/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 Formaldehyde is produced commerc... [FREE SOLUTION] | 91Ó°ÊÓ

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Formaldehyde is produced commercially by the catalytic oxidation of methanol. In a side reaction, methanol is oxidized to \(\mathrm{CO}_{2}\) $$\begin{array}{l}\mathrm{CH}_{3} \mathrm{OH}+\mathrm{O}_{2} \rightarrow \mathrm{CH}_{2} \mathrm{O}+\mathrm{H}_{2} \mathrm{O} \\\\\mathrm{CH}_{3} \mathrm{OH}+\mathrm{O}_{2} \rightarrow \mathrm{CO}_{2}+2 \mathrm{H}_{2} \mathrm{O}\end{array}$$ A mixture containing 55.6 mole \(\%\) methanol and the balance oxygen enters a reactor at \(350^{\circ} \mathrm{C}\) and \(1 \mathrm{atm}\) at a rate of \(4.60 \times 10^{4} \mathrm{L} / \mathrm{s}\). The reaction products emerge at the same temperature and pressure at a rate of \(6.26 \times 10^{4} \mathrm{L} / \mathrm{s} .\) An analysis of the products yields a molar composition of \(36.7 \% \mathrm{CH}_{2} \mathrm{O}, 4.1 \% \mathrm{CO}_{2}\) \(14.3 \% \mathrm{O}_{2},\) and \(44.9 \% \mathrm{H}_{2} \mathrm{O} .\) The required reactor cooling rate is calculated to be \(1.05 \times 10^{5} \mathrm{kW}\) (a) Is the calculated cooling rate correct for the given stream data? (b) The stream data cannot be correct. Prove it.

Short Answer

Expert verified
After calculating energetics, if the calculated cooling rate doesn't match with the \(1.05 \times 10^5 kW\), then the given cooling rate is incorrect. And if calculated moles of \(O_2\) for both reactions don't match with the moles in the input stream, the stream data is incorrect.

Step by step solution

01

- Calculation of Mole flows

First calculate the mole flows of the key substances involved in the reaction. The molar flow of the incoming methanol is calculated as \(0.556 \times \frac{4.60 \times 10^{4}\,L/s}{24.47\,L/mol}\), where 24.47 is the molar volume in liters under standard conditions (1 atm, 25 Celsius). Similarly, get the molar flows of \(CH_2O\), \(CO_2\), and \(H_2O\) from the exit gas stream.
02

- Application of Energy Balance

To verify the cooling rate, apply the energy balance principle on the system. This amounts to the fact that total energy coming into system should equate the total energy going out of it. Make use of appropriate heats of formation and combustion to calculate energetics of the incoming methanol, the desired reaction outcome, and the side reaction. Here, remember reactions are exothermic and heat will be released. Based on these findings, compare the energetics with the given cooling rate.
03

- Application of Molar Balance

To prove the inaccuracy in the stream data, apply the molar balance principle on \(O_2\), being a key reactant. Calculate the total moles of \(O_2\) needed for both the main and the side reactions. Match it with the moles of \(O_2\) in the input stream. If it doesn't match, then the stream data is shown to be incorrect.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Catalytic Oxidation
Catalytic oxidation is a fundamental chemical process whereby a catalyst accelerates the oxidation of a substance. In our context, the commercial production of formaldehyde from methanol is under scrutiny. To understand the reaction, picture the catalyst as a facilitator that doesn't change itself but makes it easier for reactants, in this case, methanol (\( \text{CH}_3\text{OH} \) and oxygen (\( \text{O}_2 \) to convert into products: formaldehyde (\( \text{CH}_2\text{O} \) and water (\( \text{H}_2\text{O} \) in the main reaction, and carbon dioxide (\( \text{CO}_2 \) and water in the side reaction.

It's important to understand that not all of the methanol turns into formaldehyde; some of it is fully oxidized into water and carbon dioxide. This is typical in such processes where multiple reactions can occur, and managing these side reactions is vital for efficiency and safety. Catalysts must be carefully selected to favor the main reaction and minimize undesired byproducts while operating under specific conditions of temperature and pressure.

When interacting with the catalyst, these molecules break and form new bonds to generate the desired and side products. In industrial processes, this is heavily monitored and optimized to ensure maximum yield and minimum waste.
Energy Balance
The energy balance is a cornerstone of chemical engineering and reaction analysis, ensuring that the energy entering a system (like our reactor) equals the energy exiting. This reflects the conservation of energy principle. In the context of the exercise, this involves comparing the heat released by the reaction (exothermic in nature) with the reactor's cooling rate.

Every chemical substance involved in a reaction possesses a certain amount of stored energy, commonly referred to as enthalpy. When reactions occur, this enthalpy changes, and energy is either absorbed or released. In our scenario, the enthalpies of formation and combustion provide us with the energy changes of methanol conversion to formaldehyde and the side reaction leading to carbon dioxide. To confirm if the reactor's cooling rate aligns with the stream data, we compare the energy released (sum of the exothermic reactions' energy) with the cooling rate provided. The calculated cooling rate should ideally match the sum of the heat of reaction of the products and the enthalpies of the inflowing and outflowing streams if the energy balance is maintained.
Mole Flows
Mole flows are a reflection of the amount of a substance in terms of its molecular count per time unit, which is crucial for quantifying chemical reactions. In our problem, the mole flow calculations help us understand how much reactant is being converted and whether the product stream data is accurate.

To calculate mole flows for this problem, we began by determining the methanol mole flow entering the reactor based on its given percentage and the volumetric flow rate. After that, we analyzed the product stream to get the mole flows for each product formed. Through these figures, it’s possible not only to gain insight into the reaction progress but also to apply a molar balance. A molar balance involves verifying if the number of moles of reactants equals the number of moles of products considering both the main and side reactions.

By establishing the mole flow for oxygen, we can compare it against the amounts required for the reactions. If the necessary oxygen for the reactions exceeds what's available in the stream, then we can conclude that there's an error in the given stream data. This essential concept allows chemical engineers to validate reaction feasibility, optimize processes, and troubleshoot production issues.

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Most popular questions from this chapter

Formaldehyde is produced by decomposing methanol over a silver catalyst: $$\mathrm{CH}_{3} \mathrm{OH} \rightarrow \mathrm{HCHO}+\mathrm{H}_{2}$$ To provide heat for this endothermic reaction, some oxygen is included in the feed to the reactor, leading to the partial combustion of the hydrogen produced in the methanol decomposition. The feed to an adiabatic formaldehyde production reactor is obtained by bubbling a stream of air at 1 atm through liquid methanol. The air leaves the vaporizer saturated with methanol and contains \(42 \%\)methanol by volume. The stream then passes through a heater in which its temperature is raised to \(145^{\circ} \mathrm{C} .\) To avoid deactivating the catalyst, the maximum temperature attained in the reactor must be limited to \(600^{\circ} \mathrm{C}\). For this purpose, saturated steam at \(145^{\circ} \mathrm{C}\) is metered into the air-methanol stream, and the combined stream cnters the reactor. A fractional methanol conversion of \(70.0 \%\) is achicved in the reactor, and the product gas contains 5.00 mole\% hydrogen. The product gas is cooled to \(145^{\circ} \mathrm{C}\) in a waste heat boiler in which saturated steam at 3.1 bar is generated from liquid water at \(30^{\circ} \mathrm{C}\). Several absorption and distillation units follow the waste heat boiler, and formaldehyde is ultimately recovered in an aqueous solution containing 37.0 wt\% HCHO. The plant is designed to produce 36 metric kilotons of this solution per year, operating 350 days/yr. (a) Draw the process flowchart and label it completely. Show the absorption/distillation train as a single unit with the reactor product gas and additional water entering and the formaldehyde solution and a gas stream containing methanol, oxygen, nitrogen, and hydrogen leaving. (b) Calculate the operating temperature of the methanol vaporizer. (c) Calculate the required feed rate of steam to the reactor \((\mathrm{kg} / \mathrm{h})\) and the molar flow rate and composition of the product gas. (d) Calculate the rate ( \(\mathrm{kg} / \mathrm{h}\) ) at which steam is generated in the waste heat boiler. (e) Enough saturated steam was added to the feed to the reactor to keep the reactor outlet temperature at \(600^{\circ} \mathrm{C}\). Explain in your own words (i) why adding steam lowers the outlet temperature, and (ii) the cconomic drawbacks of higher and lower outlet temperatures.

The synthesis of cthyl chloride is accomplished by reacting ethylene with hydrogen chloride in the presence of an aluminum chloride catalyst: $$\mathrm{C}_{2} \mathrm{H}_{4}(\mathrm{g})+\mathrm{HCl}(\mathrm{g}) \stackrel{\text { catallyst }}{\longrightarrow} \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}(\mathrm{g}) ; \quad \Delta H_{\mathrm{r}}\left(0^{\circ} \mathrm{C}\right)=-64.5 \mathrm{kJ}$$ Process data and a simplified schematic flowchart are given here. Data Reactor: adiabatic, outlet temperature \(=50^{\circ} \mathrm{C}\) Feed A: \(100 \% \mathrm{HCl}(\mathrm{g}), 0^{\circ} \mathrm{C}\) Feed \(\mathrm{B}: 93\) mole \(\% \mathrm{C}_{2} \mathrm{H}_{4}, 7 \% \mathrm{C}_{2} \mathrm{H}_{6}, 0^{\circ} \mathrm{C}\) Reactor: adiabatic, outlet temperature \(=50^{\circ} \mathrm{C}\) Feed A: 100\% HCl(g), 0"C Feed B: 93 mole\% C_H_4, 7\% C_H_0, 0"C Product C: Consists of 1.5\% of the HCl, 1.5\% of the C_2 \(\mathrm{H}_{4}\), and all of the \(\mathrm{C}_{2} \mathrm{H}_{6}\) that enter the reactor Product D: \(1600 \mathrm{kg} \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}(\mathrm{l}) / \mathrm{h}, 0^{\circ} \mathrm{C}\) Recycle to reactor: \(\mathbf{C}_{2} \mathrm{H}_{5} \mathrm{Cl}(\mathrm{l}), 0^{\circ} \mathrm{C}\) \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{Cl}: \Delta \hat{H}_{\mathrm{y}}=24.7 \mathrm{kJ} / \mathrm{mol}\) (assume independent of \(T\) ) \(\left(C_{p}\right)_{C_{2} H_{3} C(v)}\left[\mathrm{kJ} /\left(\mathrm{mol} \cdot^{\circ} \mathrm{C}\right)\right]=0.052+8.7 \times 10^{-5} T\left(^{\circ} \mathrm{C}\right)\) The reaction is exothermic, and if the heat of reaction is not removed in some way, the reactor temperature could increase to an undesirably high level. To avoid this occurrence, the reaction is carried out with the catalyst suspended in liquid cthyl chloride. As the reaction proceeds, most of the heat liberated goes to vaporize the liquid, making it possible to keep the reaction temperature at or below 50^'C. The stream leaving the reactor contains cthyl chloride formed by reaction and that vaporized in the reactor. This stream passes through a heat exchanger where it is cooled to \(0^{\circ} \mathrm{C},\) condensing essentially all of the cthyl chloride and leaving only unreacted \(\mathrm{C}_{2} \mathrm{H}_{4}, \mathrm{HCl}\), and \(\mathrm{C}_{2} \mathrm{H}_{6}\) in the gas phase. A portion of the liquid condensate is recycled to the reactor at a rate equal to the rate at which ethyl chloride is vaporized, and the rest is taken off as product. At the process conditions, heats of mixing and the influence of pressure on enthalpy may be neglected. (a) At what rates (kmol/h) do the two feed streams enter the process? (b) Calculate the composition (component mole fractions) and molar flow rate of product stream \(\mathrm{C}\). (c) Write an energy balance around the reactor and use it to determine the rate at which ethyl chloride must be recycled. (d) A number of simplifying assumptions were made in the process description and the analysis of this process system, so the results obtained using a more realistic simulation would differ considerably from those you should have obtained in Parts (a)-(c). List as many of these assumptions as you can think of.

Formaldehyde may be produced in the reaction between methanol and oxygen: $$2 \mathrm{CH}_{3} \mathrm{OH}(\mathrm{l})+\mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{HCHO}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}): \quad \Delta H_{\mathrm{r}}^{\circ}=-326.2 \mathrm{kJ}$$ The standard heat of combustion of hydrogen is $$\mathrm{H}_{2}(\mathrm{g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l}): \quad \Delta \hat{H}_{\mathrm{c}}^{\circ}=-285.8 \mathrm{kJ} / \mathrm{mol}$$ (a) Use these heats of reaction and Hess's law to determine the standard heat of the direct decomposition of mcthanol to form formaldchyde: $$\mathrm{CH}_{3} \mathrm{OH}(\mathrm{l}) \rightarrow \mathrm{HCHO}(\mathrm{g})+\mathrm{H}_{2}(\mathrm{g})$$ (b) Explain why you would probably use the method of Part (a) to determine the heat of the methanol decomposition reaction experimentally rather than carrying out the decomposition reaction and measuring \(\Delta H_{f}^{\circ}\) directly.

Calcium chloride is a salt used in a number of food and medicinal applications and in brine for refrigeration systems. Its most distinctive property is its affinity for water. in its anhydrous form it efficiently absorbs water vapor from gases, and from aqueous liquid solutions it can form (at different conditions) calcium chloride hydrate \(\left(\mathrm{CaCl}_{2} \cdot \mathrm{H}_{2} \mathrm{O}\right)\) dihydrate \(\left(\mathrm{CaCl}_{2} \cdot 2 \mathrm{H}_{2} \mathrm{O}\right)\) tetrahydrate \(\left(\mathrm{CaCl}_{2} \cdot 4 \mathrm{H}_{2} \mathrm{O}\right),\) and hexahydrate \(\left(\mathrm{CaCl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}\right)\) You have been given the task of determining the standard heat of the reaction in which calcium chloride hexahydrate is formed from anhydrous calcium chloride: $$\mathrm{CaCl}_{2}(\mathrm{s})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{CaCl}_{2} \cdot 6 \mathrm{H}_{2} \mathrm{O}(\mathrm{s}): \quad \Delta H_{\mathrm{r}}^{\circ}(\mathrm{k} \mathrm{J})=?$$ By definition, the desired quantity is the heat of hydration of calcium chloride hexahydrate. You cannot carry out the hydration reaction directly, so you resort to an indirect method. You first dissolve 1.00 mol of anhydrous \(\mathrm{CaCl}_{2}\) in \(10.0 \mathrm{mol}\) of water in a calorimeter and determine that \(64.85 \mathrm{kJ}\) of heat must be transferred away from the calorimeter to keep the solution temperature at \(25^{\circ} \mathrm{C}\). You next dissolve 1.00 mol of the hexahydrate salt in 4.00 mol of water and find that 32.1 kJ of heat must be transferred to the calorimeter to keep the temperature at \(25^{\circ} \mathrm{C}\). (a) Use these results to calculate the desired heat of reaction. (Suggestion: Begin by writing out the stoichiometric equations for the two dissolution processes.) (b) Calculate the standard heat of reaction in \(\mathrm{kJ}\) for \(\mathrm{Ca}(\mathrm{s}), \mathrm{Cl}_{2}(\mathrm{g})\) and \(\mathrm{H}_{2} \mathrm{O}\) reacting to form \(\mathrm{CaCl}_{2}\) (aq, \(r=10\) ). (c) Speculate about why the standard heat of reaction in forming calcium chloride hexahydrate cannot be measured directly by reacting the anhydrous salt with water in a calorimeter.

A methanol-synthesis reactor is fed with a gas stream at \(220^{\circ} \mathrm{C}\) consisting of 5.0 mole\% methane, \(25.0 \%\) CO, \(5.0 \% \mathrm{CO}_{2},\) and the remainder hydrogen. The reactor and feed stream are at \(7.5 \mathrm{MPa}\). The primary reaction occurring in the reactor and its associated equilibrium constant are $$\begin{array}{l}\mathrm{CO}+2 \mathrm{H}_{2} \rightleftharpoons \mathrm{CH}_{3} \mathrm{OH} \\\K=\frac{y_{\mathrm{CH}, \mathrm{OH}} y_{\mathrm{H}_{2}}}{y_{\mathrm{CO}} y_{H_{2}}^{2} P^{2}}=\exp \left(\begin{array}{c}21.225+\frac{9143.6}{T}-7.492 \ln T \\ +4.076 \times 10^{-3} T-7.161 \times 10^{-8} T^{2}\end{array}\right)\end{array}$$ where \(T\) is in kelvins. The product stream may be assumed to reach equilibrium at \(250^{\circ} \mathrm{C}\). (a) Determine the composition (mole fractions) of the product stream and the percentage conversions of CO and \(\mathrm{H}_{2}\). (b) Neglecting the effect of pressure on enthalpies, estimate the amount of heat (kJ/mol feed gas) that must be added to or removed from (state which) the reactor. (c) Calculate the extent of reaction and heat removal rate (kJ/mol feed) for reactor temperatures between \(200^{\circ} \mathrm{C}\) and \(400^{\circ} \mathrm{C}\) in \(50^{\circ} \mathrm{C}\) increments. Use these results to obtain an estimate of the adiabatic reaction temperature. (d) Determine the effect of pressure on the reaction by evaluating extent of conversion and rate of heat transfer at \(1 \mathrm{MPa}\) and \(15 \mathrm{MPa}\). (e) Considering the results of your calculations in Parts (c) and (d), propose an explanation for selection of the initial reaction conditions of \(250^{\circ} \mathrm{C}\) and \(7.5 \mathrm{MPa}\).

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