/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 75 A catalytic reactor is used to p... [FREE SOLUTION] | 91Ó°ÊÓ

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A catalytic reactor is used to produce formaldehyde from methanol in the reaction $$\mathrm{CH}_{3} \mathrm{OH} \rightarrow \mathrm{HCHO}+\mathrm{H}_{2}$$ A single-pass conversion of \(60.0 \%\) is achieved in the reactor. The methanol in the reactor product is separated from the formaldehyde and hydrogen in a multiple-unit process. The production rate of formaldehyde is 900.0 kg/h. (a) Calculate the required feed rate of methanol to the process ( \(\mathrm{kmol} / \mathrm{h}\) ) if there is no recycle. (b) Suppose the unreacted methanol is recovered and recycled to the reactor and the single-pass conversion remains 60\%. Without doing any calculations, prove that you have enough information to determine the required fresh feed rate of methanol (kmol/h) and the rates (kmol/h) at which methanol enters and leaves the reactor. Then perform the calculations. (c) The single-pass conversion in the reactor, \(X_{\mathrm{sp}},\) affects the costs of the reactor \(\left(C_{\mathrm{r}}\right)\) and the separation process and recycle line \(\left(C_{\mathrm{s}}\right) .\) What effect would you expect an increased \(X_{\mathrm{sp}}\) would have on each of these costs for a fixed formaldehyde production rate? (Hint: To get a \(100 \%\) singlepass conversion you would need an infinitely large reactor, and lowering the single-pass conversion leads to a need to process greater amounts of fluid through both process units and the recycle line.) What would you expect a plot of \(\left(C_{\mathrm{r}}+C_{\mathrm{s}}\right)\) versus \(X_{\mathrm{sp}}\) to look like? What does the design specification \(X_{\mathrm{sp}}=60 \%\) probably represent?

Short Answer

Expert verified
a) The required feed rate of methanol for the process (without recycling) is calculated using the yield and single-pass conversion rate. \nvb) With recycling, fresh feed rate of methanol and the rates at which methanol enters and leaves the reactor can all be obtained from the mass balance equation. \nc) The effect of single-pass conversion on costs can be deduced as an increased single pass conversion would increase reactor costs due to more required conversion but decrease separation and recycle costs due to less methanol present to separate and recycle. The resulting cost curve would be a trade-off between these two competing costs, introducing an optimal single-pass conversion. The specified 60% single pass conversion likely represents this optimal operational point.

Step by step solution

01

Calculate required feed rate of Methanol

First, find the amount of methanol required using the yield relation as \( Yield = \frac{Formaldehyde}{Methanol} \), for no recycle. A single-pass conversion of 60% is mentioned which means that 60% of the initial methanol is converted to formaldehyde. Using this relationship and the production rate of formaldehyde, we can find the feed rate for methanol.
02

Calculate fresh feed rate of Methanol with recycling

The conversion ratio still remains at 60% when the unreacted methanol is recovered and recycled. The flow rates can be determined based on this percentage, and the principle of mass conservation can be used to establish relations between the reactants and products at the reactor inlet and outlet.
03

Effect of Single-pass conversion on cost

We then address how an increase in single-pass conversion, \(X_{sp}\), would impact the costs of the reactor, \(C_{r}\), and the separation process, \(C_{s}\). An intuitive understanding of the system helps in interpreting the effects of increasing converter efficiency on system costs. The cost versus conversion curve is a common concept in industrial processes which must also be discussed here.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Catalytic Reactor
A catalytic reactor is a specialized vessel designed to carry out chemical reactions with the help of a catalyst. In the context of formaldehyde production, the catalyst facilitates the conversion of methanol into formaldehyde and hydrogen. It speeds up the reaction by lowering the activation energy needed, without being consumed in the process.
Catalytic reactors come in various forms, such as fixed-bed, fluidized-bed, and tubular designs, each suited to different types of reactions and operating conditions. The choice of reactor impacts the efficiency and yield of the desired product.
  • Fixed-Bed Reactors: These contain a packed bed of catalyst and are ideal for gas phase reactions.
  • Fluidized-Bed Reactors: In these, a fluidized state of solid catalyst particles offers better heat and mass transfer.
  • Tubular Reactors: These are used for reactions occurring in a continuous flow of materials through a tube filled with catalyst.
Understanding the role of the catalytic reactor in your chemical process is key to optimizing production and efficiency.
Formaldehyde Production
Formaldehyde production from methanol occurs via a chemical reaction where methanol is converted into formaldehyde and hydrogen. The reaction can be represented as \(\mathrm{CH}_{3}\mathrm{OH} \rightarrow \mathrm{HCHO} + \mathrm{H}_{2}\).
Formaldehyde is an important industrial chemical used in the production of resins, plastics, and preservatives.
The efficiency of formaldehyde production is significantly affected by various factors:
  • Reaction Temperature: High temperatures generally increase the conversion rate but may also lead to side reactions.
  • Pressure: Optimal pressures can enhance the rate of reaction.
  • Catalyst: The type and condition of the catalyst influence the speed and selectivity of the reaction.
Maintaining controlled reaction conditions is critical to achieving high yields of formaldehyde.
Single-Pass Conversion
Single-pass conversion refers to the percentage of a reactant converted into a product during one pass through the reactor. For the methanol-to-formaldehyde reaction, a 60% single-pass conversion means that 60% of the methanol feed is converted into formaldehyde in one pass through the catalytic reactor.
A higher single-pass conversion is desired because it decreases the amount of unreacted methanol, which needs separation and possible recycling. However, reaching 100% single-pass conversion is unrealistic, as it would require an infinitely large reactor, driving up costs significantly.
The conversion efficiency is a balancing act between improving reactor performance and managing costs. Generally, increasing single-pass conversion reduces the volume needing recycling, thereby lowering separation costs but potentially increasing reactor costs when trying to achieve near-complete conversion.
Methanol Feed Rate
The methanol feed rate is the amount of methanol fed into the reactor over a specified time, usually expressed in kmol/h. It is crucial for determining the production scale and ensuring adequate amounts are available to meet demand.
To calculate the required methanol feed rate, we use the production target for formaldehyde and the single-pass conversion rate. For example, if you desire a formaldehyde production rate of 900 kg/h and the single-pass conversion is 60%, the methanol feed rate must be calculated to ensure enough reactant is available to meet this target.
With recycling systems in place, the initial methanol feed rate might be adjusted since unreacted methanol can be circulated back to the reactor. This affects the fresh feed rate, as the effective rate might differ significantly from the initial input when recycling unreacted methanol.

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Most popular questions from this chapter

Oxygen consumed by a living organism in aerobic reactions is used in adding mass to the organism and/or the production of chemicals and carbon dioxide. since we may not know the molecular compositions of all species in such a reaction, it is common to define the ratio of moles of \(\mathrm{CO}_{2}\) produced per mole of \(\mathrm{O}_{2}\) consumed as the respiratory quotient, \(R Q,\) where $$R Q=\frac{n_{\mathrm{CO}_{2}}}{n_{\mathrm{O}_{2}}}\left(\text { or } \frac{\dot{n}_{\mathrm{CO}_{2}}}{\dot{n}_{\mathrm{O}_{2}}}\right)$$ since it generally is impossible to predict values of \(R Q\), they must be determined from operating data. Mammalian cells are used in a bioreactor to convert glucose to glutamic acid by the reaction $$\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}+a \mathrm{NH}_{3}+b \mathrm{O}_{2} \rightarrow p \mathrm{C}_{5} \mathrm{H}_{9} \mathrm{NO}_{4}+q \mathrm{CO}_{2}+r \mathrm{H}_{2} \mathrm{O}$$ The feed to the bioreactor comprises \(1.00 \times 10^{2} \mathrm{mol} \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6} / \mathrm{day}, 1.20 \times 10^{2} \mathrm{mol} \mathrm{NH}_{3} / \mathrm{day},\) and \(1.10 \times\) \(10^{2}\) mol \(\mathrm{O}_{2} /\) day. Data on the system show that \(R Q=0.45 \mathrm{mol} \mathrm{CO}_{2}\) produced/mol \(\mathrm{O}_{2}\) consumed. (a) Determine the five stoichiometric coefficients and the limiting reactant. (b) Assuming that the limiting reactant is consumed completely, calculate the molar and mass flow rates of all species leaving the reactor and the fractional conversions of the non-limiting reactants.

A fuel oil is fed to a furnace and burned with \(25 \%\) excess air. The oil contains \(87.0 \mathrm{wt} \% \mathrm{C}, 10.0 \% \mathrm{H},\) and 3.0\% S. Analysis of the furnace exhaust gas shows only \(\mathrm{N}_{2}, \mathrm{O}_{2}, \mathrm{CO}_{2}, \mathrm{SO}_{2},\) and \(\mathrm{H}_{2} \mathrm{O}\). The sulfur dioxide emission rate is to be controlled by passing the exhaust gas through a scrubber, in which most of the \(\mathrm{SO}_{2}\) is absorbed in an alkaline solution. The gases leaving the scrubber (all of the \(\mathrm{N}_{2}, \mathrm{O}_{2},\) and \(\mathrm{CO}_{2}\), and some of the \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{SO}_{2}\) entering the unit) pass out to a stack. The scrubber has a limited capacity, however, so that a fraction of the furnace exhaust gas must be bypassed directly to the stack. At one point during the operation of the process, the scrubber removes \(90 \%\) of the \(\mathrm{SO}_{2}\) in the gas fed to it, and the combined stack gas contains 612.5 ppm (parts per million) \(\mathrm{SO}_{2}\) on a dry basis; that is, every million moles of dry stack gas contains 612.5 moles of \(\mathrm{SO}_{2}\). Calculate the fraction of the exhaust bypassing the scrubber at this moment.

A fuel oil is analyzed and found to contain 85.0 wt\% carbon, \(12.0 \%\) elemental hydrogen (H), \(1.7 \%\) sulfur, and the remainder noncombustible matter. The oil is burned with \(20.0 \%\) excess air, based on complete combustion of the carbon to \(\mathrm{CO}_{2}\), the hydrogen to \(\mathrm{H}_{2} \mathrm{O}\), and the sulfur to \(\mathrm{SO}_{2}\). The oil is burned completely, but \(8 \%\) of the carbon forms CO. Calculate the molar composition of the stack gas.

Eggs are sorted into two sizes (large and extra large) at the Cheerful Chicken Coop. Recently, the economic downturn has not allowed Cheerful Chicken to repair the egg-sorting machine bought in 2000. Instead, the company has Chick Poulet, one of the firm's sharper-eyed employees, stamp the big eggs with a "Large" rubber stamp in her right hand and the really big eggs with an "X-large" stamp in her left as the eggs go by on a conveyor belt. Down the line, another employee puts the eggs into one of two hoppers, each egg according to its stamp. On average Chick breaks \(8 \%\) of the 120 eggs that pass by her each minute. At the same time, a check of the "X-large" stream reveals a flow rate of 70 eggs/min, of which 8 eggs/min are broken. (a) Draw and label a flowchart for this process. (b) Write and solve balances about the egg sorter on total eggs and broken eggs. (c) How many "large" eggs leave the plant each minute, and what fraction of them are broken? (d) Is Chick right- or left-handed?

A liquid mixture contains \(60.0 \mathrm{wt} \%\) ethanol \((\mathrm{E}), 5.0 \mathrm{wt} \%\) of a dissolved solute \((\mathrm{S}),\) and the balance water. A stream of this mixture is fed to a continuous distillation column operating at steady state. Product streams emerge at the top and bottom of the column. The column design calls for the product streams to have equal mass flow rates and for the top stream to contain 90.0 wt\% ethanol and no S. (a) Assume a basis of calculation, draw and fully label a process flowchart, do the degree-of-freedom analysis, and verify that all unknown stream flows and compositions can be calculated. (Don't do any calculations yet.) (b) Calculate (i) the mass fraction of \(S\) in the bottom stream and (ii) the fraction of the ethanol in the feed that leaves in the bottom product stream (i.e., \(\mathrm{kg} \mathrm{E}\) in bottom stream/kg \(\mathrm{E}\) in feed) if the process operates as designed. (c) An analyzer is available to determine the composition of ethanol-water mixtures. The calibration curve for the analyzer is a straight line on a plot on logarithmic axes of mass fraction of ethanol, \(x\) (kg E/kg mixture), versus analyzer reading, \(R\). The line passes through the points \((R=15, x=\) 0.100) and \((R=38, x=0.400)\). Derive an expression for \(x\) as a function of \(R(x=\cdots\) ) based on the calibration, and use it to determine the value of \(R\) that should be obtained if the top product stream from the distillation column is analyzed. (d) Suppose a sample of the top stream is taken and analyzed and the reading obtained is not the one calculated in Part (c). Assume that the calculation in Part (c) is correct and that the plant operator followed the correct procedure in doing the analysis. Give five significantly different possible causes for the deviation between \(R_{\text {measured and }} R_{\text {prediced }}\), including several assumptions made when writing the balances of Part (c). For each one, suggest something that the operator could do to check whether it is in fact the problem.

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