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The specific internal energy of formaldehyde (HCHO) vapor at 1 atm and moderate temperatures is given by the formula $$\hat{U}(\mathrm{J} / \mathrm{mol})=25.96 T+0.02134 T^{2}$$ where \(T\) is in \(^{\circ} \mathrm{C}\) (a) Calculate the specific internal energies of formaldehyde vapor at \(0^{\circ} \mathrm{C}\) and \(200^{\circ} \mathrm{C}\). What reference temperature was used to generate the given expression for \(\hat{U} ?\) (b) The value of \(\hat{U}\) calculated for \(200^{\circ} \mathrm{C}\) is not the true value of the specific internal energy of formaldehyde vapor at this condition. Why not? (Hint: Refer back to Section 7.5a.) Briefly state the physical significance of the calculated quantity. (c) Use the closed system energy balance to calculate the heat (J) required to raise the temperature of 3.0 mol HCHO at constant volume from 0^0 C to 200^'C. List all of your assumptions. (d) From the definition of heat capacity at constant volume, derive a formula for \(C_{v}(T)\left[\mathrm{J} /\left(\mathrm{mol} \cdot^{\circ} \mathrm{C}\right)\right]\) Then use this formula and Equation \(8.3-6\) to calculate the heat \((\) J) required to raise the temperature of 3.0 mol of HCHO(v) at constant volume from 0^ C to 200^'C. [You should get the same result you got in Part (c).]

Short Answer

Expert verified
The internal energy of formaldehyde vapor at \(0^{\circ}C\) and \(200^{\circ}C\) can be calculated using the given expression. The calculated values are not the true values of the specific internal energy because it does not include the changes in state. The heat required to raise the temperature from \(0^{\circ}C\) to \(200^{\circ}C\) can be found using the energy balance and verification can be done using the formula of heat capacity at constant volume.

Step by step solution

01

Calculate Specific Internal Energies

Substitute \(T\) with \(0^{\circ} C\) and \(200^{\circ} C\) in the given formula to get internal energies at these temperatures. Also, look for the reference temperature where \(\hat{U} = 0\).
02

Discuss Physical Significance

The physical significance of the calculated quantity is the amount of energy required to heat formaldehyde vapor from the reference temperature to the given temperature at constant volume. It is not the true value because it does not account for the changes in state (from liquid to vapor).
03

Calculate Heat Required

The heat (q) required to raise the tempreature from \(0^{\circ} C\) to \(200^{\circ} C\) can be calculated by using the relation \(q = \Delta U = U(200^{\circ} C) - U(0^{\circ} C)\), where \(U(T)\) is the internal energy calculated using given formula.
04

Derive and Use Heat Capacity Formula

From the definition of heat capacity at constant volume (\(Cv\)), \(Cv = (\Delta U / \Delta T)\). Integration of this formula from \(T1\) to \(T2\) gives the heat required. Cross verify this value with the one calculated in step 3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Closed System Energy Balance
The concept of a closed system energy balance is central to understanding how energy transforms within a system that does not exchange mass with its surroundings. Consider a sealed container of gas; even though heat may enter or leave, the mass of the gas remains constant. When we apply this to calculating the change in the internal energy of a substance like formaldehyde vapor, the first step is to quantify the initial and final internal energy levels under constant volume conditions.

For instance, when raising the temperature of formaldehyde vapor from 0°C to 200°C, the change in specific internal energy (\(\frac{\text{J}}{\text{mol}}\)) can be found using the provided temperature-dependent function for \(\text{\(\text{U}\)}}\). You simply calculate the internal energy at both temperatures, and their difference reflects the net energy transfer in the form of heat (assuming no work is done, as is the case at constant volume). This straightforward approach is an illustration of the conservation of energy principle, fundamental to all closed system energy balances.
Heat Capacity at Constant Volume
Heat capacity at constant volume (\(C_v(T)\)) is an intrinsic property of a material that indicates how much heat energy is required to raise the temperature of a unit amount of substance by one degree Celsius at constant volume.

Derivation of \(C_v\)

From thermodynamics, the heat capacity is defined by the rate of change of internal energy with temperature. Mathematically, this is presented as \(C_v = \frac{\text{d}U}{\text{d}T}\), where \(U\) is internal energy and \(T\) is temperature. For a temperature-dependent heat capacity, this would involve integrating the expression over the temperature range of interest.

The close relationship between heat capacity and internal energy is why calculations from steps involving heat capacity should corroborate the findings from an energy balance, emphasizing the interconnected nature of these concepts.
Temperature Effects on Internal Energy
Internal energy is deeply affected by temperature changes, particularly in gases. The relationship between the two can often be described by a polynomial where each term represents energy contributions at different temperature conditions. In the case of formaldehyde vapor, the given formula shows a linear and a squared term as it relates to temperature, indicating the energy changes more rapidly at higher temperatures.

Understanding the Polynomial

The linear term (proportional to \(T\)) suggests a direct change with temperature, while the squared term (proportional to \(T^2\)) reveals a progressively greater impact as temperature increases. Together, these terms manifest the specific internal energy variations, which guide us in calculating the thermal energy required for a temperature-induced process, such as heating formaldehyde gas from one temperature to another. This understanding is crucial for accurately gauging the energy dynamic in response to temperature fluctuations.

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Most popular questions from this chapter

Estimate the heat of vaporization of diethyl ether at its normal boiling point using Trouton's rule and Chen's rule and compare the results with a tabulated value of this quantity. Calculate the percentage error that results from using each estimation. Then estimate \(\Delta \hat{H}_{\mathrm{v}}\) at \(100^{\circ} \mathrm{C}\) using Watson's correlation.

The brakes on an automobile act by forcing brake pads, which have a metal support and a lining, to press against a disk (rotor) attached to the wheel. Friction between the pads and the disk causes the car to slow or stop. Each wheel has an iron brake disk with a mass of \(15 \mathrm{lb}_{\mathrm{m}}\) and two brake pads, each having a mass of \(11 \mathrm{b}_{\mathrm{m}}\). (a) Suppose an automobile is moving at 55 miles per hour when the driver suddenly applies the brakes and brings the car to a rapid halt. Take the heat capacity of the disk and brake pads to be \(0.12 \mathrm{Btu} /\left(\mathrm{lb}_{\mathrm{m}} \cdot^{\circ} \mathrm{F}\right)\) and assume that the car stops so rapidly that heat transfer from the disk and pads has been insignificant. Estimate the final temperature of the disk and pads if the car is (i) a Toyota Camry, which has a mass of about \(3200 \mathrm{Ib}_{\mathrm{m}},\) or (ii) a Cadillac Escalade, which has a mass of about \(5.900 \mathrm{lb}_{\mathrm{m}}.\) (b) Why are the linings on brake pads no longer made of asbestos? Your answer should provide information on specific issues or concerns caused by the use of asbestos.

Among the best-known building blocks in nanotechnology applications are nanoparticles of noble metals. For example, colloidal suspensions of silver or gold nanoparticles (10-200 nm) exhibit vivid colors because of intense optical absorption in the visible spectrum, making them useful in colorimetric sensors. In the illustration shown below, a suspension of gold nanoparticles of a fairly uniform size in water exhibits peak absorption near a wavelength of \(525 \mathrm{nm}\) (near the blue region of the visible spectrum of light). When one views the solution in ambient (white) light, the solution appears wine-red because the blue part of the spectrum is largely absorbed. When the nanoparticles aggregate to form large particles, an optical absorption peak near \(600-700 \mathrm{nm}\) (near the red region of the visible spectrum) is observed. The breadth of the peak reflects a fairly broad particle size distribution. The solution appears bluish because the unabsorbed light reaching the eye is dominated by the short (blue-violet) wavelength region of the spectrum. since the optical properties of metallic nanoparticles are a strong function of their size, achieving a narrow particle size distribution is an important step in the development of nanoparticle applications. A promising way to do so is laser photolysis, in which a suspension of particles of several different sizes is irradiated with a high-intensity laser pulse. By carefully selecting the wavelength and energy of the pulse to match an absorption peak of one of the particle sizes (e.g., irradiating the red solution in the diagram with a \(525 \mathrm{nm}\) laser pulse), particles of or near that size can be selectively vaporized. (a) A spherical silver nanoparticle of diameter \(D\) at \(25^{\circ} \mathrm{C}\) is to be heated to its normal boiling point and vaporized with a pulsed laser. Considering the particle a closed system at constant pressure, write the energy balance for this process, look up the physical properties of silver that are required in the energy balance, and perform all the required substitutions and integrations to derive an expression for the energy \(Q_{\text {abs }}(\mathrm{J})\) that must be absorbed by the particle as a function of \(D(\mathrm{nm})\) (b) The total energy absorbed by a single particle \(\left(Q_{\text {abs }}\right)\) can also be calculated from the following relation: $$ Q_{\mathrm{abs}}=F A_{\mathrm{p}} \sigma_{\mathrm{abs}} $$ where \(F\left(\mathrm{J} / \mathrm{m}^{2}\right)\) is the energy in a single laser pulse per unit spot area (area of the laser beam) and \(A_{\mathrm{p}}\left(\mathrm{m}^{2}\right)\) is the total surface area of the nanoparticle. The effectiveness factor, \(\sigma_{\mathrm{ahs}},\) accounts for the efficiency of absorption by the nanoparticle at the wavelength of the laser pulse and is dependent on the particle size, shape, and material. For a spherical silver nanoparticle irradiated by a laser pulse with a peak wavelength of \(532 \mathrm{nm}\) and spot diameter of \(7 \mathrm{mm}\) with \(D\) ranging from 40 to \(200 \mathrm{nm}\), the following empirical equation can be used for \(\sigma_{\mathrm{abs}}\) $$ \sigma_{\mathrm{abs}}=\frac{1}{4}\left[0.05045+2.2876 \exp \left(-\left(\frac{D-137.6}{41.675}\right)^{2}\right)\right] $$ where \(\sigma_{\text {abs }}\) and the leading \(\frac{1}{4}\) are dimensionless and \(D\) has units of nm. Use the results of Part (a) to determine the minimum values of F required for complete vaporization of single nanoparticles with diameters of \(40.0 \mathrm{nm}, 80.0 \mathrm{nm},\) and \(120.0 \mathrm{nm}\). If the pulse frequency of the laser is \(10 \mathrm{Hz}\) (i.e., 10 pulses per second), what is the minimum laser power \(P(\mathrm{W})\) required for each of those values of D? (Hint: Set up a dimensional equation relating \(P\) to \(F\).) (c) Suppose you have a suspension of a mixture of \(D=40 \mathrm{nm}\) and \(D=120 \mathrm{nm}\) spherical silver nanoparticles and a \(10 \mathrm{Hz} / 532 \mathrm{nm}\) pulsed laser source with a \(7 \mathrm{nm}\) diameter spot and adjustable power. Describe how you would use the laser to produce a suspension of particles of only a single size and state what that size would be.

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