium ion and hydroxide.
Step by step solution
01
Identify the Species Involved
First, identify the chemical species involved in both acid-base equilibria. For pyrrolidine and water: pyrrolidine (\(\text{C}_4\text{H}_9\text{NH}\)) and water (\(\text{H}_2\text{O}\)). For pyridine and water: pyridine (\(\text{C}_5\text{H}_5\text{N}\)) and water (\(\text{H}_2\text{O}\)).
02
Understanding the Acid-Base Behavior
Understand how each species acts in the presence of water. Pyrrolidine is a secondary amine and acts as a base, accepting a proton. Water acts as an acid, donating a proton. Pyridine also acts as a base by accepting a proton, while water again acts as an acid.
03
Write the Equilibrium Equation for Pyrrolidine
Write the equation for the reaction between pyrrolidine and water: \[ \text{C}_4\text{H}_9\text{NH} + \text{H}_2\text{O} \rightleftharpoons \text{C}_4\text{H}_9\text{NH}_2^+ + \text{OH}^- \]Here, pyrrolidine (\(\text{C}_4\text{H}_9\text{NH}\)) acts as the base, water (\(\text{H}_2\text{O}\)) as the acid, pyrrolidinium ion (\(\text{C}_4\text{H}_9\text{NH}_2^+\)) as the conjugate acid, and hydroxide ion (\(\text{OH}^-\)) as the conjugate base.
04
Write the Equilibrium Equation for Pyridine
Write the equation for the reaction between pyridine and water: \[ \text{C}_5\text{H}_5\text{N} + \text{H}_2\text{O} \rightleftharpoons \text{C}_5\text{H}_5\text{NH}^+ + \text{OH}^- \]Here, pyridine (\(\text{C}_5\text{H}_5\text{N}\)) acts as the base, water (\(\text{H}_2\text{O}\)) as the acid, pyridinium ion (\(\text{C}_5\text{H}_5\text{NH}^+\)) as the conjugate acid, and hydroxide ion (\(\text{OH}^-\)) as the conjugate base.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Pyrrolidine in Acid-Base Equilibrium
Pyrrolidine is a cyclic secondary amine with the molecular formula \(\text{C}_4\text{H}_9\text{NH}\). It stands out due to its basic nature, as it can accept a proton when dissolved in water. This reaction forms the pyrrolidinium ion \(\text{C}_4\text{H}_9\text{NH}_2^+\). Understanding this behavior is crucial for predicting the outcome of reactions involving pyrrolidine. In its equilibrium with water, pyrrolidine acts as a base and water acts as an acid.
This process lays the foundation for the equilibrium equation:
This process lays the foundation for the equilibrium equation:
- Basic Pyrrolidine: \(\text{C}_4\text{H}_9\text{NH} + \text{H}_2\text{O} \rightleftharpoons \text{C}_4\text{H}_9\text{NH}_2^+ + \text{OH}^- \)
Pyridine: A Basic Compound
Pyridine, with the formula \(\text{C}_5\text{H}_5\text{N}\), is an important compound in the chemistry of heterocyclic amines. It features a nitrogen atom within an aromatic ring structure, significantly contributing to its basic characteristics. Pyridine interacts with water similarly to many bases by accepting a proton from water to form a pyridinium ion \(\text{C}_5\text{H}_5\text{NH}^+\).
In this reaction, pyridine assumes the role of a base, while water serves as an acid:
In this reaction, pyridine assumes the role of a base, while water serves as an acid:
- Pyridine Base: \(\text{C}_5\text{H}_5\text{N} + \text{H}_2\text{O} \rightleftharpoons \text{C}_5\text{H}_5\text{NH}^+ + \text{OH}^- \)
Understanding Conjugate Acid-Base Pairs
The concept of conjugate acid-base pairs is foundational in acid-base chemistry. It involves the transformations that occur when a compound donates or accepts a proton. When we look at pyrrolidine and pyridine in water, each acts as a base by accepting a proton. The proton transfer results in the formation of new species, known as conjugate acids and bases.
In the case of pyrrolidine:
In the case of pyrrolidine:
- Pyrrolidinium ion \(\text{C}_4\text{H}_9\text{NH}_2^+\) acts as the conjugate acid.
- The hydroxide ion \(\text{OH}^-\) is the conjugate base.
- Pyridinium ion \(\text{C}_5\text{H}_5\text{NH}^+\) is the conjugate acid.
- The hydroxide ion \(\text{OH}^-\) also forms as the conjugate base.