/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 In April \(2010,\) the worst oil... [FREE SOLUTION] | 91Ó°ÊÓ

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In April \(2010,\) the worst oil spill ever recorded occurred when an explosion and fire on the Deepwater Horizon offshore oil-drilling rig left 11 workers dead and began releasing oil into the Gulf of Mexico. One of the attempts to contain the spill involved pumping drilling mud into the well to balance the pressure of escaping oil against a column of fluid (the mud) having a density significantly higher than those of seawater and oil. In the following problems, you may assume that seawater has a specific gravity of 1.03 and that the subsea wellhead was 5053 ft below the surface of the Gulf. (a) Estimate the gauge pressure (psig) in the Gulf at a depth of \(5053 \mathrm{ft}\). (b) Measurements indicate that the pressure inside the wellhead is 4400 psig. Suppose a pipe between the surface of the Gulf and the wellhead is filled with drilling mud and balances that pressure. Estimate the specific gravity of the drilling mud. (c) The drilling mud is a stable slurry of seawater and barite (SG \(=4.37\) ). What is the mass fraction of barite in the slurry? (d) What would you expect to happen if the barite weight fraction were significantly less than that estimated in Part (c)? Explain your reasoning.

Short Answer

Expert verified
The gauge pressure in the Gulf at a depth of 5053 ft is approximately 1522.8 psig. The specific gravity of the drilling mud that would balance this pressure at this depth is estimated to be around 2.18. The mass fraction of barite in the slurry is estimated to be around 0.31 or 31\%. If the barite mass fraction decreases significantly, it will fail to counter the oil pressure leading to more spillages.

Step by step solution

01

Gauge Pressure Calculation

The problem asks for the gauge pressure (psig) at a depth of 5053 ft. By definition, gauge pressure in a fluid is given by \( P = \rho g h \), where \( \rho \) is the density, \( g \) is the acceleration due to gravity, and \( h \) is the height (or depth in this case). The specific gravity of sea water is 1.03, hence density of sea water \( \rho = 1.03 \times 62.4 \, lb/ft^{3} = 64.272 \, lb/ft^{3} \). (Note: 62.4 lb/ft³ is the density of water).We insert these findings into the pressure equation together with the gravitational acceleration \( g = 32.2 \, ft/s^{2} \), to find out the pressure: \( P = \rho gh = 64.272 \times 32.2 \times 5053 \, lb/ft^{2} \). Since \( 1 \, psig = 144 \, lb/ft^{2} \), we divide by 144 to convert to psig.
02

Estimate Specific Gravity

Next, we need to estimate the specific gravity of the drilling mud. Given that the pressure inside the wellhead is 4400 psig, the mud using its specific gravity and the same depth needs to exert the same amount of pressure to balance this. Therefore, the specific gravity of the mud \( SG_{mud} = P_{mud} / (g \times h \times SG_{water}) \). Here, \( P_{mud} = 4400 \times 144 \, lb/ft^{2} \), \( SG_{water} = 1.03 \), and all other variables are the same as in step 1.
03

Mass Fraction Calculation

The third part of the exercise asks for the mass fraction of barite in the slurry. The specific gravity of barite is stated as 4.37. The specific gravity of a mix can be represented by the equation \( SG_{mix} = x \times SG_{barite} + (1-x) \times SG_{seawater} \), where \( x \) is the mass fraction of barite. Using the values from step 2 and solving for \( x \) will give us the mass fraction of barite.
04

Observations on Changes in Mass Fraction

A significant decrease in the mass fraction of barite would mean less of heavy material counteracting the oil pressure. The mud would have a lower specific gravity. It would therefore not be able to sufficiently counterbalance the high oil pressure which would result in the oil continuing to spew into the Gulf.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gauge Pressure Calculation
Understanding gauge pressure is crucial for diverse fields such as engineering, meteorology, and even cooking. Gauge pressure is the pressure of a fluid relative to the ambient atmospheric pressure. As you saw in the example regarding the oil spill in the Gulf of Mexico, calculating gauge pressure involves considering the fluid's density, the depth at which the pressure is being measured, and the acceleration due to gravity.

To simplify, we can think of it like this: deep under the ocean's surface, water exerts pressure on any object because of its weight. The deeper you go, the greater the pressure. This scale doesn't start at zero, though; it's 'zeroed' against atmospheric pressure - meaning it represents the excess pressure over and above atmospheric pressure. For scientists and engineers working in the field, these calculations are critical for designing equipment that can withstand underwater pressure, such as subsea oil wells or pipelines.
Specific Gravity Estimation
Specific gravity (SG) is a measure of the density of a substance compared to the density of water. This concept becomes handy when differentiating between materials or substances based on their density without getting into complex units. For example, estimating the specific gravity of drilling mud, as needed for the oil spill scenario, helps engineers determine if the mud will be effective at counteracting the high pressure from the oil wellhead.

Practically, if a substance has a specific gravity less than 1, it floats on water, and if it's greater than 1, it sinks. The drilling mud in the case of the Deepwater Horizon spill needed a specific gravity higher than that of seawater to neutralize the upthrust of the escaping oil. Understanding specific gravity is hence pivotal in environmental management and industrial processes—like choosing the right materials for flotation devices or anticipating how pollutants might spread in water.
Mass Fraction in Slurry
The mass fraction is a dimensionless number representing the ratio of a substance's mass to the total mass of a mixture. In chemical engineering, particularly in preparing mixtures like slurry, mass fraction is essential to ensure the desired properties of the final product. For the Deepwater Horizon oil spill, engineers had to calculate the mass fraction of barite in the drilling mud slurry to ensure it was dense enough to counter the oil's escape pressure.

By balancing the specific gravity equation with known values of seawater and barite, you can determine the exact composition required for the drilling mud. This careful calculation exemplifies how the industry uses mass fraction to control processes and achieve specific outcomes, essential for tasks ranging from manufacturing to environmental remediation.
Oil Spill Environmental Impact
The environmental impact of an oil spill extends far beyond the immediate vicinity of the spill. It can devastate entire ecosystems, from the seabed to the shorelines, and affect the flora and fauna for years to come. Containment and clean-up efforts are challenging and costly, with an emphasis on preventing the oil from reaching coastal areas and harming wildlife or disrupting local economies that rely on fishing and tourism.

In the context of the Deepwater Horizon spill, the extended consequences included harm to marine life, widespread economic loss, and health issues among cleanup workers and local residents. By relating this example to the theoretical and practical aspects of chemical engineering education, we highlight the importance of responsible engineering practices and the mitigation of environmental risks. Understanding the mechanics behind gauge pressure, specific gravity, and mass fractions is not just academic; it is instrumental in anticipating and preventing disasters, measuring their potential impact, and orchestrating effective responses.

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Most popular questions from this chapter

An open-end mercury manometer is connected to a low-pressure pipeline that supplies a gas to a laboratory. Because paint was spilled on the arm connected to the line during a laboratory renovation, it is impossible to see the level of the manometer fluid in this arm. During a period when the gas supply is connected to the line but there is no gas flow, a Bourdon gauge connected to the line downstream from the manometer gives a reading of 7.5 psig. The level of mercury in the open arm is \(900 \mathrm{mm}\) above the lowest part of the manometer. (a) When the gas is not flowing, the pressure is the same everywhere in the pipe. How high above the bottom of the manometer would the mercury be in the arm connected to the pipe? (b) When gas is flowing, the mercury level in the visible arm drops by \(25 \mathrm{mm}\). What is the gas pressure (psig) at this moment?

In the manufacture of pharmaceuticals, most active pharmaceutical ingredients (APIs) are made in solution and then recovered by separation. Acetaminophen, a pain-killing drug commercially marketed as Tylenol", is synthesized in an aqueous solution and subsequently crystallized. The slurry of crystals is sent to a centrifuge from which two effluent streams emerge: ( 1 ) a wet cake containing 90.0 wt\% solid acetaminophen \((\mathrm{MW}=\) 151 g/mol) and 10.0 wt\% water (plus some acetaminophen and other dissolved substances, which we will neglect), and (2) a highly dilute aqueous solution of acetaminophen that is discharged from the process. The wet cake is fed to a dryer where the water is completely evaporated, leaving the residual acetaminophen solids bone dry. If the evaporated water were condensed, its volumetric flow rate would be \(50.0 \mathrm{Lh}\). Following is a flowchart of the process, which runs 24 h/day, 320 days/yr. A denotes acetaminophen. (a) Calculate the yearly production rate of solid acetaminophen (tonne/yr), using as few dimensional equations as possible. (b) A proposal has been made to subject the liquid solution leaving the centrifuge to further processing to recover more of the dissolved acetaminophen instead of disposing of the solution. On what would the decision depend?

Perform the following estimations without using a calculator. (a) Estimate the mass of water (kg) in an Olympic-size swimming pool. (b) A drinking glass is being filled from a pitcher. Estimate the mass flow rate of the water (g/s). (c) Twelve male heavyweight boxers coincidentally get on the same elevator in Great Britain. Posted on the elevator wall is a sign that gives the maximum safe combined weight of the passengers, \(W_{\mathrm{max}},\) in stones. (A stone is a unit of mass equal to \(14 \mathrm{lb}_{\mathrm{m}}\). It is commonly used in England as a measure of body weight, which, like the numerical equivalence between the \(1 \mathrm{b}_{\mathrm{m}}\) and \(\mathrm{Ib}_{\mathrm{f}},\) is only valid at or near sea level.) If you were one of the boxers, estimate the lowest value of \(W_{\max }\) for which you would feel comfortable remaining on the elevator. (d) The Trans-Alaska Pipeline has an outside diameter of 4 ft and extends 800 miles from the North Slope of Alaska to the northernmost ice-free port in Valdez, Alaska. How many barrels of oil are required to fill the pipeline? (e) Estimate the volume of your body \(\left(\mathrm{cm}^{3}\right)\) in two different ways. (Show your work.) (f) A solid block is dropped into water and very slowly sinks to the bottom. Estimate its specific gravity.

Certain solid substances, known as hydrated compounds, have well-defined molecular ratios of water to some other species. For example, calcium sulfate dihydrate (commonly known as gypsum, \(\left.\mathrm{CaSO}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O}\right),\) has 2 moles of water per mole of calcium sulfate; alternatively, it may be said that 1 mole of gypsum consists of 1 mole of calcium sulfate and 2 moles of water. The water in such substances is called water of hydration. (More information about hydrated salts is given in Chapter 6 .) In order to eliminate the discharge of sulfuric acid into the environment, a process has been developed in which the acid is reacted with aragonite \(\left(\mathrm{CaCO}_{3}\right)\) to produce calcium sulfate. The calcium sulfate then comes out of solution in a crystallizer to form a slurry (a suspension of solid particles in a liquid) of solid gypsum particles suspended in an aqueous \(\mathrm{CaSO}_{4}\) solution. The slurry flows from the crystallizer to a filter in which the particles are collected as a filter cake. The filter cake, which is 95.0 wiff solid gypsum and the remainder CaSO_solution, is fed to a dryer in which all water (including the water of hydration in the crystals) is driven off to yield anhydrous (water-free) CaSO \(_{4}\) as product. A flowchart and relevant process data are given below. Solids content of slurry leaving crystallizer: \(0.35 \mathrm{kg} \mathrm{CaSO}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O} / \mathrm{L}\) slurry \(\mathrm{CaSO}_{4}\) content of slurry liquid: \(0.209 \mathrm{g} \mathrm{CaSO}_{4} / 100 \mathrm{g} \mathrm{H}_{2} \mathrm{O}\) Specific gravities: \(\mathrm{CaSO}_{4} \cdot 2 \mathrm{H}_{2} \mathrm{O}(\mathrm{s}), 2.32 ;\) liquid solutions, 1.05 (a) Briefly explain in your own words the functions of the three units (crystallizer, filter, and dryer). (b) Takea basis of one liter of solution leaving the crystallizer and calculate the mass (kg) and volume (L) of solid gypsum, the mass of \(\mathrm{CaSO}_{4}\) in the gypsum, and the mass of \(\mathrm{CaSO}_{4}\) in the liquid solution. (c) Calculate the percentage recovery of \(\mathrm{CaSO}_{4}-\) that is, the percentage of the total \(\mathrm{CaSO}_{4}\) (precipitated plus dissolved) leaving the crystallizer recovered as solid anhydrous \(\mathrm{CaSO}_{4}\) (d) List five potential negative consequences of discharging \(\mathrm{H}_{2} \mathrm{SO}_{4}\) into the river passing the plant.

The reaction \(A \rightarrow B\) is carried out in a laboratory reactor. According to a published article the concentration of A should vary with time as follows: \(C_{\mathrm{A}}=C_{\mathrm{A} 0} \exp (-k t)\) where \(C_{\mathrm{A} 0}\) is the initial concentration of \(\mathrm{A}\) in the reactor and \(k\) is a constant. (a) If \(C_{\mathrm{A}}\) and \(C_{\mathrm{A} 0}\) are in \(\mathrm{Ib}-\) moles \(/ \mathrm{ft}^{3}\) and \(t\) is in minutes, what are the units of \(k ?\) (b) The following data are taken for \(C_{\mathrm{A}}(t):\) $$\begin{array}{cc}\hline t(\min ) & C_{\mathrm{A}}\left(\mathrm{lb}-\mathrm{mole} / \mathrm{ft}^{3}\right) \\\\\hline 0.5 & 1.02 \\\1.0 & 0.84 \\\1.5 & 0.69 \\\2.0 & 0.56 \\\3.0 & 0.38 \\\ 5.0 & 0.17 \\\10.0 & 0.02 \\\\\hline\end{array}$$ Verify the proposed rate law graphically (first determine what plot should yield a straight line), and calculate \(C_{\mathrm{A} 0}\) and \(k\) (c) Convert the formula with the calculated constants included to an expression for the molarity of A in the reaction mixture in terms of \(t\) (seconds). Calculate the molarity at \(t=265 \mathrm{s}\).

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