/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Prove that for an ideal gas, \(\... [FREE SOLUTION] | 91Ó°ÊÓ

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Prove that for an ideal gas, \(\hat{U}\) and \(\hat{H}\) are related as \(\hat{H}=\hat{U}+R T\), where \(R\) is the gas constant. Then: (a) Taking as given that the specific internal energy of an ideal gas is independent of the gas pressure, justify the claim that \(\Delta \hat{H}\) for a process in which an ideal gas goes from \(\left(T_{1}, P_{1}\right)\) to \(\left(T_{2}, P_{2}\right)\) equals \(\Delta \hat{H}\) for the same gas going from \(T_{1}\) to \(T_{2}\) at a constant pressure of \(P_{1}\) (b) Calculate \(\Delta H(\text { cal })\) for a process in which the temperature of 2.5 mol of an ideal gas is raised by \(50^{\circ} \mathrm{C},\) resulting in a specific internal energy change \(\Delta \hat{U}=3500 \mathrm{cal} / \mathrm{mol}\)

Short Answer

Expert verified
The change in enthalpy \(\Delta H\) for a gas going from (T1, P1) to (T2, P2) is same as the change in enthalpy for the gas when it goes from T1 to T2 at a constant pressure of P1. Also, for the second part for a temperature change of 50 degrees Celsius and specific internal energy change of 3500 cal/mol, we calculate the change in enthalpy \(\Delta H\) through the provided equation.

Step by step solution

01

Determine Enthalpy from given equation

According to the question, the relationship between enthalpy (H) and internal energy (U) for an ideal gas is given by \(\hat{H}=\hat{U}+R T\), where R is the gas constant and T is the temperature. This indicates that the enthalpy of a system is equal to the internal energy plus the product of the gas constant and the temperature.
02

Justify claim for variation in enthalpy with given conditions

The specific internal energy U is given to be independent of the pressure. Therefore the change in enthalpy \(\Delta \hat{H}\) of a process, for a gas that goes from (T1, P1) to (T2, P2) depends solely on the change in temperature. This implies that \(\Delta \hat{H}\) for the same gas going from T1 to T2 at a constant pressure P1 is equal to \(\Delta \hat{H}\) for a process in which the gas goes from (T1, P1) to (T2, P2). This is because, in both cases, the change in enthalpy would depend upon the change in temperature only.
03

Calculate changes in Enthalpy

For part (b) of the question, it's given that the temperature of 2.5 moles of gas is changed by 50 degrees Celsius. Also, the specific internal energy change \(\Delta \hat{U}\) = 3500 cal/mol. We can use our equation, \(\Delta \hat{H}=\Delta \hat{U}+R \Delta T\), substituting \(\Delta \hat{U}\) and \(\Delta T\), and remembering to convert the temperature change to Kelvin (by adding 273.15 to the temperature in Celsius). The gas constant R in these units is 1.987 cal/K.mol. After computation, we get the value for \(\Delta H\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Internal Energy
The concept of internal energy is crucial in understanding thermodynamics and the behavior of gases. Internal energy, denoted as \( U \) for a specific quantity of substance (or \( \hat{U} \) for specific internal energy per unit mass or mole), represents the total energy contained within a system due to the kinetic and potential energies of the molecules. In the context of an ideal gas, the internal energy is entirely kinetic in nature, because the particles are considered to be point masses with no intermolecular forces.

For an ideal gas, the internal energy is independent of pressure and volume, and depends solely on temperature. This is derived from the kinetic theory of gases, which states that the average kinetic energy of gas particles is directly proportional to the absolute temperature. Therefore, when dealing with an ideal gas, any change in internal energy \( \Delta \hat{U} \) comes from a change in temperature. This is a key factor in understanding the thermal properties of ideal gases and leads to the simplification of many thermodynamic equations.
Gas Constant
The gas constant, represented by \( R \), is a fundamental parameter in the equations of state for gases. It is the constant of proportionality that appears in the ideal gas law and translates physical conditions into energy units. For an ideal gas, the ideal gas law \( PV=nRT \) relates the product of pressure \( P \) and volume \( V \) to the product of the amount of substance in moles \( n \) and temperature \( T \).

The gas constant has different values depending on the units used for pressure, volume, and temperature. In the International System of Units (SI), \( R \) is approximately 8.314 J/(mol\cdot K). However, for calculations involving calories, \( R \) is usually given as 1.987 cal/(mol\cdot K). Determining the correct value for \( R \) is essential for accurate thermodynamic calculations concerning ideal gases.
Temperature Dependence of Enthalpy
The temperature dependence of enthalpy in an ideal gas reveals a direct relationship between the enthalpy change \( \Delta \hat{H} \) and the temperature change \( \Delta T \). Since the specific internal energy \( \hat{U} \) of an ideal gas is independent of pressure and determined solely by temperature, the enthalpy change can be expressed as \( \Delta \hat{H} = \Delta \hat{U} + R \Delta T \).

This means that if the temperature of an ideal gas increases, its enthalpy also increases, and vice versa. Other factors, such as pressure or volume, do not directly affect the change in enthalpy of an ideal gas. This simplifies calculations for various thermodynamic processes, as changes in pressure at constant temperature do not entail changes in enthalpy.
Ideal Gas Law
The ideal gas law is a corner-stone in the study of gases and thermodynamics. It provides a clear and simple equation that relates four state variables: pressure \( P \), volume \( V \), temperature \( T \) and the number of moles \( n \) of the gas. The law is succinctly captured in the formula \( PV=nRT \), indicating that the product of pressure and volume of a gas is directly proportional to the product of its mole number and the absolute temperature, with the gas constant \( R \) as the proportionality factor.

This intrinsic relationship helps in understanding how changing one variable could affect the others for an ideal gas. This law assumes that the gas molecules have no size and no intermolecular forces, which is, of course, an approximation but holds reasonably well for many gases under standard conditions. In practice, the ideal gas law simplifies the study of gas behavior and is foundational in explaining how gases expand, contract, and exchange energy with their surroundings.

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Most popular questions from this chapter

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You recently purchased a large plot of land in the Amazon jungle at an extremely low cost. You are quite pleased with yourself until you arrive there and find that the nearest source of electricity is 1500 miles away, a fact that your brother-in-law, the real estate agent, somehow forgot to mention. since the local hardware store does not carry 1500 -mile-long extension cords, you decide to build a small hydroelectric generator under a 75-m high waterfall located nearby. The flow rate of the waterfall is 10 \(^{5} \mathrm{m}^{3} / \mathrm{h}\), and you anticipate needing \(750 \mathrm{kW} \cdot \mathrm{h} / \mathrm{wk}\) to run your lights, air conditioner, and television. Calculate the maximum power theoretically available from the waterfall and see if it is sufficient to meet your needs.

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