/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 31 Propane gas enters a continuous ... [FREE SOLUTION] | 91Ó°ÊÓ

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Propane gas enters a continuous adiabatic heat exchanger \(^{17}\) at \(40^{\circ} \mathrm{C}\) and \(250 \mathrm{kPa}\) and exits at \(240^{\circ} \mathrm{C}\). Superheated steam at \(300^{\circ} \mathrm{C}\) and 5.0 bar enters the exchanger flowing countercurrently to the propane and exits as a saturated liquid at the same pressure. (a) Taking as a basis 100 mol of propane fed to the exchanger, draw and label a process flowchart. Include in your labeling the volume of propane fed \(\left(\mathrm{m}^{3}\right),\) the mass of steam fed \((\mathrm{kg}),\) and the volume of steam fed \(\left(\mathrm{m}^{3}\right)\) (b) Calculate values of the labeled specific enthalpies in the following inlet-outlet enthalpy table for this process. $$\begin{array}{|l|cc|cc|} \hline \text { Species } & n_{\text {in }} & \hat{H}_{\text {in }} & n_{\text {out }} & \hat{H}_{\text {out }} \\ \hline \mathrm{C}_{3} \mathrm{H}_{8} & 100 \mathrm{mol} & \hat{H}_{\mathrm{a}}(\mathrm{kJ} / \mathrm{mol}) & 100 \mathrm{mol} & \hat{H}_{\mathrm{c}}(\mathrm{kJ} / \mathrm{mol}) \\ \mathrm{H}_{2} \mathrm{O} & m_{\mathrm{w}}(\mathrm{kg}) & \hat{H}_{\mathrm{b}}(\mathrm{kJ} / \mathrm{kg}) & m_{\mathrm{w}}(\mathrm{kg}) & \hat{H}_{\mathrm{d}}(\mathrm{kJ} / \mathrm{kg}) \\ \hline \end{array}$$ (c) Use an energy balance to calculate the required mass feed rate of the steam. Then calculate the volumetric feed ratio of the two streams ( \(\mathrm{m}^{3}\) steam fed \(/ \mathrm{m}^{3}\) propane fed). Assume ideal-gas behavior for the propane but not the steam and recall that the exchanger is adiabatic. (d) Calculate the heat transferred from the water to the propane ( \(k J / m^{3}\) propane fed). (Hint: Do an energy balance on either the water or the propane rather than on the entire heat exchanger.) (e) Over a period of time, scale builds up on the heat-transfer surface, resulting in a lower rate of heat transfer between the propane and the steam. What changes in the outlet streams would you expect to see as a result of the decreased heat transfer?

Short Answer

Expert verified
For propane, \(\hat{H}_{a}\) and \(\hat{H}_{c}\) can be found from thermodynamic tables at the given temperatures. The same applies for \(\hat{H}_{b}\) and \(\hat{H}_{d}\) for steam. Mass feed rate and heat transferred can be calculated from energy balance equations. Volumetric feed rate can be found using ideal gas law for propane and steam properties for steam. Scale affects heat transfer causing less heat exchange between propane and steam.

Step by step solution

01

Sketch the Flowchart

For part (a), sketch a flowchart with propane and steam coming into the adiabatic heat exchanger and exiting as heated propane and saturated water respectively. Importantly, mark the quantities asked in the exercise.
02

Calculate the Specific Enthalpies

In part (b), determine the specific enthalpies (\(\hat{H}_{in}\) and \(\hat{H}_{out}\)) for propane and steam using thermodynamic properties data tables, where you need to reference the state (temperature, pressure, and phase) of each substance.
03

Energy Balance and Mass Feed Rate

In part (c), apply the energy balance equation. As there are no other forms of energy involved and it's an adiabatic system (no heat is lost to surroundings), energy going in will equal to energy coming out. From this, calculate the mass feed rate of steam.
04

Volumetric Feed Ratio

Next, use the ideal gas law for the propane and steam volume from steam tables to derive the volumetric feed ratios of propane and steam.
05

Heat Transfer Calculation

In part (d), use the principle of energy conservation to calculate the heat transferred. It can be calculated from the change in enthalpy of propane and the feed rate.
06

Predict the Effect of Scale Build-up

Lastly, part (e) involves a qualitative analysis. As the heat transfer decreases because of scale build up, one would expect less heat to be transferred from steam to the propane, which would likely result in a lower exit temperature for the propane and a less condensed steam.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Heat Exchanger
A heat exchanger is a device that allows energy exchange between two fluids at different temperatures. In this exercise, propane gas and steam are flown through a continuous adiabatic heat exchanger. The goal is simple: transfer heat from one fluid to another without mixing them. By using metal walls and countercurrent flow, heat can be transferred effectively from the hotter steam to the cooler propane. This process is essential in many industrial applications, enabling processes like heating, cooling, or maintaining specific temperatures.

In a heat exchanger, the main objective is usually to achieve an energy balance, where the heat lost by the hot stream equals the heat gained by the cold stream. During operation, both streams can either increase or decrease in temperature, achieving the required outlet conditions. Awareness of process parameters like inlet and outlet temperatures, pressure conditions, and phase changes is important. It ensures design efficiency and operational stability of the heat exchanger unit.
Enthalpy Calculation
Enthalpy represents the total heat content of a fluid or a system, with both internal energy and the work done by the system to change its volume factored in. For calculations in processes involving heat exchange, like in this exercise, specific enthalpy in kilojoules per mole (kJ/mol for gases) or kilojoules per kilogram (kJ/kg for liquids) can be crucial.

To determine the heat transfer in our gas exchange, knowing the specific enthalpy helps us to calculate how much energy is being moved into or out of the stream. In the context of this problem, it's important to find the specific enthalpies of propane and steam at both the inlet and outlet. For this, one uses data from thermodynamic tables or charts that relate enthalpy to temperature, pressure, and, if applicable, phase changes during the process.
  • Inlet and outlet temperatures and pressures are key variables needed for accurate enthalpy evaluation.
  • Thermodynamic properties help understand phase changes, essential in determining specific enthalpy adjustments.
Understanding these enthalpy changes is key for any energy balance problem.
Ideal-Gas Behavior
Ideal-gas behavior is an assumption applied to gases that behave according to the ideal gas law, expressed as \(PV = nRT\). Here, \(P\) represents pressure, \(V\) is the volume, \(n\) is the amount of substance in moles, \(R\) is the ideal gas constant, and \(T\) is temperature in Kelvin. Assuming ideal-gas behavior simplifies calculations of volumetric flow and energy changes in processes.

In our exercise, propane is assumed to behave like an ideal gas. This makes it easier to calculate the volume of propane using the gas law, given the pressure and temperature conditions. The assumption is typically valid under high temperature and low pressure conditions, where intermolecular forces and volumes are negligible.
  • Predicts how gases expand, contract, and transfer heat when heated or cooled.
  • Assumptions are simplified but accurate enough for a first approximation in engineering calculations.
This concept is crucial because it allows engineers to predict process behaviors without complex calculations involving real gas behaviors.
Adiabatic Process
An adiabatic process refers to a thermodynamic process where no heat enters or leaves the system. This means that the system is thermally isolated, with all energy transfers being in the form of work or changes in internal energy. No energy is lost or gained as heat through its boundaries with the surroundings.

In the context of our heat exchanger scenario, being adiabatic implies that the exchange of energy between the propane and steam occurs solely between them without it being gained or lost to the surroundings. This condition is crucial for energy balance calculations, where the energy entering and leaving must be equal.
  • Ensures all energy in such a system is managed and conserved within the system.
  • Crucial for ensuring accuracy in energy and enthalpy calculations in systems designed with thermal isolation.
Adiabatic processes are common in engineering systems designed for efficiency and conservation of energy.

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Most popular questions from this chapter

As part of a design calculation, you must evaluate an enthalpy change for an obscure organic vapor that is to be cooled from \(1800^{\circ} \mathrm{C}\) to \(150^{\circ} \mathrm{C}\) in a heat exchanger. You search through all the standard references for tabulated enthalpy or heat capacity data for the vapor but have no luck at all, until you finally stumble on an article in the May 1922 Antarctican Journal of Obscure Organic Vapors that contains a plot of \(C_{p}\left[\operatorname{cal} /\left(\mathrm{g} \cdot^{\cdot} \mathrm{C}\right)\right]\) on a logarithmic scale versus \(\left[T\left(^{\circ} \mathrm{C}\right)\right]^{1 / 2}\) on a linear scale. The plot is a straight line through the points \(\left(C_{p}=0.329, T^{1 / 2}=7.1\right)\) and \(\left(C_{p}=0.533, T^{1 / 2}=17.3\right)\) (a) Derive an equation for \(C_{p}\) as a function of \(T.\) (b) Suppose the relationship of Part (a) turns out to be $$ C_{p}=0.235 \exp \left[0.0473 T^{1 / 2}\right] $$ and that you wish to evaluate $$ \Delta \hat{H}(\mathrm{cal} / \mathrm{g})=\int_{1800 \mathrm{c}}^{150^{\circ} \mathrm{C}} C_{p} d T $$ First perform the integration analytically, using a table of integrals if necessary; then write a spreadsheet or computer program to do it using Simpson's rule (Appendix A.3). Have the program evaluate \(C_{p}\) at 11 equally spaced points from \(150^{\circ} \mathrm{C}\) to \(1800^{\circ} \mathrm{C}\), estimate and print the value of \(\Delta H,\) and repeat the calculation using 101 points. What can you conclude about the accuracy of the numerical calculation?

An adiabatic membrane separation unit is used to dry (remove water vapor from) a gas mixture containing 10.0 mole \(\% \mathrm{H}_{2} \mathrm{O}(\mathrm{v}), 10.0\) mole \(\% \mathrm{CO},\) and the balance \(\mathrm{CO}_{2} .\) The gas enters the unit at \(30^{\circ} \mathrm{C}\) and flows past a semipermeable membrane. Water vapor permeates through the membrane into an air stream. The dried gas leaves the separator at \(30^{\circ} \mathrm{C}\) containing \(2.0 \mathrm{mole} \% \mathrm{H}_{2} \mathrm{O}(\mathrm{v})\) and the balance \(\mathrm{CO}\) and \(\mathrm{CO}_{2}\). Air enters the separator at \(50^{\circ} \mathrm{C}\) with an absolute humidity of \(0.002 \mathrm{kg} \mathrm{H}_{2} \mathrm{O} / \mathrm{kg}\) dry air and leaves at \(48^{\circ} \mathrm{C}\). Negligible quantities of \(\mathrm{CO}, \mathrm{CO}_{2}, \mathrm{O}_{2},\) and \(\mathrm{N}_{2}\) permeate through the membrane. All gas streams are at approximately 1 atm. (a) Draw and label a flowchart of the process and carry out a degree of freedom analysis to verify that you can determine all unknown quantities on the chart. (b) Calculate (i) the ratio of entering air to entering gas (kg humid air/mol gas) and (ii) the relative humidity of the exiting air. (c) List several desirable properties of the membrane. (Think about more than just what it allows and does not allow to permeate.)

The brakes on an automobile act by forcing brake pads, which have a metal support and a lining, to press against a disk (rotor) attached to the wheel. Friction between the pads and the disk causes the car to slow or stop. Each wheel has an iron brake disk with a mass of \(15 \mathrm{lb}_{\mathrm{m}}\) and two brake pads, each having a mass of \(11 \mathrm{b}_{\mathrm{m}}\). (a) Suppose an automobile is moving at 55 miles per hour when the driver suddenly applies the brakes and brings the car to a rapid halt. Take the heat capacity of the disk and brake pads to be \(0.12 \mathrm{Btu} /\left(\mathrm{lb}_{\mathrm{m}} \cdot^{\circ} \mathrm{F}\right)\) and assume that the car stops so rapidly that heat transfer from the disk and pads has been insignificant. Estimate the final temperature of the disk and pads if the car is (i) a Toyota Camry, which has a mass of about \(3200 \mathrm{Ib}_{\mathrm{m}},\) or (ii) a Cadillac Escalade, which has a mass of about \(5.900 \mathrm{lb}_{\mathrm{m}}.\) (b) Why are the linings on brake pads no longer made of asbestos? Your answer should provide information on specific issues or concerns caused by the use of asbestos.

Saturated propane vapor at \(2.00 \times 10^{2}\) psia is fed to a well- insulated heat exchanger at a rate of \(3.00 \times 10^{3} \mathrm{SCFH}\) (standard cubic feet per hour). The propane leaves the exchanger as a saturated liquid (i.e., a liquid at its boiling point) at the same pressure. Cooling water enters the exchanger at \(70^{\circ} \mathrm{F},\) flowing cocurrently (in the same direction) with the propane. The temperature difference between the outlet streams (liquid propane and water) is \(15^{\circ} \mathrm{F}\). (a) What is the outlet temperature of the water stream? (Use the Antoine equation.) Is the outlet water temperature less than or greater than the outlet propane temperature? Briefly explain. (b) Estimate the rate (Btu/h) at which heat must be transferred from the propane to the water in the heat exchanger and the required flow rate \(\left(1 \mathrm{b}_{\mathrm{m}} / \mathrm{h}\right)\) of the water. (You will need to write two separate energy balances.) Assume the heat capacity of liquid water is constant at \(1.00 \mathrm{Btu} /\left(\mathrm{lb}_{\mathrm{m}} \cdot^{\circ} \mathrm{F}\right)\) and neglect heat losses to the outside and the effects of pressure on the heat of vaporization of propane.

The heat capacities of a substance have been defined as $$C_{v}=\left(\frac{\partial \hat{U}}{\partial T}\right)_{V}, \quad C_{p}=\left(\frac{\partial \hat{H}}{\partial T}\right)_{P}$$ Use the defining relationship between \(\hat{H}\) and \(\hat{U}\) and the fact that \(\hat{H}\) and \(\hat{U}\) for ideal gases are functions only of temperature to prove that \(C_{p}=C_{v}+R\) for an ideal gas (Eq. \(8.3-12\) ).

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