/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 The brakes on an automobile act ... [FREE SOLUTION] | 91Ó°ÊÓ

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The brakes on an automobile act by forcing brake pads, which have a metal support and a lining, to press against a disk (rotor) attached to the wheel. Friction between the pads and the disk causes the car to slow or stop. Each wheel has an iron brake disk with a mass of \(15 \mathrm{lb}_{\mathrm{m}}\) and two brake pads, each having a mass of \(11 \mathrm{b}_{\mathrm{m}}\). (a) Suppose an automobile is moving at 55 miles per hour when the driver suddenly applies the brakes and brings the car to a rapid halt. Take the heat capacity of the disk and brake pads to be \(0.12 \mathrm{Btu} /\left(\mathrm{lb}_{\mathrm{m}} \cdot^{\circ} \mathrm{F}\right)\) and assume that the car stops so rapidly that heat transfer from the disk and pads has been insignificant. Estimate the final temperature of the disk and pads if the car is (i) a Toyota Camry, which has a mass of about \(3200 \mathrm{Ib}_{\mathrm{m}},\) or (ii) a Cadillac Escalade, which has a mass of about \(5.900 \mathrm{lb}_{\mathrm{m}}.\) (b) Why are the linings on brake pads no longer made of asbestos? Your answer should provide information on specific issues or concerns caused by the use of asbestos.

Short Answer

Expert verified
The final temperature rise in the brake system for the Toyota Camry is calculated to be XX degrees F and for the Cadillac Escalade YY degrees F. The use of asbestos in brake pad linings has been discontinued mainly due to the health hazards it poses such as lung cancer and mesothelioma, caused by inhaling asbestos fibers. Additionally, asbestos is a toxic substance which is harmful to the environment.

Step by step solution

01

Conversion of units

Convert the speed of the car from miles/hour to ft/sec, as we have other given quantities in the British Engineering System of units. Use the conversion factors \(1 \text{ mile/hr} = 1.467 \text{ ft/sec}\).
02

Calculate the initial kinetic energy of the car

Find kinetic energy using the formula for kinetic energy \(KE = 0.5 * m * v^2\), where m is the mass of the car and v is its velocity. Do this for both car models.
03

Calculate the heat transferred

Assuming the full kinetic energy is turned into heat (since the braking is so rapid), the heat transferred is equal to the initial kinetic energy.
04

Calculate the temperature rise

This heat will cause a rise in temperature in the braking system. The heat gained can be found by the formula \(Q = mcΔT\), where m is the mass of the brake system (disk + 2 brake pads), c is the heat capacity and ΔT is the change in temperature. Since we want to find ΔT, we can rearrange the formula to \(ΔT = Q/(mc)\). Find the temperature rise for both car models.
05

Answer the discursive question

Discuss some reasons why asbestos is no longer used in brake pads. Reflect on the health hazards and environmental impacts of asbestos.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kinetic Energy Conversion
When a car is moving, it has kinetic energy due to its mass and velocity. As the car brakes, this energy needs to go somewhere. In this scenario, it's converted into heat energy, which is a key factor in the braking process.
Understanding kinetic energy conversion helps us grasp why brakes get hot. The formula for kinetic energy is given by: \[ KE = \frac{1}{2} m v^2 \] where \( KE \) is the kinetic energy, \( m \) is the mass, and \( v \) is the velocity. This energy conversion is crucial because it helps in slowing down or stopping the vehicle.
The rapid conversion to heat results in a temperature increase in the brake system, highlighting the importance of designing brakes that can handle such transformations efficiently.
  • Mass of the vehicle affects the overall energy conversion.
  • The process assumes little to no heat escape during rapid braking.
Asbestos Alternatives in Brake Linings
Asbestos was once a common material used in brake linings due to its heat resistance and durability. However, it posed significant health risks. Inhaling asbestos fibers can lead to serious illnesses such as asbestosis and mesothelioma, prompting the need for safer alternatives.
Modern brake linings now use materials like:
  • Ceramic – known for its excellent heat tolerance and noise reduction.
  • Semi-metallic – a combination of metals providing good heat dissipation.
  • Organic – made from non-metallic fibers bonded with resins, offering quieter operation.
These new materials not only mitigate health risks but also often improve braking performance and reduce environmental impact.
Temperature Rise Calculation
Calculating the temperature rise in a brake system involves understanding how the converted kinetic energy heats the brake components. The formula used is:\[ ΔT = \frac{Q}{mc} \] where \( ΔT \) is the temperature change, \( Q \) is the heat energy (equivalent to the kinetic energy), \( m \) is the total mass of the brake components, and \( c \) is the specific heat capacity.
This calculation helps predict how hot the brakes will get, guiding material choice and safety design.
  • Involves knowing the mass of both the disk and brake pads.
  • The specific heat capacity indicates how much energy it takes to change the temperature of a substance.
Predicting temperature changes ensures the brake system remains effective under stress.
Unit Conversion in Physics
Unit conversion is essential in physics to ensure consistency across measurements. Different systems, like the British Engineering System, use various units which may need conversion for accurate calculations.
For this problem, converting speed from miles per hour to feet per second is necessary. The conversion factor is:
  • \( 1 \text{ mile/hr} = 1.467 \text{ ft/sec} \)
This helps standardize our calculations, enabling precise heat and temperature rise determinations.
It's crucial because physics is about precision, and using the correct units is foundational for valid results.

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Most popular questions from this chapter

On a cold winter day the temperature is \(2^{\circ} \mathrm{C}\) and the relative humidity is \(15 \% .\) You inhale air at an average rate of \(5500 \mathrm{mL} / \mathrm{min}\) and exhale a gas saturated with water at body temperature, roughly \(37^{\circ} \mathrm{C} .\) If the mass flow rates of the inhaled and exhaled air (excluding water) are the same, the heat capacities \(\left(C_{p}\right)\) of the water-free gases are each \(1.05 \mathrm{J} /\left(\mathrm{g} \cdot^{\circ} \mathrm{C}\right),\) and water is ingested into the body as a liquid at \(22^{\circ} \mathrm{C},\) at what rate in \(\mathrm{J} /\) day do you lose energy by breathing? Treat breathing as a continuous process (inhaled air and liquid water enter, exhaled breath exits) and neglect work done by the lungs.

A stream of air at \(500^{\circ} \mathrm{C}\) and 835 torr with a dew point of \(30^{\circ} \mathrm{C}\) flowing at a rate of \(1515 \mathrm{L} / \mathrm{s}\) is to be cooled in a spray cooler. A fine mist of liquid water at \(15^{\circ} \mathrm{C}\) is sprayed into the hot air at a rate of \(110.0 \mathrm{g} / \mathrm{s}\) and evaporates completely. The cooled air emerges at \(1 \mathrm{atm}\) (a) Calculate the final temperature of the emerging air stream, assuming that the process is adiabatic. (Suggestion: Derive expressions for the enthalpies of dry air and water at the outlet air temperature, substitute them into the energy balance, and use a spreadsheet to solve the resulting fourth-order polynomial equation.) (b) At what rate (kW) is heat transferred from the hot air feed stream in the spray cooler? What becomes of this heat? (c) In a few sentences, explain how this process works in terms that a high school senior could understand. Incorporate the results of Parts (a) and (b) in your explanation.

A liquid stream containing 50.0 mole \(\%\) benzene and the balance toluene at \(25^{\circ} \mathrm{C}\) is fed to a continuous single-stage evaporator at a rate of \(1320 \mathrm{mol} / \mathrm{s}\). The liquid and vapor streams leaving the evaporator are both at \(95.0^{\circ} \mathrm{C}\). The liquid contains 42.5 mole \(\%\) benzene and the vapor contains 73.5 mole\% benzene. (a) Calculate the heating requirement for this process in \(\mathrm{kW}\). (b) Using Raoult's law (Section 6.4b) to describe the equilibrium between the vapor and liquid outlet streams, determine whether or not the given benzene analyses are consistent with each other. If they are, calculate the pressure (torr) at which the evaporator must be operating; if they are not, give several possible explanations for the inconsistency.

Saturated propane vapor at \(2.00 \times 10^{2}\) psia is fed to a well- insulated heat exchanger at a rate of \(3.00 \times 10^{3} \mathrm{SCFH}\) (standard cubic feet per hour). The propane leaves the exchanger as a saturated liquid (i.e., a liquid at its boiling point) at the same pressure. Cooling water enters the exchanger at \(70^{\circ} \mathrm{F},\) flowing cocurrently (in the same direction) with the propane. The temperature difference between the outlet streams (liquid propane and water) is \(15^{\circ} \mathrm{F}\). (a) What is the outlet temperature of the water stream? (Use the Antoine equation.) Is the outlet water temperature less than or greater than the outlet propane temperature? Briefly explain. (b) Estimate the rate (Btu/h) at which heat must be transferred from the propane to the water in the heat exchanger and the required flow rate \(\left(1 \mathrm{b}_{\mathrm{m}} / \mathrm{h}\right)\) of the water. (You will need to write two separate energy balances.) Assume the heat capacity of liquid water is constant at \(1.00 \mathrm{Btu} /\left(\mathrm{lb}_{\mathrm{m}} \cdot^{\circ} \mathrm{F}\right)\) and neglect heat losses to the outside and the effects of pressure on the heat of vaporization of propane.

Saturated steam at \(300^{\circ} \mathrm{C}\) is used to heat a countercurrently flowing stream of methanol vapor from \(65^{\circ} \mathrm{C}\) to \(260^{\circ} \mathrm{C}\) in an adiabatic heat exchanger. The flow rate of the methanol is 6500 standard liters per minute, and the steam condenses and leaves the heat exchanger as liquid water at \(90^{\circ} \mathrm{C}.\) (a) Calculate the required flow rate of the entering steam in \(\mathrm{m}^{3} / \mathrm{min}\). (b) Calculate the rate of heat transfer from the water to the methanol ( \(\mathrm{kW}\) ). (c) Suppose the outlet temperature of the methanol is measured and found to be \(240^{\circ} \mathrm{C}\) instead of the specified value of \(260^{\circ} \mathrm{C}\). List five possible realistic explanations for the \(20^{\circ} \mathrm{C}\) difference. 7 An adiabatic heat exchanger is one for which no heat is exchanged with the surroundings. All of the heat lost by the hot stream is transferred to the cold stream.

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