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(a) The irreversible elementary reaction \(2 \mathrm{A} \longrightarrow \mathrm{B}\) takes place in the gas phase in an isothermal tubular (plug-flow) reactor. Reactant A and a diluent \(C\) are fed in equimolar ratio, and conversion of \(A\) is \(80 \%\). If the molar feed rate of \(A\) is cut in half, what is the conversion of \(A\) assuming that the feed rate of \(\mathrm{C}\) is left unchanged? Assume ideal behavior and that the reactor temperature remains unchanged. What was the point of this problem? (From California Professional Engineers Exam.) (b) Write a question that requires critical thinking, and explain why it involves critical thinking.

Short Answer

Expert verified
The conversion of A when the molar feed rate is cut in half is found to be \(X'_A = 0.941\), which is higher than the initial conversion of 80%. This problem demonstrated the effect of changing the molar feed rate of a reactant on the conversion rate in an isothermal plug-flow reactor, requiring the application of reactor design concepts and the understanding of feed rates on reaction rates.

Step by step solution

01

Find the initial molar flow rate of A

Since Reactant A and diluent C are in equimolar ratio, the initial molar flow rate of A, \(F_{A0}\), is equal to half the total molar flow rate.
02

Apply the continuity equation for plug flow reactors

The continuity equation for plug flow reactors is given by: \(\frac{dF_A}{dV} = r_A\) Where \(F_A\) is the molar flow rate of A, \(V\) is the reactor volume, and \(r_A\) is the rate of reaction of A. For an isothermal irreversible elementary reaction, the rate of reaction is given by: \(r_A = -k C_A^2\) Considering ideal behavior, the concentration of A (\(C_A\)) can be expressed as: \(C_A = \frac{F_A C_{T0}}{F_{T0}}\) Where \(C_{T0}\) is the total inlet concentration, and \(F_{T0}\) is the total molar flow rate. Substitute the expressions for \(r_A\) and \(C_A\) into the continuity equation: \(\frac{dF_A}{dV} = -k \left(\frac{F_A C_{T0}}{F_{T0}}\right)^2\)
03

Integrate the continuity equation to find V

Integrate the continuity equation from \(F_{A0}\) to \(F_A\) and from 0 to V: \(\int_{F_{A0}}^{F_A} \frac{dF_A'}{F_A'^2} = -kC_{T0}^2 \int_{0}^{V} dV'\) Upon integrating and rearranging, we get the reactor volume V: \(V = \frac{1}{kC_{T0}^2} \left(\frac{1}{F_A} - \frac{1}{F_{A0}}\right)\) Since the conversion of A is 80%, we can find \(F_A\) as: \(F_A = F_{A0}(1 - X_A)\) Where \(X_A\) is the conversion of A. Substitute this into the reactor volume equation and solve for V.
04

Calculate the conversion of A when the molar feed rate is halved

Now, we will cut the molar feed rate of A in half, which means \(F'_{A0} = \frac{1}{2}F_{A0}\). We will use the same reactor volume equation but with the new molar feed rate of A: \(V = \frac{1}{kC_{T0}^2} \left(\frac{1}{F'_A} - \frac{1}{F'_{A0}}\right)\) Since the reactor volume and temperature are unchanged, the equation will remain the same. We can solve for the new conversion \(X'_A\) by finding the relation between \(F'_A\) and \(F'_{A0}\): \(F'_A = F'_{A0}(1 - X'_A)\) Substitute this into the reactor volume equation and solve for \(X'_A\).
05

Point of this problem

The point of this problem was to demonstrate how changing the molar feed rate of a reactant can affect the conversion rate in an isothermal plug-flow reactor. The problem required us to apply the concepts of reactor design and the effect of feed rates on reaction rates.
06

Example of a critical thinking question

How would using a non-isothermal reactor instead of an isothermal reactor modify the conversion of reactant A if the molar feed rate of A was cut in half? Explain the differences considering heat effects and reaction kinetics. This question involves critical thinking because it requires understanding the fundamental concepts of reactor design, evaluating the differences between isothermal and non-isothermal reactors, and analyzing the impact of heat effects and kinetics on the conversion of reactant A.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactor Design
Understanding the design of chemical reactors, such as the isothermal plug-flow reactor (PFR) involved in the exercise, is critical for chemical engineers. In a PFR, reactants flow through a cylindrical pipe without mixing in the radial direction. The reaction proceeds as the mixture moves along the length of the reactor.

An essential aspect of designing a PFR is the consideration of steady-state operation where the reaction conditions, like temperature and pressure, remain constant throughout the reactor. The PFR design must ensure that the desired conversion is achieved efficiently and safely. Key design aspects include reactor dimensions, material choice, and temperature control mechanisms. Reactor sizing is often based on the integration of a rate law over the reactor volume, as seen in the exercise. Isothermal conditions, where temperature is constant, simplify the calculations but may not always represent practical conditions accurately.
Reaction Kinetics
Reaction kinetics plays a pivotal role in the design and operation of reactors. It involves studying the rates of chemical reactions and how they are affected by various factors such as concentration, temperature, and catalyst presence. Kinetics dictates how quickly reactant converts to product, which in turn has a direct impact on the size and type of reactor needed.

In the provided exercise, the reaction kinetics are represented by the rate law for an elementary reaction, given as a function of the concentration of reactant A. The rate law is integrated to determine the reactor volume needed to achieve a particular conversion, illustrating the practical application of kinetics in reactor design. The exercise demonstrates the significance of kinetics by showing how the conversion changes when the initial molar feed rate is altered while keeping the reactor isothermal.
Molar Feed Rate
The molar feed rate is the number of moles of a reactant being fed into a reactor per unit time. It's a critical parameter as it influences the concentration of reactants in the reactor, and thereby, the rate of reaction. In case of the isothermal plug-flow reactor from the exercise, the feed rate of reactant A directly affects the concentration of A, which in turn influences the rate at which A converts to product B.

The relationship between molar feed rates and conversion is non-linear, with variations in feed rates leading to changes in conversion levels. Decreasing the molar feed rate, as seen in the exercise, allows for more residence time or more volume for reactant molecules within the reactor, potentially increasing the conversion percentage. The exercise showcases that halving the feed rate does not simply halve conversion, but the impact needs to be evaluated through the continuity equation.
Reaction Conversion
Reaction conversion is the fraction of reactant that transforms into product, and it ultimately determines the efficiency of a reactor. High conversion rates are often desired as they indicate a more effective use of reactants and often lead to lower costs of operation. In the exercise, the conversion of reactant A from the molar feed rate serves as the yardstick to assess the performance of the plug-flow reactor.

Conversion can be affected by factors like feed rates, reactor type, catalyst presence, and operating conditions, including temperature and pressure. The exercise demonstrates how conversion is calculated, showing that the initial 80% conversion is specific to the initial feed rate. By halving the molar feed rate of A while keeping the feed rate of diluent C constant, the exercise challenges the student to predict the new conversion, which requires a detailed understanding of the interplay between reactor design parameters and reaction kinetics.

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Most popular questions from this chapter

Nutrition is an important part of ready-to-eat cereal. To make cereal healthier, many nutrients are added. Unfortunately, nutrients degrade over time, making it necessary to add more than the declared amount to assure enough for the life of the cereal. Vitamin \(V_{1}\) is declared at a level of \(20 \%\) of the Recommended Daily Allowance per serving size (serving size \(=30 \mathrm{g}\) ). The Recommended Daily Allowance is \(6500 \mathrm{IU}\left(1.7 \times 10^{6} \mathrm{IU}=1 \mathrm{g}\right) .\) It has been found that the degradation of this nutrient is first order in the amount of nutrients. Accelerated storage tests have been conducted on this cereal, with the following results: $$\begin{array}{l|ccc} \text { Temperature }\left(^{\circ} \mathrm{C}\right) & 45 & 55 & 65 \\ \hline k \text { (week }^{-1} \text {) } & 0.0061 & 0.0097 & 0.0185 \end{array}$$ (a) Given this information and the fact that the cereal needs to have a vitamin level above the declared value of 6500 IU for 1 year at \(25^{\circ} \mathrm{C}\). what IU should be present in the cereal at the time it is manufactured? Your answer may also be reported in percent overuse: $$\% \mathrm{OU}=\frac{C(t=0)-C(t=1 \mathrm{yr})}{C(t=1 \mathrm{yr})} \times 100$$ (b) At what percent of declared value of 6500 IU must you apply the vitamin? If 10,000.000 lb/yr of the cereal is made and the nutrient cost is S100 per pound, how much will this overuse cost? (c) If this were your factory, what percent overuse would you actually apply and why? (d) How would your answers change if you stored the material in a Bangkok warehouse for 6 months. where the daily temperature is \(40^{\circ} \mathrm{C}\), before moving it to the supermarket? (Table of results of accelerated storage tests on cereal; and Problem of vitamin level of cereal after storage courtesy of General Mills, Minneapolis, MN.)

The following reaction is to be carried out in the liquid phase $$\mathrm{NaOH}+\mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5} \longrightarrow \mathrm{CH}_{3} \mathrm{COO}^{-} \mathrm{Na}^{+}+\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}$$ The initial concentrations are \(0.2 \quad M\) in \(\mathrm{NaOH}\) and \(0.25 \mathrm{M}\) in \(\mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5}\) with \(k=5.2 \times 10^{-5} \mathrm{m}^{3} / \mathrm{mol} \cdot \mathrm{s}\) at \(20^{\circ} \mathrm{C}\) with \(E=42.810\) J/mol. Design a set of operating conditions to produce 200 mol/day of ethanol in a semibatch reactor and not operate above \(35^{\circ} \mathrm{C}\) and below a concentration of \(\mathrm{NaOH}\) of 0.02 molar. \(^{12}\) The semibatch reactor you have available is \(1.5 \mathrm{m}\) in diameter and \(2.5 \mathrm{m}\) tall.

It is desired to carry out the gaseous reaction \(A \longrightarrow B\) in an existing tubular reactor consisting of 50 parallel tubes 40 ft long with a 0.75-in. inside diameter. Bench-scale experiments have given the reaction rate constant for this first-order reaction as \(0.00152 \mathrm{s}^{-1}\) at \(200^{\circ} \mathrm{F}\) and \(0.0740 \mathrm{s}^{-1}\) at \(300^{\circ} \mathrm{F}\). At what temperature should the reactor be operated to give a conversion of \(\mathrm{A}\) of \(80 \%\) with a feed rate of \(500 \mathrm{lb} / \mathrm{h}\) of pure \(\mathrm{A}\) and an operating pressure of 100 psig? A has a molecular weight of \(73 .\) Departures from perfect gas behavior may be neglected, and the reverse reaction is insignificant at these conditions. (Ans.: \(T=275^{\circ} \mathrm{F}\) ) (From California Professional Engineers Exam.)

The production of ethylene glycol from ethylene chlorohydrin and sodium bicarbonate $$\mathrm{CH}_{2} \mathrm{OHCH}_{2} \mathrm{Cl}+\mathrm{NaHCO}_{3} \rightarrow\left(\mathrm{CH}_{2} \mathrm{OH}\right)_{2}+\mathrm{NaCl}+\mathrm{CO}_{2}$$ is carried out in a semibatch reactor. A 1.5 molar solution of ethylene chlorohydrin is fed at a rate 0.1 mole/minute to \(1500 \mathrm{dm}^{3}\) of a 0.75 molar solution of sodium bicarbonate. The reaction is elementary and carried out isother mally at \(30^{\circ} \mathrm{C}\) where the specific reaction rate is \(5.1 \mathrm{dm}^{3} / \mathrm{mol} / \mathrm{h}\). Higher tem peratures produce unwanted side reactions. The reactor can hold a maximun of \(2500 \mathrm{dm}^{3}\) of liquid. Assume constant density. (a) Plot the conversion, reaction rate, concentration of reactants and prod ucts, and number of moles of glycol formed as a function of time. (b) Suppose you could vary the flow rate between 0.01 and \(2 \mathrm{mol} / \mathrm{min}\), whas flow a rate would and holding time you choose to make the greatest num ber of moles of ethylene glycol in 24 hours keeping in mind the down times for cleaning, filling. etc., shown in Table 4-1. (c) Suppose the ethylene chlorohydrin is fed at a rate of 0.15 mol/min until the reactor is full and then shut in. Plot the conversion as a function of time. (d) Discuss what you learned from this problem and what you believe to be the point of this problem.

The gaseous reaction \(A \longrightarrow B\) has a unimolecular reaction rate constant of \(0.0015 \mathrm{min}^{-1}\) at \(80^{\circ} \mathrm{F}\). This reaction is to be carried out in parallel tubes \(10 \mathrm{ft}\) long and 1 in. inside diameter under a pressure of 132 psig at \(260^{\circ} \mathrm{F}\). A production rate of \(1000 \mathrm{lb} / \mathrm{h}\) of \(\mathrm{B}\) is required. Assuming an activation energy of 25,000 cal/mol. how many tubes are needed if the conversion of \(A\) is to be \(90 \% ?\) Assume perfect gas laws. A and \(\mathrm{B}\) each have molecular weights of 58 . (From California Professional Engineers Exam.)

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