/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 22 Explain why carbon dioxide can c... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain why carbon dioxide can cross a cell membrane without the aid of a transport protein.

Short Answer

Expert verified
COâ‚‚ crosses the cell membrane by passive diffusion due to its small, nonpolar nature.

Step by step solution

01

Understand the Cell Membrane Structure

The cell membrane is primarily composed of a phospholipid bilayer with embedded proteins. The hydrophobic (water-repelling) tails of the phospholipids face inward, creating a nonpolar and lipid-rich environment.
02

Identify the Nature of Carbon Dioxide

Carbon dioxide (COâ‚‚) is a small, nonpolar molecule. Its nonpolar nature means it can easily interact with the nonpolar, hydrophobic interior of the lipid bilayer.
03

Explain Passive Diffusion

Passive diffusion is the movement of molecules across a cell membrane from an area of higher concentration to an area of lower concentration, without the need for energy input or transport proteins. Nonpolar molecules, like COâ‚‚, can freely diffuse across the hydrophobic core of the cell membrane.
04

Apply Knowledge to COâ‚‚

Given that COâ‚‚ is small and nonpolar, it can dissolve in the lipid bilayer and diffuse across the membrane down its concentration gradient without the aid of transport proteins.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Phospholipid Bilayer
The phospholipid bilayer forms the fundamental structure of the cell membrane. It's like a barricade that surrounds the cell, protecting it and controlling which substances can enter or leave. Imagine it as a sandwich with two layers of bread, where each 'slice' is a phospholipid molecule. Each phospholipid has a hydrophilic (water-attracting) "head" and two hydrophobic (water-repelling) "tails." These tails face inward, away from water, making the center of the bilayer a nonpolar zone.
This arrangement creates a specialized environment that is selective about what can pass through. It permits only certain substances, especially nonpolar ones, to slip through easily. This is crucial because it ensures that cells can maintain their specific internal environment, despite the potentially different conditions outside the cell. The bilayer acts as a guardian, mediating interactions and exchanges between the cell and its surroundings.
Passive Diffusion
Passive diffusion is a natural process that doesn't require cellular energy. It's all about molecules moving from areas of higher concentration to areas of lower concentration, much like people leaving a crowded room for a less crowded one. This movement is spontaneous and occurs because molecules are always in motion.
For substances crossing the cell membrane, passive diffusion is especially significant. Molecules that can diffuse passively are typically nonpolar and small, allowing them to easily navigate the nonpolar interior of the phospholipid bilayer. This means that no assistance from specialized proteins is needed for their passage.
Passive diffusion is an efficient way for the cell to exchange gases like oxygen (Oâ‚‚) and carbon dioxide (COâ‚‚) without using energy. It's a fundamental mechanism that all cells use to maintain equilibrium with their environment, allowing cells to perform vital functions smoothly and efficiently.
Nonpolar Molecules
Nonpolar molecules play an essential role in transport across the cell membrane. These molecules do not have a charge, meaning they are not attracted to polar substances like water. Due to this nonpolar nature, they are more compatible with the hydrophobic interior of the phospholipid bilayer.
This characteristic is crucial for molecules like carbon dioxide (COâ‚‚) and oxygen (Oâ‚‚), which must pass in and out of cells to sustain life. Nonpolar molecules can immerse into the lipid core of the membrane and simply diffuse across without any hindrance. In this way, their nonpolar trait is an advantage, allowing them to freely pass through otherwise selective barriers.
Understanding nonpolar molecules helps clarify why certain small and uncharged substances can effortlessly enter or exit cells. It is this ability that facilitates vital processes like cellular respiration, enabling the uptake of oxygen and release of carbon dioxide. Nonpolar molecules, therefore, are critical actors in maintaining the balance and function of living cells.

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Most popular questions from this chapter

Experiments with erythrocyte "ghosts" were carried out to learn more about the glucose transporter in red blood cells. "Ghosts" are prepared by lysing red blood cells in a hypotonic medium and washing away the cytoplasmic contents. Suspension in an isotonic buffer allows the ghost membranes to reseal. If ghosts are prepared so that the enzyme trypsin is incorporated into the ghost interior, glucose transport does not occur. But glucose transport is not affected if trypsin is located in the extracellular ghost medium. What can you conclude about the glucose transporter, given these observations?

The bacterium Pseudomonas aeruginosa expresses a phosphatespecific porin when phosphate in its growth medium is limiting. Noting that there are three lysines clustered in the surface-exposed amino terminal region of the protein, investigators constructed mutants in which the lysine residues were replaced with glutamate residues. a. Why did the investigators hypothesize that lysine residues might play an important role in phosphate transport in the bacterium? b. Predict the effect of the Lys \(\rightarrow\) Glu substitution on the transport activity of the porin.

a. Calculate the value of \(\Delta G\) for the movement of glucose from outside to inside at \(20^{\circ} \mathrm{C}\) when the extracellular concentration is \(5 \mathrm{mM}\) and the cytosolic concentration is \(0.5 \mathrm{mM}\). b. What is the free energy cost of moving glucose from the outside of the cell (where its concentration is \(0.5 \mathrm{mM}\) ) to the cytosol (where its concentration is \(5 \mathrm{mM}\) ) when \(T=20^{\circ} \mathrm{C}\) ?

As discussed in Section 5.1, tissues produce \(\mathrm{CO}_{2}\) as a waste product during respiration. The \(\mathrm{CO}_{2}\) enters the red blood cell and combines with water to form carbonic acid in a reaction catalyzed by carbonic anhydrase. A red blood cell protein called Band 3 transports \(\mathrm{HCO}_{3}^{-}\)ions in exchange for \(\mathrm{Cl}^{-}\)ions. What role does Band 3 play in transporting \(\mathrm{CO}_{2}\) to the lungs where it can be exhaled?

Explain why acid-gated channel proteins include a set of Asp or Glu residues in their acid sensors. How would these groups participate in gating?

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