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At \(25^{\circ} \mathrm{C},\) an aqueous solution containing \(35.0 \mathrm{wt} \% \mathrm{H}_{2} \mathrm{SO}_{4}\) has a specific gravity of \(1.2563 .\) A quantity of the \(35 \%\) solution is needed that contains 195.5 kg of \(\mathrm{H}_{2} \mathrm{SO}_{4}\). (a) Calculate the required volume (L) of the solution using the given specific gravity. (b) Estimate the percentage error that would have resulted if pure-component specific gravities of \(\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{SG}=1.8255)\) and water had been used for the calculation instead of the given specific gravity of the mixture.

Short Answer

Expert verified
The required volume of the solution is approximately 445L. If the pure-component specific gravities had been used for the calculation, the percentage error that would have resulted could have been calculated by carrying out the same steps as above with the average of the pure-component specific gravities instead of the ones given.

Step by step solution

01

Calculate mass of solution

Start by calculating the mass of the solution that contains 195.5 kg of H2SO4. Since the solution is 35 wt%, the total mass of solution is \(195.5 kg / 0.35 = 558.57 kg\).
02

Convert mass to volume

Next, convert that mass into volume using the specific gravity of the solution which is given as 1.2563. The specific gravity is the ratio of the density of a substance to the density of a reference substance; in our case it's water, which has a density of 1 g/cm^3. Therefore, the density of the solution is \(1.2563 g/cm^3 = 1256.3 kg/m^3\), and thus its volume is \(558.57 kg / 1256.3 kg/m^3 = 0.445 m^3 \). To convert this into litres, use the fact that 1 m^3 = 1000 L, giving 445L.
03

Estimating percentage error

To estimate the percentage error one would have made if the specific gravities of the components had been used, first calculate the average specific gravity of the solution as the weighted average of the specific gravities of H2SO4 and water, using the weight percent of H2SO4 (35%) as the weight. This gives \(SG_{avg} = 0.35*1.8255 + 0.65*1 = 1.289\). Then, calculate the volume using this average specific gravity and compare it to the volume found in Step 2. The percentage error would be \( |(V_{avg} - V_{measured}) / V_{measured}| x 100\% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Engineering Principles
Chemical engineering principles play a pivotal role in analyzing and designing processes that transform raw materials into valuable products. One such principle involves the understanding and application of specific gravity in calculations, which is crucial for designing equipment and processes in the chemical industry.

Specific gravity, symbolized as SG, is a dimensionless quantity that represents the ratio of a substance's density to that of a standard reference, typically water at 4°C (39°F). The significance of specific gravity lies in its ability to relate a substance’s density to a well-known reference, allowing engineers to calculate essential parameters like the mass and volume of liquids without needing to measure density directly.

This parameter becomes especially important when dealing with mixtures. For example, in the field of process engineering, calculating the mass and volume of a chemical solution is critical for process design, safety assessments, and quality control. By incorporating specific gravity into these calculations, engineers are equipped to make accurate and informed decisions regarding the production and handling of chemical solutions.
Solution Concentration
Solution concentration is a key concept in chemical engineering and refers to the amount of a substance (solute) present in a specified quantity of solvent. Weight percent (wt%) is a common unit of concentration in the industry, representing the mass of the solute compared to the total mass of the solution.

For instance, the problem given deals with an aqueous solution containing 35.0 wt% of H2SO4 (sulfuric acid). This means that for every 100 kg of solution, there are 35 kg of H2SO4. Knowing the concentration of the solution helps to further understand the relationship between the mass of the solute and the total mass of the solution which is critical for preparing solutions with desired properties, optimizing reactions, and scaling up processes from the lab to production scale.

In practice, obtaining an accurate concentration is crucial for the preparation of reagents, medication formulations, and various other applications in fields ranging from pharmaceuticals to water treatment. By understanding solution concentration, chemical engineers can ensure that the desired reactions occur under optimal conditions, efficiently and safely.
Density and Volume Conversion
Density and volume are intrinsically linked properties of substances, and converting between them is a fundamental aspect of chemical engineering calculations. Density is a measure of how much mass of a substance is contained within a specific volume. When performing specific gravity calculations, the conversion between mass and volume is essential.

As illustrated in the exercise, once the mass of a solution is determined, one can find the volume by utilizing the density (or the specific gravity as a proxy for density when compared to water). The conversion requires a clear understanding of the relationship: density = mass/volume, which can be rearranged to find the volume if the mass and density are known.

The ability to convert between density and volume allows engineers to design processes and equipment appropriately. It also plays a significant role in tasks like material selection, quality control, and ensuring compliance with safety regulations. For example, in the context of the exercise, accurately converting the mass of H2SO4 to the corresponding volume of the solution is critical for any application where precise volumes are needed, such as in the mixing of chemical reactants or the packaging of chemicals for distribution.

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