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A storage tank containing oil ( \(\mathrm{SG}=0.92\) ) is 10.0 meters high and 16.0 meters in diameter. The tank is closed, but the amount of oil it contains can be determined from the gauge pressure at the bottom. (a) A pressure gauge connected to the bottom of the tank was calibrated with the top of the tank open to the atmosphere. The calibration curve is a plot of height of oil, \(h(\mathrm{m}),\) versus \(P_{\text {geuge }}(\mathrm{kPa}) .\) Sketch the expected shape of this plot. What height of oil would lead to a gauge reading of \(68 \mathrm{kPa} ?\) What would be the mass (kg) of oil in the tank corresponding to this height? (b) An operator observes that the pressure gauge reading is 68 kPa and notes the corresponding liquid height from the calibration curve. What he did not know was that the absolute pressure above the liquid surface in the tank was \(115 \mathrm{kPa}\) when he read the gauge. What is the actual height of the oil? (Assume atmospheric pressure is \(101 \mathrm{kPa}\).)

Short Answer

Expert verified
The height of the oil corresponding to a gauge reading of 68 kPa is approximately 7.54 m, and the corresponding mass of oil is around 911,600 kg. However, if the absolute pressure above the liquid surface in the tank was 115 kPa when the gauge was read, the actual height of the oil is approximately 19.9 m.

Step by step solution

01

Calculation of the height of oil

Using the formula for fluid pressure at a depth, we have \(P = \rho gh\), where \(P\) is the pressure, \(\rho\) is the density of the fluid, \(g\) is acceleration due to gravity and \(h\) is the height of the fluid above the point. The density of oil \(\rho\) can be found by multiplying the specific gravity of oil with the density of water ( \(1,000 \, kg/m^3\)). Substituting the known values, we get \(h = P / (\rho g) = 68000 / (0.92*1000*9.81)\).
02

Calculation of the mass of the oil

The volume of the oil can be calculated using the height from Step 1 and the diameter of the tank (assuming the tank is filled up to the calculated height), using the formula for volume of a cylinder \(V = \pi r^2 h\), where \(r\) is the radius and \(h\) is the height. The mass of the oil can then be calculated using the formula \(m = \rho V\), where \(\rho\) is the density and \(V\) is the volume. From Step 1, we already have the density and the calculated volume of the oil.
03

Calculation of actual oil height

The net pressure at the bottom of the tank is the sum of the absolute pressure above the liquid surface and the pressure due to the liquid column. Thus, the actual height of the oil can be recalculated using the formula from Step 1, but using the total pressure (115kPa + 68kPa) instead of the gauge pressure. Therefore, \(h = (115000+68000) / (0.92*1000*9.81)\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fluid Density
Understanding fluid density is essential when dealing with the principles of fluid mechanics, particularly in problems like calculating the pressure at a point within a fluid. Fluid density, typically denoted as \(\rho\), is defined as the mass per unit volume of a fluid substance. It is often expressed in the units of kilograms per cubic meter (kg/m^3) in the International System of Units (SI).

For instance, in our exercise example, the fluid in question is oil with a specific gravity (SG) of 0.92. Specific gravity is a dimensionless quantity that compares the density of a fluid to the density of a reference substance, usually water at 4°C for liquids. Since the density of water at standard conditions is approximately 1,000 kg/m^3, the density of the oil can be calculated by multiplying the specific gravity of oil with the density of water, which is \(\rho_{oil} = 0.92 \times 1000 \, \text{kg/m}^3 = 920 \, \text{kg/m}^3\).

Understanding the relationship between specific gravity and fluid density allows us to compute various other parameters such as fluid pressure and mass, critical to solving problems within fluid dynamics and engineering.
Hydrostatic Pressure
Hydrostatic pressure, often referred to simply as fluid pressure, is the pressure exerted by a fluid at equilibrium at any given point within the fluid due to the force of gravity. It increases proportionally with depth measured from the surface because of the increasing weight of fluid exerting downward force from above. The formula to calculate the hydrostatic pressure at a depth \(h\) is given by \(P = \rho gh\), where \(P\) is the pressure, \(\rho\) is the density of the fluid, \(g\) is the acceleration due to gravity (approximately 9.81 m/s^2 on Earth), and \(h\) is the height of the fluid above the point in question.

For a practical example, consider the exercise where the oil in a tank exerts hydrostatic pressure on the gauge at the bottom. By knowing the fluid density, which we've calculated previously, and the height of the oil column, we can determine the hydrostatic pressure at the bottom of the tank. This concept is fundamental in applications ranging from hydraulic engineering to the calibration of pressure gauges, as it helps predict how a fluid will behave under different conditions of depth and density.
Pressure Gauge Calibration
Pressure gauge calibration is an important procedure that ensures the accuracy and reliability of a pressure gauge, which is a device used to measure the pressure of fluids within containers such as tanks, pipes, or any system that confines the fluid. Calibration involves comparing the readings of the instrument in question to that of a standard or reference instrument, often in a controlled setting, to understand and correct any deviations.

In our example problem, a pressure gauge is used to determine the height of oil in a storage tank. During the calibration process, the gauge must be set to read zero when there is no pressure other than atmospheric pressure; that is, when the tank is open to the atmosphere. As the tank is filled, the gauge measures the increase in hydrostatic pressure, which can then be used to create a calibration curve that correlates pressure readings to oil height. However, it's important to take into account any additional pressures, such as the absolute pressure above the liquid surface, to get accurate readings. Failing to consider this, as seen in the case of an operator who took the gauge pressure without accounting for the tank's absolute pressure, can lead to incorrect assessments of the fluid height within the tank.

Meticulous calibration of pressure gauges underpins the safe and precise operation of fluid systems in various industrial and scientific applications, and when properly calibrated, they provide invaluable information for maintenance and operational protocols.

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Most popular questions from this chapter

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