/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 4 A sample of cells has a total re... [FREE SOLUTION] | 91Ó°ÊÓ

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A sample of cells has a total receptor concentration of \(50 \mathrm{mM}\). Fifty percent of the receptors have bound ligand and the concentration of free ligand is \(5 \mathrm{mM}\). a. What is the \(K_{\mathrm{d}}\) for the receptor- ligand interaction? b. What is the relationship between \(K_{\mathrm{d}}\) and [L]?

Short Answer

Expert verified
a. \(K_d = 5 \; \text{mM}\); b. \([L] = K_d\) when receptors are 50% bound.

Step by step solution

01

Understand the Given Problem

We are given a ligand-receptor interaction scenario where a total receptor concentration of \(50 \; \text{mM}\) is provided. It is stated that 50% of these receptors have bound ligands. The concentration of free ligand is \(5 \; \text{mM}\). The task is to find the dissociation constant \(K_d\) and understand its relationship with the free ligand concentration \([L]\).
02

Recall the Definition of Dissociation Constant

The dissociation constant \(K_d\) is defined as the concentration of ligand \([L]\) when half of the receptors \([R]_t\) are bound. Mathematically, \(K_d = \frac{{[L][R]}}{{[RL]}}\), where \([L]\) is the concentration of free ligand, \([R]\) is the concentration of free receptors, and \([RL]\) is the concentration of receptor-ligand complex.
03

Set up the Equation Using Given Information

Since 50% of the \(50\; \text{mM}\) receptors are bound, \([RL] = 25\; \text{mM}\). This means \([R] = 25\; \text{mM}\) because the total receptor concentration \([R]_t = [R] + [RL] = 50 \; \text{mM}\) when half are bound. Also, \([L] = 5\; \text{mM}\).
04

Calculate \(K_d\)

Substitute the values into the equation \(K_d = \frac{{[L][R]}}{{[RL]}}\):\[K_d = \frac{{5\; \text{mM} \times 25\; \text{mM}}}{{25\; \text{mM}}} = 5 \; \text{mM}\]Thus, the dissociation constant \(K_d\) is \(5 \; \text{mM}\).
05

Relationship Between \(K_d\) and \([L]\)

By definition, when \([RL]\) is 50% of the receptor concentration \([R]_t\), \([L] = K_d\). Therefore, \(K_d\) is equal to the ligand concentration that results in half of the receptors being occupied. In this scenario, \([L] = K_d = 5 \; \text{mM}\), which is consistent with the problem statement.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Receptor-Ligand Interaction
In biochemistry, receptor-ligand interactions are crucial for numerous cellular processes. These interactions involve receptors, which are proteins on the cell surface or within the cell, and ligands, which are molecules like hormones or neurotransmitters that bind specifically to the receptors. This binding often results in a cellular response. The strength or affinity of the interaction is characterized by the dissociation constant, abbreviated as \(K_d\).

When a ligand binds to a receptor, a reversible complex \([RL]\) is formed. It is important to understand that the binding of a ligand to its receptor can be thought of as an equilibrium reaction:

\[ R + L \rightleftharpoons RL \]

Here, \([R]\) represents free receptors, \([L]\) represents free ligands, and \([RL]\) represents the receptor-ligand complex. The dissociation constant \(K_d\) provides an indication of how tightly a ligand binds to a receptor. A lower \(K_d\) value indicates a higher affinity because less ligand is needed to occupy half of the receptors.
Free Ligand Concentration
Understanding free ligand concentration is vital in determining receptor-ligand interactions. Free ligand concentration \([L]\) refers to the amount of ligand present that is not bound to any receptor. In the context of calculating \(K_d\), knowing \([L]\) helps to identify how much ligand is necessary to achieve specific occupancy levels of the receptors.

In the example problem, you are told that the concentration of free ligand is \(5 \, \text{mM}\). This information is essential to calculate the \(K_d\) because it directly relates to the degree of receptor occupancy. In receptors systems, once half of the receptors are occupied, the concentration of free ligand equals the \(K_d\). So for our task, since 50% of the receptors are occupied, the \([L]\) given is indeed the \(K_d\).

In summary, free ligand concentration is a crucial component in understanding receptor occupancy and, consequently, in determining the dissociation constant \(K_d\).
Biochemistry Problem Solving
Biochemistry problems, such as determining the dissociation constant, involve a series of logical steps. Breaking down the problem and analyzing each component with clarity is key. Let's see how this applies to our receptor-ligand interaction problem.

First, identify what you've been provided and what needs solving. In the scenario, we're given:
  • A total receptor concentration \([R]_t\) of \(50 \, \text{mM}\).
  • 50% of these receptors have bound ligand.
  • The concentration of free ligand \([L]\) = \(5 \, \text{mM}\).
Next, understand the concept of \(K_d\) and the equation \(K_d = \frac{{[L][R]}}{{[RL]}}\). We substitute known values into this equation:
\[ K_d = \frac{5 \, \text{mM} \times 25 \, \text{mM}}{25 \, \text{mM}} = 5 \, \text{mM} \]

Finally, comprehend the relationship between \(K_d\) and \([L]\). At 50% receptor saturation, \(K_d\) equals \([L]\). Following these steps will provide clarity and allow accurate solutions to biochemistry problems.

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