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A mixture is 10.0 mole \(\%\) methyl alcohol, 75.0 mole \(\%\) methyl acetate \(\left(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}_{2}\right),\) and 15.0 mole \(\%\) acetic acid. Calculate the mass fractions of each compound. What is the average molecular weight of the mixture? What would be the mass (kg) of a sample containing 25.0 kmol of methyl acetate?

Short Answer

Expert verified
The mass fractions of Methyl Alcohol, Methyl Acetate, and Acetic Acid in the mixture are approximately 0.10, 0.75, and 0.15 respectively. The average molecular weight of the mixture is approximately 67 g/mol. A sample containing 25.0 kmol of Methyl Acetate would weigh approximately 1850 kg.

Step by step solution

01

Determine The Molecular Weights of Each Component

First determine the molecular weights of each compound in the mixture. The molecular weights can be calculated by adding up the atomic weights of each atom in a molecule. The atomic weights of carbon (C), hydrogen (H), and oxygen (O) are approximately 12, 1, and 16 g/mol respectively. Therefore, the molecular weights are: Methyl Alcohol (CH3OH) = 32 g/mol, Methyl Acetate (C3H6O2) = 74 g/mol, and Acetic Acid (C2H4O2) = 60 g/mol.
02

Calculate The Mass Fractions of Each Component

Calculate the mass fractions of each compound. Mass fraction can be calculated by dividing the mass of each compound by the total mass of the mixture. Here, the 'mass' of each compound can be calculated from its molecular weight and mole percent. Therefore, mass fraction = (Molecular weight * Mole %) / Total mass. The total mass of the mixture is the sum of the masses of all compounds, which is calculated in the same manner (Molecular weight * Mole %). Calculate this for each compound in the mixture.
03

Determine The Average Molecular Weight of the Mixture

The average molecular weight of the mixture can be calculated by adding together the products of mole percent and molecular weight of each compound. The formula is Average Molecular weight = Sum(Molecular weight * Mole %) for each compound. Add up these products to obtain the average molecular weight of the mixture.
04

Calculate The Mass of The Sample With Known Amount of Methyl Acetate

The mass (kg) of the sample containing a specific amount of a compound can be determined by multiplying the quantity of the compound (in kmol) with its molecular weight and then converting to kg (since 1 mol = 1 kg/kmol). Therefore, Mass = Quantity in kmol * Molecular weight * (1 kg/kmol). Calculate this for 25.0 kmol of methyl acetate.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mole Percent Calculation
Understanding the mole percent of a compound in a mixture is essential for a variety of chemical process calculations. The mole percent represents the proportion of moles of a particular substance to the total moles in a mixture, expressed as a percentage. It's calculated by taking the number of moles of the compound of interest and dividing it by the total number of moles of all substances in the mixture. Multiplying the result by 100 gives the mole percent. For example, if you have a mixture where 10 out of 100 total moles are of methyl alcohol, then the mole percent of methyl alcohol would be \( \frac{10 \text{ moles}}{100 \text{ moles}} \times 100 = 10.0\% \).

It's an essential value that allows chemists and chemical engineers to understand the composition of mixtures and to proceed with further calculations, such as determining mass fractions or the average molecular weight of the mixture.
Mass Fraction
The mass fraction is a way to express how much of a particular component is present in a mixture based on mass. Unlike mole percent, which deals with the number of moles, mass fraction is concerned with the weight part of a component. To calculate the mass fraction, we take the mass of each compound—which can be found by multiplying the compound's molecular weight by its mole fraction—and divide it by the total mass of the mixture. This will yield a dimensionless number representing the share of the total mixture's mass that is due to that component. Because masses are additive, the sum of all mass fractions in a mixture will be equal to 1 (or 100%).

The mass fraction is particularly useful in industries where the mixture's weight needs to be considered for the preparation or processing of chemical solutions, such as when dosing pharmaceuticals or preparing reactants for a chemical reaction.
Average Molecular Weight
The average molecular weight is a weighted average that reflects the overall heft of a mixture's components. It considers both the molecular weights of the individual compounds and their abundance in the mixture as dictated by the mole fraction. To find the average molecular weight of a mixture, we multiply the molecular weight of each substance by its mole percent and add all these values together. The resulting number gives us an effective molecular weight that can represent the mixture in further calculations.

This average is invaluable for calculations involving the mass of gases or when converting between moles and mass in chemical processes. For example, the average molecular weight helps us predict how a gaseous mixture might behave under certain pressure and temperature conditions by giving us a single value to use in ideal gas law calculations. It simplifies the process of finding the volume or mass of a gas without breaking it down into its separate components.
Chemical Process Calculations
Chemical process calculations are integral to designing and operating any chemical reaction or process, spanning from simple mixture preparations to complex industrial processes. These calculations take into account factors such as the relationships between moles, mass, volume, and molecular weights, alongside physical properties like density, viscosity, and solubility. By executing precise mathematical computations—such as mole percent, mass fraction, and average molecular weight calculations—we can ensure the desired outcome of a chemical process, be it for producing a new material or purifying a substance.

Using the provided exercise as an example, if we needed to calculate the mass of a sample that contains 25.0 kmol of methyl acetate, we would utilize the molecular weight of methyl acetate and the knowledge that 1 kmol is equivalent to 1 kg. Such calculations are commonplace in industrial chemistry settings where managing exact quantities of substances is critical for successful reactions and product consistency.

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Most popular questions from this chapter

The chemical reactor shown below has a cover that is held in place by a series of bolts. The cover is made of stainless steel ( \(\mathrm{SG}=8.0\) ), is 3 inches thick, has a diameter of 24 inches, and covers and seals an opening 20 inches in diameter. During turnaround, when the reactor is taken out of service for cleaning and repair, the cover was removed by an operator who thought the reactor had been depressurized using a standard venting procedure. However, the pressure gauge had been damaged in an earlier process upset (the reactor pressure had exceeded the upper limit of the gauge), and instead of being depressurized completely, the vessel was under a gauge pressure of 30 psi. (a) What force ( \(\left(\mathrm{b}_{\mathrm{f}}\right)\) were the bolts exerting on the cover before they were removed? (Hint: Don't forget that a pressure is exerted on the top of the cover by the atmosphere.) What happened when the last bolt was removed by the operator? Justify your prediction by estimating the initial acceleration of the cover upon removal of the last bolt. (b) Propose an alteration in the turnaround procedure to prevent recurrence of an incident of this kind.

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