/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 The vapor leaving the top of a d... [FREE SOLUTION] | 91Ó°ÊÓ

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The vapor leaving the top of a distillation column goes to a condenser in which either total or partial condensation takes place. If a total condenser is used, a portion of the condensate is returned to the top of the column as \(r e f l u x\) and the remaining liquid is taken off as the overhead product (or distillate). (See Problem 6.63.) If a partial condenser is used, the liquid condensate is returned as reflux and the uncondensed vapor is taken off as the overhead product.The overhead product from an \(n\) -butane- \(n\) -pentane distillation column is 96 mole \(\%\) butane. The temperature of the cooling fluid limits the condenser temperature to \(40^{\circ} \mathrm{C}\) or higher.(a) Using Raoult's law, estimate the minimum pressure at which the condenser can operate as a partial condenser (i.e., at which it can produce liquid for reflux) and the minimum pressure at which it can operate as a total condenser. In terms of dew point and bubble point, what do each of these pressures represent for the given temperature?(b) Suppose the condenser operates as a total condenser at \(40^{\circ} \mathrm{C}\), the production rate of overhead product is \(75 \mathrm{kmol} / \mathrm{h}\), and the mole ratio of reflux to overhead product is \(1.5: 1 .\) Calculate the molar flow rates and compositions of the reflux stream and the vapor feed to the condenser.(c) Suppose now that a partial condenser is used, with the reflux and overhead product in equilibrium at \(40^{\circ} \mathrm{C}\) and the overhead product flow rate and reflux-to-overhead product ratio having the values given in Part (b). Calculate the operating pressure of the condenser and the compositions of the reflux and vapor feed to the condenser.

Short Answer

Expert verified
The minimum pressure at which the condenser can operate as a partial and total condenser can be found using Raoult's law and are representative of the bubble point and dew point respectively. For the total condenser scenario, molar flow rates and stream compositions can be found using known parameters and assuming the reflux stream composition is similar to the distillate as total condensation occurs. For the partial condenser, operating parameters can be found using Raoult's law considering vapor-liquid equilibrium and performing iteration to find composition. The actual values depend on Antoine's coefficients and algebraic calculations.

Step by step solution

01

Find the minimum pressure for both partial and total condenser

Firstly, let's apply Raoult's law for the partial and total condenser situations. Raoult's law states the vapor pressure of a solvent in a solution will be lower than the vapor pressure of the solvent in its pure state. Considering a vapor-liquid equilibrium mixture of butane and pentane at \(40^{\circ} \mathrm{C}\), we can use the Antoine's equation to estimate the vapor pressures of the pure components and through Raoult's law infer the pressure of the mixture. The minimum pressure for the partial condenser represents the bubble point and for the total condenser represents the dew point.
02

Calculate molar flow rates and compositions for total condenser

To estimate the molar flow rates and compositions of the reflux stream and the vapor feed to the condenser, we must first calculate the total molar flow. This can be done by multiplying the production rate of the overhead product by the mole ratio of reflux to overhead product and then adding the production rate of the overhead product. We also know that the composition of the reflux stream is the same as that of the distillate since the condenser is operating as a total condenser.
03

Calculate operating pressure and compositions for partial condenser

For the case of a partial condenser, we know that the temperature is the same and the flow rate and the reflux ratio are the same as in the case of total condensing. We also know that the condenser operates at a pressure such that the liquid and vapor leaving the condenser are in equilibrium. Therefore, we can use Raoult’s law to calculate this pressure, an iteration process can be used to solve for the compositions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Raoult's Law and its Applications
Raoult's law is fundamental in understanding the behavior of solutions in chemical processes. It states that the partial vapor pressure of each component in an ideal mixture is proportional to the mole fraction of the component present in the solution. Formally expressed as:
\( P_i = x_i \cdot P_{i}^{*} \)
where \( P_i \) is the partial pressure of component \( i \) in the vapor phase, \( x_i \) is the mole fraction of component \( i \) in the liquid mixture, and \( P_{i}^{*} \) is the vapor pressure of the pure component \( i \) at the same temperature. This principle is pivotal when dealing with vapor-liquid equilibrium situations, such as predicting the composition of a vapor resulting from a liquid solution.

By applying Raoult's law, we can determine, for example, the minimum operating pressure of a condenser in distillation processes. The law comes into play when considering both partial and total condensation. In the case of a distillation column, for a total condenser, Raoult's law helps in defining the dew point pressure, whereas for a partial condenser, it assists in determining the bubble point pressure. Both are indicative of the state at which a mixture begins to condense (bubble point) or starts to vaporize (dew point), essential information for proper column operation.
Distillation Column Operation
A distillation column is a critical piece of equipment in separating components based on differences in their volatilities. The operation of a distillation column involves the introduction of a feed, which is then heated until it vaporizes. As the vapor rises through the column, it cools and condenses. This process is facilitated by trays or packing within the column, which encourage contact between the rising vapor and descending liquid (reflux), promoting the exchange of heat and mass.

In a distillation column's operation, both reboilers and condensers play pivotal roles. The reboiler adds energy to create vapor at the bottom of the column, while the condenser removes energy to condense vapor at the top. The reflux, a portion of the condensed vapor, is returned to the top of the column to achieve the desired separation. The composition and flow rates of the streams in a distillation process can be manipulated to optimize the separation efficiency and energy usage by understanding and controlling variables such as reflux ratio, column pressure, and tray efficiency.
Vapor-Liquid Equilibrium
Vapor-liquid equilibrium (VLE) is a condition where a liquid and its vapor phase are in balance at a given temperature and pressure, meaning that the rates of evaporation and condensation are equal. For a multicomponent system, VLE conditions imply that the composition of the vapor and the composition of the liquid are stable and do not change with time.

VLE plays a significant role in distillation as it governs how the composition of vapor and liquid will vary throughout the column. The use of phase diagrams and VLE data enables engineers to predict the outcome of separation processes—crucial for designing and optimizing distillation equipment. Understanding VLE is often needed for accurate calculations in distillation design, especially when dealing with non-ideal mixtures where interactions between molecules deviate from Raoult’s Law. For students dealing with such complexities, grasping the concept of activity coefficients and their impact on vapor and liquid phases is key to a comprehensive understanding of the subject matter.
Antoine's Equation and its Utility
Antoine's equation is a practical and straightforward means of estimating the vapor pressure of pure substances. This is particularly important in chemical process engineering when applying Raoult's Law to real-world problems. Antoine's equation is given by:
\( \log P = A - \frac{B}{C+T} \)
where \( P \) represents the vapor pressure of the substance, \( T \) its temperature, and \( A \), \( B \), and \( C \) are empirical constants unique to each substance.

The accuracy of Antoine's equation makes it valuable for the prediction of vapor pressures at various temperatures, a crucial step in many VLE calculations. When working with distillation columns, for instance, Antoine’s equation helps in determining the conditions at which condensation will begin. This assists in calculating the minimum operating pressures for condensers and provides an understanding of the equilibrium state within the column. For students tackling exercises involving these calculations, comprehending how to apply Antoine's equation and interpret its results is critical to success in chemical process engineering education.

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Most popular questions from this chapter

The solubility coefficient of a gas may be defined as the number of cubic centimeters (STP) of the gas that dissolves in \(1 \mathrm{cm}^{3}\) of a solvent under a partial pressure of 1 atm. The solubility coefficient of \(\mathrm{CO}_{2}\) in water at \(20^{\circ} \mathrm{C}\) is \(0.0901 \mathrm{cm}^{3} \mathrm{CO}_{2}(\mathrm{STP}) / \mathrm{cm}^{3} \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\). (a) Calculate the Henry's law constant in atm/mole fraction for \(\mathrm{CO}_{2}\) in \(\mathrm{H}_{2} \mathrm{O}\) at \(20^{\circ} \mathrm{C}\) from the given solubility coefficient. (b) How many grams of \(\mathrm{CO}_{2}\) can be dissolved in a \(12-\mathrm{oz}\) bottle of soda at \(20^{\circ} \mathrm{C}\) if the gas above the soda is pure \(\mathrm{CO}_{2}\) at a gauge pressure of 2.5 atm ( 1 liter \(=33.8\) fluid ounces)? Assume the liquid properties are those of water. (c) What volume would the dissolved \(C O_{2}\) occupy if it were released from solution at body temperature and pressure \(-37^{\circ} \mathrm{C}\) and 1 atm?

A fuel cell is an electrochemical device in which hydrogen reacts with oxygen to produce water and DC electricity. A 1-watt proton-exchange membrane fuel cell (PEMFC) could be used for portable applications such as cellular telephones, and a \(100-\mathrm{kW}\) PEMFC could be used to power an automobile. The following reactions occur inside the PEMFC:Anode: \(\quad \mathrm{H}_{2} \rightarrow 2 \mathrm{H}^{+}+2 \mathrm{e}^{-}\) Cathode: \(\quad \frac{1}{2} \mathrm{O}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \rightarrow \mathrm{H}_{2} \mathrm{O}\) Overall: \(\quad \overline{\mathrm{H}}_{2}+\frac{1}{2} \mathrm{O}_{2} \rightarrow \mathrm{H}_{2} \mathrm{O}\) A flowchart of a single cell of a PEMFC is shown below. The complete cell would consist of a stack of such cells in series, such as the one shown in Problem 9.19.The cell consists of two gas channels separated by a membrane sandwiched between two flat carbonpaper electrodes- -the anode and the cathode- -that contain imbedded platinum particles. Hydrogen flows into the anode chamber and contacts the anode, where \(\mathrm{H}_{2}\) molecules are catalyzed by the platinum to dissociate and ionize to form hydrogen ions (protons) and electrons. The electrons are conducted throughthe carbon fibers of the anode to an extemal circuit, where they pass to the cathode of the next cell in the stack. The hydrogen ions permeate from the anode through the membrane to the cathode.Humid air is fed into the cathode chamber, and at the cathode \(\mathrm{O}_{2}\) molecules are catalytically split to form oxygen atoms, which combine with the hydrogen ions coming through the membrane and electrons coming from the external circuit to form water. The water desorbs into the cathode gas and is carried out of the cell. The membrane material is a hydrophilic polymer that absorbs water molecules and facilitates the transport of the hydrogen ions from the anode to the cathode. Electrons come from the anode of the cell at one end of the stack and flow through an extemal circuit to drive the device that the fuel cell is powering, while the electrons coming from the device flow back to the cathode at the opposite end of the stack to complete the circuit. is important to keep the water content of the cathode gas between upper and lower limits. If the content reaches a value for which the relative humidity would exceed \(100 \%,\) condensation occurs at the cathode (flooding), and the entering oxygen must diffuse through a liquid water film before it can react. The rate of this diffusion is much lower than the rate of diffusion through the gas film normally adjacent to the cathode, and so the performance of the fuel cell deteriorates. On the other hand, if there is not enough water in the cathode gas (less than \(85 \%\) relative humidity), the membrane dries out and cannot transport hydrogen efficiently, which also leads to reduced performance. 400-sell 300-yolt PEMFS anerates at stady state witha nonwer outnul of 36 k W, The air fod to It is important to keep the water content of the cathode gas between upper and lower limits. If the content reaches a value for which the relative humidity would exceed \(100 \%,\) condensation occurs at the cathode (flooding), and the entering oxygen must diffuse through a liquid water film before it can react. The rate of this diffusion is much lower than the rate of diffusion through the gas film normally adjacent to the cathode, and so the performance of the fuel cell deteriorates. On the other hand, if there is not enough water in the cathode gas (less than \(85 \%\) relative humidity), the membrane dries out and cannot transport hydrogen efficiently, which also leads to reduced performance.A 400-cell 300-volt PEMFC operates at steady state with a power output of 36 kW. The air fed to the cathode side is at \(20.0^{\circ} \mathrm{C}\) and roughly 1.0 atm (absolute) with a relative humidity of \(70.0 \%\) and a volumetric flow rate of \(4.00 \times 10^{3}\) SLPM (standard liters per minute). The gas exits at \(60^{\circ} \mathrm{C}\). (a) Explain in your own words what happens in a single cell of a PEMFC. (b) The stoichiometric hydrogen requirement for a PEMFC is given by \(\left(n_{\mathrm{Hz}}\right)_{\text {conanmad }}=I N / 2 F,\) where \(I\) is the current in amperes (coulomb/s), \(N\) is the number of single cells in the fuel cell stack, and \(F\) is the Faraday constant, 96,485 coulombs of charge per mol of electrons. Derive this expression. (Hint: Recall that since the cells are stacked in series the same current flows through each one, and the same quantity of hydrogen must be consumed in each single cell to produce that current at each anode.) (c) Use the expression of Part (b) to determine the molar rates of oxygen consumed and water generated in the unit with the given specifications, both in units of mol/min. (Remember that power = voltage \(\times\) current.) Then determine the relative humidity of the cathode exit stream, \(h_{\mathrm{r} \text { rout. }}\) (d) Determine the minimum cathode inlet flow rate in SLPM to prevent the fuel cell from flooding ( \(h_{\mathrm{r}, \text { out }}=100 \%\) ) and the maximum flow rate to prevent it from drying \(\left(h_{\mathrm{r}, \text { out }}=85 \%\right)\) .

The vapor pressure of an organic solvent is \(50 \mathrm{mm}\) Hg at \(25^{\circ} \mathrm{C}\) and \(200 \mathrm{mm} \mathrm{Hg}\) at \(45^{\circ} \mathrm{C}\). The solvent is the only species in a closed flask at \(35^{\circ} \mathrm{C}\) and is present in both liquid and vapor states. The volume of gas above the liquid is \(150 \mathrm{mL}\). (a) Estimate the amount of the solvent \((\mathrm{mol})\)contained in the gas phase. (b) What assumptions did you make? How would your answer change if the species dimerized (one molecule results from two molecules of the species combining)?

Recovery and processing of various oils are important elements of the agricultural and food industries. For example, soybean hulls are removed from the beans, which are then flaked and contacted with hexane. The hexane extracts soybean oil and leaves very little oil in the residual solids. The solids are dried at an elevated temperature, and the dried solids are used to feed livestock or further processed to extract soy protein. The gas stream leaving the dryer is at \(80^{\circ} \mathrm{C}\) 1 atm absolute, and 50\% relative saturation.(a) To recover hexane, the gas leaving the dryer is fed to a condenser, which operates at 1 atm absolute. The gas leaving the condenser contains 5.00 mole \(\%\) hexane, and the hexane condensate is recovered at a rate of \(1.50 \mathrm{kmol} / \mathrm{min}\). (b) In an altemative arrangement, the gas leaving the dryer is compressed to 10.0 atm and the temperature simultancously is increased so that the relative saturation remains at \(50 \% .\) The gas then is cooled at constant pressure to produce a stream containing 5.00 mole \(\%\) hexane. Calculate the final gas temperature and the ratio of volumetric flow rates of the gas streams leaving and entering the condenser. State any assumptions you make.(c) What would you need to know to determine which of processes (a) and (b) is more cost- effective?

A gas mixture containing 85.0 mole \(\% \mathrm{N}_{2}\) and the balance \(n\) -hexane flows through a pipe at a rate of \(100.0 \mathrm{m}^{3} / \mathrm{h} .\) The pressure is 2.00 atm absolute and the temperature is \(100^{\circ} \mathrm{C}\). (a) What is the molar flow rate of the gas in \(\mathrm{kmol} / \mathrm{h}\) ? (b) Is the gas saturated? If not, to what temperature ( \(^{C} C\) ) would it have to be cooled at constant pressure in order to begin condensing hexane? (c) To what temperature ( \(C\) ) would the gas have to be cooled at constant pressure in order to condense \(80 \%\) of the hexane?

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