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Limestone (calcium carbonate) particles are stored in \(50-\mathrm{L}\) bags. The void fraction of the particulate matter is 0.30 (liter of void space per liter of total volume) and the specific gravity of solid calcium carbonate is 2.93. (a) Estimate the bulk density of the bag contents ( \(\mathbf{k g}\) CaCO \(_{3}\) /iter of total volume). (b) Estimate the weight ( \(W\) ) of the filled bags. State what you are neglecting in your estimate. (c) The contents of three bags are fed to a ball mill, a device something like a rotating clothes dryer containing steel balls. The tumbling action of the balls crushes the limestone particles and turns them into a powder. (See pp. \(21-64\) of Perry's Chemical Engineers' Handbook, 8 th ed.) The limestone coming out of the mill is put back into \(50-\mathrm{L}\) bags. Would the limestone (i) just fill three bags, (ii) fall short of filling three bags, or (iii) fill more than three bags? Briefly explain your answer.

Short Answer

Expert verified
The bulk density of the bag contents is 2.051 kg/L, the weight of the filled bags is approximately 102.55 kg, and the contents post-grinding should still be sufficient to fill three 50-L bags.

Step by step solution

01

Calculate the bulk density

Bulk density is the ratio of the total mass to the total volume, including the void. The mass of calcium carbonate in 1 liter can be calculated from its specific gravity (2.93 g/cm³). We know: 1 cm³ = 1 mL = 0.001 L, so the mass of calcium carbonate = 2.93 g/cm³ * 1000 cm³/L = 2930 g/L = 2.93 kg/L. Therefore, the bulk density = mass * (1 - void fraction) = 2.93 kg/L * (1 - 0.3) = 2.051 kg/L.
02

Estimate the weight of the filled bags

The weight of the filled bags can be calculated by multiplying the bulk density by the volume of the bag. Therefore, the weight = volume * bulk density = 50 L * 2.051 kg/L = 102.55 kg. The weight is an estimate because it does not include the weight of the bag itself or any possible packing materials.
03

Estimate the number of filled bags post-grinding

The total volume of limestone remains constant even after grinding. Therefore, the contents should still fill three bags because while the individual particles may be smaller, the total volume of material (limestone) hasn't changed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specific Gravity
Understanding the specific gravity is essential when dealing with the bulk density calculation of a substance in chemical processes. Specific gravity, often termed as relative density, is the ratio of the density of a substance to the density of a reference substance, usually water at 4°C for liquids and solids, and air at room temperature for gases. It is a dimensionless unit because it is a ratio of two densities and can provide quick insights about the substance. For instance, a specific gravity greater than one, as in the case of calcium carbonate (2.93), indicates that the substance is denser than water.

When calculating the bulk density, one can quickly determine the mass per unit volume by using the specific gravity. The conversion factor from specific gravity to mass density, under standard conditions, is typically the density of water, which is approximately 1 g/cm³ or 1000 kg/m³. Hence, for calcium carbonate with a specific gravity of 2.93, its density can be calculated as 2.93 times the density of water, giving us a mass density of 2.93 g/cm³ or 2930 kg/m³.
Void Fraction
Void fraction is a measure of the amount of empty space in a material. In the context of chemical engineering and particulate solids, particularly when looking at storage or handling of bulk materials, the void fraction is critical. It represents the fraction of the total volume taken up by the voids (spaces) between particles. This means that in a container filled with particles, not every bit of space is occupied by the material itself; some of it is empty space.

The void fraction has implications for numerous properties, like the flowability of a material, its ability to compact, and of course, its bulk density. Here, it is given that the void fraction for the calcium carbonate particles is 0.30. When calculating bulk density, one must account for this space to get an accurate measure of the density of the material in a container, which includes both the particles and the voids. The calculation for bulk density effectively adjusts the solid density by a factor of \(1 - \text{void fraction}\), as seen in the step-by-step solution.
Chemical Engineering Principles in Bulk Density Calculation
Applying chemical engineering principles to the calculation of bulk density allows for a more accurate understanding of the material's behavior in various processes. Bulk density is not just an intrinsic property of a material; it is contextual and depends on both the material's specific gravity and the void fraction. Chemical engineers need to consider these variables, along with others such as particle size distribution, shape, and cohesiveness, when designing processes involving powders and particulates.

In the given problem, dealing with storage and material transformation (grinding to powder), the conservation of mass is an underlying principle used to solve part (b) and (c) of the exercise. The total mass of the limestone remains unchanged after grinding, indicating that, barring any losses, the same volume will be occupied. These principles guide the handling, transportation, and transformation of materials in industries ranging from pharmaceuticals, food processing, to mining.

A cornerstone of chemical engineering is the understanding of physical principles that govern the behavior of materials. By combining knowledge on specific gravity, void fraction, and mass conservation, engineers can predict the outcome of process changes, such as the one described involving the ball mill, and ensure effective and efficient designs.

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