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Fill in the blanks of the following table: Acid, base, or neutral? pH [H+] (M) [OH鈥 ] (M) Blood ______ 7.42 ______ ______ Saliva neutral ______ ______ ______ Urine ______ ______ ______ 6.3 脳 10鈥8 Gastric juice ______ ______ 7.9 脳 10鈥3 ______

Short Answer

Expert verified
Blood is basic with [H+] = 3.80 脳 10鈦烩伕 M, [OH-] = 2.63 脳 10鈦烩伔 M. Saliva is neutral at pH 7, so [H+] = [OH-] = 1 脳 10鈦烩伔 M. Urine is slightly acidic with pH 鈮 6.80. Gastric juice is acidic with [OH-] = 7.9 脳 10鈦宦 M and [H+] 鈮 1.27 脳 10鈦宦孤 M.

Step by step solution

01

Understand pH and its implications

To determine if a solution is an acid, base, or neutral, we observe the pH value. If the pH < 7, it's acidic; if pH = 7, it's neutral; if pH > 7, it's basic (alkaline).
02

Calculate hydrogen ion concentration from pH

The hydrogen ion concentration, \([ ext{H}^+]\), can be calculated using the formula \( [ ext{H}^+] = 10^{- ext{pH}} \).
03

Use pH and [H+] to find [OH-]

For any aqueous solution, \([ ext{H}^+] imes [ ext{OH}^-] = 1 imes 10^{-14}\). We can use this equality to find \([ ext{OH}^-]\) given \([ ext{H}^+]\) or vice versa.
04

Analyze Blood Data

Blood has a pH of 7.42. This indicates that it's a basic (alkaline) solution. Using Step 2, we calculate \( [ ext{H}^+] = 10^{-7.42} = 3.80 imes 10^{-8} \) M. Next, using Step 3, \( [ ext{OH}^-] = \frac{1 imes 10^{-14}}{3.80 imes 10^{-8}} = 2.63 imes 10^{-7} \) M.
05

Analyze Saliva Data

Saliva is stated to be neutral implying a pH of 7. Therefore, \( [ ext{H}^+] = 10^{-7} = 1 imes 10^{-7} \) M and \( [ ext{OH}^-] = 1 imes 10^{-7} \) M.
06

Analyze Urine Data

Given the \( [ ext{OH}^-] = 6.3 imes 10^{-8} \) M, we find \( [ ext{H}^+] \) using \( [ ext{H}^+] = \frac{1 imes 10^{-14}}{6.3 imes 10^{-8}} = 1.59 imes 10^{-7} \) M. Thus, pH = -log(1.59 imes 10^{-7}) 鈮 6.80, indicating it's slightly acidic.
07

Analyze Gastric Juice Data

With \( [ ext{OH}^-] = 7.9 imes 10^{-3} \) M, calculate \( [ ext{H}^+] = \frac{1 imes 10^{-14}}{7.9 imes 10^{-3}} = 1.27 imes 10^{-12} \) M. This gives a pH = -log(1.27 imes 10^{-12}) 鈮 12.90, showing that gastric juice is quite acidic.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acid-Base Chemistry
Acid-base chemistry is a branch of chemistry dealing with reactions between acids and bases. Understanding whether a substance is an acid or base depends on its pH level, which measures how acidic or basic a solution is. Here's a quick guide:
  • A solution is acidic if it has a pH less than 7. Examples include lemon juice and vinegar.
  • A solution is neutral if it has a pH of 7. Pure water is a classic example of this.
  • A solution is basic (or alkaline) if it has a pH greater than 7. Common examples are bleach and baking soda.
While pH provides a simple way to determine the nature of the solution, the actual chemistry involves more complexity. In water, acidic solutions result from an increased concentration of hydrogen ions \( [\text{H}^+] \), while bases increase the concentration of hydroxide ions \( [\text{OH}^-] \). Both these ions play a crucial role in defining whether a solution is acidic or basic.
Hydrogen Ion Concentration
Understanding the hydrogen ion concentration is vital for grasping the nuances of pH and acidity or basicity in a solution. The concentration of hydrogen ions in a solution is measured in moles per liter \(M\) and directly influences the pH value.To calculate the hydrogen ion concentration from a given pH, we use the formula:\[[\text{H}^+] = 10^{-\text{pH}}\]This formula tells us that the hydrogen ion concentration decreases as the pH increases and vise versa. For example, if a solution has a pH of 3, its hydrogen ion concentration \( [\text{H}^+] \) will be \( 10^{-3} \ or 0.001 \text{ M} \). Similarly, for a neutral pH of 7, \( [\text{H}^+] = 10^{-7} \text{ M} \).This concept not only helps us understand acidity but also aids in determining the basicity. If we know the hydrogen ion concentration, we can find the hydroxide ion concentration using the relation:\[[\text{H}^+] \times [\text{OH}^-] = 1 \times 10^{-14}\]This balance between hydrogen and hydroxide ions is fundamental to acid-base chemistry.
Neutral Solutions
Neutral solutions are a special category in the acid-base chemistry world. A neutral solution has a pH of exactly 7, indicating it is neither acidic nor basic. The best-known example is pure water.In a neutral solution:
  • The concentration of hydrogen ions \( [\text{H}^+] \) is equal to that of hydroxide ions \( [\text{OH}^-] \). Both are \( 1 \times 10^{-7} \text{ M} \).
  • This balance creates a stable environment, making neutral solutions ideal for certain chemical reactions and processes.
Understanding neutral solutions is crucial, as it acts as a benchmark against which we can measure the acidity or basicity of other solutions. In practice, adjusting a solution to a neutral pH can be essential in certain scientific and industrial processes, ensuring that there's no corrosive or adverse reaction driven by acidity or alkalinity.

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Most popular questions from this chapter

The amino acid glycine \(\left(\mathrm{H}_{2} \mathrm{~N}-\mathrm{CH}_{2}-\mathrm{COOH}\right)\) has \(\mathrm{p} K\) values of \(2.35\) and \(9.78\). Indicate the structure and net charge of the molecular species that predominate at \(\mathrm{pH} 2,7\), and 10 .

a. Water has a surface tension that is nearly three times greater than that of ethanol. Explain. b. The surface tension of water decreases with increasing temperature. Explain.

Metabolic acidosis is a general term that describes a number of disorders in metabolism in the body that result in a lowering of the blood pH from \(7.4\) to \(7.35\) or below. The kidney plays a vital role in regulating blood \(\mathrm{pH}\). The kidney can either excrete or reabsorb various ions, including phosphate, \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\); ammonium, \(\mathrm{NH}_{4}^{+}\); or bicarbonate, \(\mathrm{HCO}_{3}^{-}\). Which ions are excreted and which ions are reabsorbed in metabolic acidosis? Explain, using relevant chemical equations.

What is the volume (in \(\mathrm{mL}\) ) of glacial acetic acid \((17.4 \mathrm{M})\) that would have to be added to \(500 \mathrm{~mL}\) of a solution of \(0.20 \mathrm{M}\) sodium acetate in order to achieve a pH of \(5.0\) ?

The \(\mathrm{pH}\) of blood is maintained within a narrow range \((7.35\) 7.45). Carbonic acid, \(\mathrm{H}_{2} \mathrm{CO}_{3}\), participates in blood buffering. a. Write the equations for the dissociation of the two ionizable protons. b. The \(\mathrm{p} K\) for the first ionizable proton is \(6.35\); the \(\mathrm{p} K\) for the second ionizable proton is \(10.33\). Use this information to identify the weak acid and the conjugate base present in the blood. c. Calculate the concentration of carbonic acid in a sample of blood with a bicarbonate concentration of \(24 \mathrm{mM}\) and a \(\mathrm{pH}\) of \(7.40\).

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