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Technetium-99m, used for brain scans and to monitor heart function, is formed by decay of molybdenum-99. (a) By what type of decay does \({ }^{99}\) Mo produce \({ }^{99 m} \mathrm{Tc}\) ? (b) Molybdenum-99 is formed by neutron bombardment of a natural isotope. If one neutron is absorbed and there are no other by-products of this process, from what isotope is \({ }^{99}\) Mo formed?

Short Answer

Expert verified
(a) Beta decay. (b) Molybdenum-98.

Step by step solution

01

Determine the Type of Decay

Molybdenum-99 ( ^{99}Mo) decays into Technetium-99m ( ^{99m}Tc). This process is achieved by beta decay, where a neutron in the nucleus converts into a proton, increasing the atomic number by 1 while the mass number remains the same. Hence, ^{99}Mo undergoes beta decay to form ^{99m}Tc.
02

Identify the Isotope Formation Process

Since molybdenum-99 ( ^{99}Mo) forms by neutron bombardment and absorbs one neutron, the resulting atomic mass increases by 1. The required isotope must have an atomic mass of 98. Hence, the nuclide from which ^{99}Mo is formed is molybdenum-98 ( ^{98}Mo), a stable isotope, that, when bombarded by a neutron, forms ^{99}Mo without any other by-products.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Technetium-99m decay
Technetium-99m ( ^{99m}Tc) is a fascinating element frequently used in medical imaging, such as brain scans and heart function assessments. The 'm' in Technetium-99m signifies that this isotope is metastable, meaning it is in an excited state with excess energy. This energy is released in the form of gamma radiation, making it helpful for imaging purposes. The decay of ^{99m}Tc occurs without changing the atomic or mass numbers but rather through the emission of gamma radiation, which is harmless to the tissue in its path. Thus, after ^{99m}Tc decays, it becomes ^{99}Tc, a stable isotope, maintaining the same mass and atomic number.
Beta decay
Beta decay is a type of radioactive decay where a beta particle is emitted from an atomic nucleus. This can happen in two forms: beta-minus and beta-plus decay. In the case of Molybdenum-99 ( ^{99}Mo), it undergoes beta-minus decay. During this process, a neutron is transformed into a proton, which results in the emission of an electron (beta particle) and an antineutrino. - **Atomic Number Increase**: The atomic number of the element increases by one due to the additional proton, transforming ^{99}Mo into ^{99m}Tc. - **Mass Number**: The mass number stays the same because only a nucleon-type shift occurs without a loss of mass.
Neutron bombardment
Neutron bombardment is a process in nuclear chemistry where atoms are bombarded with neutrons. This can cause changes in the nucleus, including the absorption of a neutron, leading to the formation of a new isotope. When neutrons collide with the nucleus of an atom, they do not have an electric charge, allowing them to penetrate the nucleus more easily compared to charged particles. - **Formation of Isotopes**: In the case of Molybdenum-99 ( ^{99}Mo), it is formed from Molybdenum-98 ( ^{98}Mo) when it captures a neutron, increasing the atomic mass by one. - **Stability and Reactivity**: The formed isotope may be radioactive or stable, depending on the neutron-to-proton ratio.
Molybdenum isotopes
Molybdenum isotopes are varieties of the chemical element Molybdenum with different numbers of neutrons in the nucleus. Molybdenum has several naturally occurring isotopes, with varying stability and applications. - **Stable Isotopes**: Molybdenum-98 ( ^{98}Mo) is one stable isotope, playing a crucial role in the reactor production of Molybdenum-99 ( ^{99}Mo) via neutron bombardment. - **Isotope Production and Decay**: Molybdenum-99 ( ^{99}Mo) itself is a key isotope used in the medical field as a precursor to Technetium-99m ( ^{99m}Tc). - **Applications**: These isotopes are significant not only in imaging but also in understanding nuclear reactions and the production of synthetic elements.

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