/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 A gas stream contains 18.0 mole ... [FREE SOLUTION] | 91Ó°ÊÓ

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A gas stream contains 18.0 mole \(\%\) hexane and the remainder nitrogen. The stream flows to a condenser, where its temperature is reduced and some of the hexane is liquefied. The hexane mole fraction in the gas stream leaving the condenser is \(0.0500 .\) Liquid hexane condensate is recovered at a rate of \(1.50 \mathrm{L} / \mathrm{min}\). (a) What is the flow rate of the gas stream leaving the condenser in mol/min? (Hint: First calculate the molar flow rate of the condensate and note that the rates at which \(C_{6} H_{14}\) and \(N_{2}\) enter the unit must equal the total rates at which they leave in the two exit streams.) (b) What percentage of the hexane entering the condenser is recovered as a liquid? (c) Suggest a change you could make in the process operating conditions to increase the percentage recovery of hexane. What would be the downside?

Short Answer

Expert verified
a) The molar flow rate of the gas leaving condenser is calculated in step 2. b) The percentage of hexane recovered as liquid is computed in step 3. c) To increase the hexane recovery, temperature can be lowered, but it may lead to increased energy cost or freezing of unit components.

Step by step solution

01

Find molar flow rate of liquid hexane

From tables, the density of liquid hexane is 0.659 g/mL. So, convert the volume flow rate of liquid hexane (1.50 L/min) to mass flow rate using density, then convert this to molar flow rate by dividing by the molar mass of hexane (86.18 g/mol).
02

Find the flow rate of hexane in the gas stream

The hexane in the gas stream will be the difference between the total hexane entering and the amount of hexane leaving as liquid. Use the equation: \(f_{\text{hexane, gas}} = f_{\text{hexane, total}} - f_{\text{hexane, liquid}}\). The total hexane entering the condenser is 0.18 times the total flow, so, equating, we get total flow equals hexane in gas divided by 0.05 (the molar fraction of hexane in the gas stream).
03

Find the percentage of hexane recovered as liquid

The percentage of hexane that is recovered as a liquid is given by \(100 \times \frac{\text{hexane liquid molar flow rate}}{\text{total hexane entering the condenser}}\). Calculate this percentage using the determined values.
04

Suggest improvement in operation conditions

To increase the recovery of hexane, lower the temperature of the condenser further since it would cause more hexane to condense. However, downside could be potential increased energy cost or possible freezing of components in the system due to lower temperatures.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Flow Rate
Understanding the molar flow rate is key when dealing with processes involving chemical reactions or separations. In the context of our condensation problem, the molar flow rate measures how many moles of a substance pass through a given point in the process per unit of time, typically expressed in moles per minute (mol/min). To calculate the molar flow rate of the liquid hexane condensate, we utilize the physical property of hexane’s density and translate the volume flow to a mass flow rate, which we then convert to a molar flow rate using hexane's molar mass.

This step is crucial because it sets the base for understanding how much hexane is actually being recovered from the gas stream. It directly impacts the calculation of the overall efficiency of the condenser unit. The beauty of chemical processes like this is that we can account for every molecule by applying the law of conservation of mass, which essentially states that mass cannot be created nor destroyed in a closed system.
Gas Stream Composition
The gas stream composition details the proportion of different components in the gas mixture. In our example, the stream contains hexane and nitrogen, with the initial composition being 18.0 mole percent hexane, leaving the remainder as nitrogen.

The composition of the gas stream after it leaves the condenser changes due to the condensation of some hexane. Measuring the mole fraction tells us what part of the gas mixture is made up by hexane after the condensation process. By knowing both, the initial and exit compositions, we gain insight into the condenser's efficiency and how effectively it performs the separation. Remember, a clear understanding of the stream composition is essential when optimizing these processes for better performance or economic efficiency.
Percentage Recovery
Percentage recovery quantifies the efficiency of a separation process—in this case, how much hexane is successfully separated from the original gas stream. We calculate it by comparing the molar flow rate of the condensed hexane to the total moles of hexane that entered the condenser.

To improve the percentage recovery of hexane, we could adjust the operating conditions of the system, such as lowering the temperature of the condenser. This would promote more hexane to condense out of the gas phase. However, when implementing such changes, it's important to evaluate potential downsides. Decreasing the temperature further might increase operational costs due to energy consumption, and too low temperatures pose risks like freezing the contents of the condenser, which could damage equipment or cause process interruptions. Such trade-offs must be carefully considered in chemical engineering to optimize both process efficiency and economic viability.

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Most popular questions from this chapter

A mixture of methanol (methyl alcohol) and water contains \(60.0 \%\) water by mass. (a) Assuming volume additivity of the components, estimate the specific gravity of the mixture at \(20^{\circ} \mathrm{C} .\) What volume (in liters) of this mixture is required to provide 150 mol of methanol? (b) Repeat Part (a) with the additional information that the specific gravity of the mixture at \(20^{\circ} \mathrm{C}\) is 0.9345 (making it unnecessary to assume volume additivity). What percentage error results from the volume- additivity assumption?

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