/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Liquid water is fed to a boiler ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Liquid water is fed to a boiler at \(24^{\circ} \mathrm{C}\) and 10 bar and is converted at constant pressure to saturated steam. (a) Use the steam tables to calculate \(\Delta \hat{H}(\mathrm{kJ} / \mathrm{kg})\) for this process, and then determine the heat input required to produce \(15,800 \mathrm{m}^{3} / \mathrm{h}\) of steam at the exit conditions. Assume the kinetic energy of the entering liquid is negligible and that steam is discharged through a 15 -cm ID pipe. (b) How would the calculated value of the heat input change if you did not neglect the kinetic energy of the inlet water and if the inner diameter of the steam discharge pipe were \(13 \mathrm{cm}\) (increase, decrease, stay the same, or no way to tell without more information)?

Short Answer

Expert verified
The change in enthalpy (\(\Delta \hat{H}\)) for this process can be obtained from the steam tables for given initial and final conditions. This is used to calculate the heat input required to produce 15800 cubic m/h of steam under given exit conditions. The heed input increases when the kinetic energy of the incoming water is not neglected and the diameter of the steam discharge pipe decreases.

Step by step solution

01

Determining the enthalpy change

Entire problem is at constant pressure 10 bar. We first need to find out the enthalpy (\(\hat{H}\)) values from the steam tables corresponding to given initial and final conditions:1. Enthalpy of liquid at \(24^{\circ} \mathrm{C}\) and 10 bar2. Enthalpy of saturated steam at the 10 bar.After that, we can determine the change in enthalpy for the process as:\(\Delta \hat{H} = \hat{H}_{\text{steam}} - \hat{H}_{\text{water}}\)
02

Calculating the heat input

Once we have the value for \(\Delta \hat{H}\), we can determine the heat input using the formula:Heat input = Volume of steam produced (15,800 cubic m/h) * Density of steam at given conditions * \(\Delta \hat{H}\)
03

Evaluating the effect of kinetic energy

If we do not neglect the kinetic energy, it will add to the energy input, since kinetic energy contributes to the total energy of the steam. As this energy was previously considered negligible, including it would increase the calculated value. Moreover, the kinetic energy depends on the velocity of the fluid which in turn depends on the inner diameter of the pipe. Decreasing the diameter from 15cm to 13cm for the same flow rate essentially means the steam velocity should be higher, therefore increasing the kinetic energy.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Steam Tables
Steam tables are invaluable resources in the study of thermodynamics, especially when dealing with problems involving water and steam. These tables provide detailed information about the properties of water in various states, such as liquid (subcooled or compressed) and steam (saturated or superheated). In a typical steam table, you'll find key properties like pressure, temperature, enthalpy, and entropy, which are all crucial for analyzing energy processes.
In the exercise, the steam tables help find the enthalpy values of water and steam at specific conditions. For example, you start by identifying two important points: the enthalpy of liquid water at 24°C under 10 bar and the enthalpy of saturated steam at the same pressure. Using these values, one can calculate the change in enthalpy between the initial water state and the final steam state. This is essential for determining the energy required for converting water into steam at a constant pressure, making steam tables fundamental in thermodynamic calculations.
Enthalpy Change
Enthalpy change (\(\Delta \hat{H}\)) is a crucial concept in thermodynamics, representing the heat absorbed or released during a process at constant pressure. In the context of the given exercise, it is about finding out how much energy is needed to convert liquid water to steam. This is done by taking the difference between the enthalpy values of steam and water, as derived from steam tables.
Calculating the enthalpy change is straightforward: find the specific enthalpy of the final state (saturated steam) and subtract the enthalpy of the initial state (liquid water). The result, \(\Delta \hat{H}\), is expressed in kilojoules per kilogram (kJ/kg), indicating the energy change per kilogram of water converted. This value is then used to compute the total heat input required for the entire volume of steam being produced, which is crucial for designing and operating boilers and other thermal systems effectively.
Kinetic Energy
Kinetic energy in a thermodynamics context often assumes a minor role, but it can still be significant, especially in fluid systems with changes in velocity, such as in pipes. It is given by the formula \( KE = \frac{1}{2}mv^2 \), where \(m\) is mass and \(v\) is velocity. In the original exercise, the kinetic energy of incoming liquid water was considered negligible initially, simplifying calculations.
However, changes in conditions, like the diameter of the steam discharge pipe, can alter fluid velocity and thus its kinetic energy significantly. If the diameter is reduced, maintaining the same flow rate necessitates a higher velocity, leading to increased kinetic energy. Factoring this kinetic energy into the total energy balance ensures a more precise calculation of heat input required for steam generation. By acknowledging kinetic energy, engineers can account for all energy exchanges in dynamic steam systems and optimize efficiency.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Superheated steam at 40 bar absolute and \(500^{\circ} \mathrm{C}\) flows at a rate of \(250 \mathrm{kg} / \mathrm{min}\) to an adiabatic turbine, where it expands to 5 bar. The turbine develops \(1500 \mathrm{kW}\). From the turbine the steam flows to a heater, where it is reheated isobarically to its initial temperature. Neglect kinetic energy changes. (a) Write an energy balance on the turbine and use it to determine the outlet stream temperature. (b) Write an energy balance on the heater and use it to determine the required input (kW) to the steam. (c) Verify that an overall energy balance on the two-unit process is satisfied. (d) Suppose the turbine inlet and outlet pipes both have diameters of 0.5 meter. Show that it is reasonable to neglect the change in kinetic energy for this unit.

Your friend has asked you to help move a 60 inch \(\times 78\) inch mattress with a mass of 75 Ib \(_{\mathrm{m}}\). The two of you position it horizontally in an open flat-bed trailer that you hitch to your car. There is nothing available to tie the mattress to the trailer, but you know there is a risk of the mattress being lifted from the trailer by the air flowing over it and perform the following calculations: (a) Although the conditions do not exactly match those for which the Bemoulli equation is applicable, use the equation to get a rough estimate of how fast you can drive (miles/h) before the mattress is lifted. Assume the velocity of air above the mattress equals the velocity of the car, the pressure difference between the top and bottom of the mattress equals the weight of the mattress divided by the mattress cross-sectional area, and air has a constant density of \(0.075 \mathrm{lb}_{\mathrm{m}} / \mathrm{ft}^{3}\). What is your result? (b) You see that your friend also has several boxes of books. Since you would like to drive at 60 miles per hour, what weight of books ( \(\left(\mathrm{b}_{\mathrm{f}}\right)\) do you need to put on the mattress to hold it in place?

Energy may be produced from solid waste in two ways: (1) generate methane from anaerobic decomposition of the waste and burn it (landfill-gas-to-energy, or LFGTE) or(2) burn the waste directly (waste-to-energy, or WTE). The heat generated by either method can be used to produce steam, which impinges on a turbine rotor connected to a generator to produce electricity. LFGTE produces about 215 k Wh electricity/ton of waste, and WTE produces roughly 600 kWh/ton of waste. The average output of a large power plant is 1 GW, which is enough to supply the annual residential energy consumption of a city of roughly 800,000 people. (a) The current rate of municipal solid-waste generation in the United States is approximately 413 million tons per year. If all of it were used for energy recovery, how many \(1 \mathrm{GW}\) power plants could LFGTE supply? How many if WTE is used? A useful source of information regarding LFGTE is the U.S. EPA Landfill Methane Outreach Program, http://www.epa.gov//mop/; the Waste-to-Energy Research and Technology Council at Columbia University provides useful information on WTE, http://www.seas.columbia.edu/earth/wtert/; and information on natural gas can be obtained from the U.S. Energy Information Administration, http:// www.eia.doe.gov/oil_gas/natural_gas/info_glance/natural_gas.html.

Methane enters a 3 -cm ID pipe at \(30^{\circ} \mathrm{C}\) and 10 bar with an average velocity of \(5.00 \mathrm{m} / \mathrm{s}\) and emerges at a point 200 m lower than the inlet at \(30^{\circ} \mathrm{C}\) and 9 bar. (a) Without doing any calculations, predict the signs ( \(+\) or \(-\) ) of \(\Delta \dot{E}_{\mathrm{k}}\) and \(\Delta \dot{E}_{\mathrm{p}},\) where \(\Delta\) signifies (outlet - inlet). Briefly explain your reasoning. (b) Calculate \(\Delta \dot{E}_{\mathrm{k}}\) and \(\Delta \dot{E}_{\mathrm{p}}(\mathrm{W}),\) assuming that the methane behaves as an ideal gas. (c) If you determine that \(\Delta \dot{E}_{\mathrm{k}} \neq-\Delta \dot{E}_{\mathrm{p}},\) explain how that result is possible.

If a system expands in volume by an amount \(\Delta V\left(\mathrm{m}^{3}\right)\) against a constant restraining pressure \(P\left(\mathrm{N} / \mathrm{m}^{2}\right),\) a quantity \(P \Delta V(\mathrm{J})\) of energy is transferred as expansion work from the system to its surroundings. Suppose that the following four conditions are satisfied for a closed system: (a) the system expands against a constant pressure (so that \(\Delta P=0\) ); (b) \(\Delta E_{\mathrm{k}}=0 ;\) (c) \(\Delta E_{\mathrm{p}}=0 ;\) and (d) the only work done by or on the system is expansion work. Prove that under these conditions, the energy balance simplifies to \(Q=\Delta H\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.