/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 An open-end mercury manometer is... [FREE SOLUTION] | 91Ó°ÊÓ

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An open-end mercury manometer is to be used to measure the pressure in an apparatus containing a vapor that reacts with mercury. A 10 -cm layer of silicon oil \((\mathrm{SG}=0.92)\) is placed on top of the mercury in the arm attached to the apparatus. Atmospheric pressure is \(765\) \(\mathrm{mm}\) Hg. (a) If the level of mercury in the open end is 365 mm below the mercury level in the other arm, what is the pressure (mm Hg) in the apparatus? (b) When the instrumentation specialist was deciding on a liquid to put in the manometer, she listed several properties the fluid should have and eventually selected silicon oil. What might the listed properties have been?

Short Answer

Expert verified
a) For the pressure in the apparatus, perform the calculation as described in step 2 to get value of final pressure in mm Hg. b) Desired properties that might be listed for the liquid include: chemical stability (does not react with the system), appropriate specific gravity (makes pressure differences measurable), non-volatility (doesn't evaporate easily), cost effectiveness, and stability in a wide range of operational temperatures.

Step by step solution

01

Understand Pressure Difference

Firstly, it is important to understand that the pressure difference between two points in a static fluid column equals the density of the fluid multiplied by gravity and the height of the column. Pressure difference = \(\mathrm{SG} \times g \times h\) where the value of g is 9.81 m/s² as an approximation for the acceleration due to gravity and h is height of fluid column (difference in mercury level). The pressure exerted by the silicon oil is calculated by using its known specific gravity (0.92 in this case). The pressure at station point in the apparatus then equals to atmospheric pressure plus the pressure caused by the silicon oil layer minus the pressure corresponding to the mercury level difference.
02

Calculate Pressure in Apparatus

To calculate pressure in the apparatus (in mm Hg), use the following method:- Convert given atmospheric pressure into cm Hg by dividing by 10 (since 1 cm = 10 mm), let's denote as \( P_{atm} \).- Convert mercury level difference into cm by dividing by 10 (let's denote as \( h_{Hg} \)).- Use above Step 1 formulation, substitute SG = 0.92 and h = 10 cm (silicon oil height), then convert resulting pressure in mm Hg (let's denote as \( P_{oil} \)).- Then add \( P_{atm} \) and \( P_{oil} \) and subtract \( h_{Hg} \) to get pressure in the apparatus \( P_{app} = P_{atm} + P_{oil} - h_{Hg} \).
03

Reflect on Required Properties of Manometer Fluid

In part (b), there is no explicit calculation. Reflecting on why silicon oil was selected over other fluids can indicate the desired properties for a fluid to be used in manometer. Important properties could be chemical inertness (especially to the operating vapor), suitable specific gravity, non-volatile nature, low cost, and stability in a wide range of temperatures.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Specific Gravity
Specific gravity is a fundamental concept when dealing with fluid dynamics, particularly in the context of manometer pressure calculations. It is defined as the ratio of the density of a fluid to the density of a reference substance, usually water for liquids. This dimensionless quantity allows us to compare the density of a fluid to water without worrying about units. For instance, the specific gravity (\( \text{SG} \)) of silicon oil is given as 0.92, which means silicon oil is less dense than water, as it is only 92% as dense as water at a specified temperature (typically 4°C for water).

In our exercise, specific gravity serves as a crucial factor in determining the pressure exerted by the silicon oil layer in the manometer. Since we know the specific gravity of silicon oil, we can calculate its density relative to mercury and subsequently determine the pressure contribution to the overall pressure in the apparatus. Without understanding specific gravity, it would be difficult to relate the measured heights in a manometer to actual pressures.
Static Fluid Column
The concept of a static fluid column is integral to understanding the operation of manometers. It refers to a vertical column of fluid that is at rest, with no fluid moving up or down. When the fluid in such a column is in hydrostatic equilibrium, the pressure at every point in the fluid is determined by the weight of the fluid above it. This is because the pressure at a point in a fluid at rest must support the weight of the fluid column directly above it.

The relationship between pressure difference and a static fluid column is given by the equation \( \text{Pressure difference} = \text{SG} \times g \times h \), where \( g \) represents the acceleration due to gravity and \( h \) the height of the fluid column. In the provided exercise, the static fluid column is created by the height difference of mercury in the two arms of the manometer and the layer of silicon oil. Calculating the pressure in the apparatus heavily relies on the accurate measurement of this static fluid column and requires understanding the contributing factors, such as the specific gravity of the fluid and the local acceleration due to gravity.
Manometry Properties
Manometry properties encompass the characteristics a fluid must possess to function effectively within a manometer. These properties include chemical compatibility, specific gravity, non-volatility, and thermal stability. Chemical compatibility means the manometric fluid should not react with the substances it comes into contact with; otherwise, it may alter the pressure reading or damage the manometer. Given that the vapor in the apparatus reacts with mercury, silicon oil's non-reactivity makes it a suitable choice.

The specific gravity of the manometric fluid influences sensitivity and range of measurements. Silicon oil's specific gravity of 0.92 provides an appropriate balance between sensitivity and the ability to measure the required pressure range. Non-volatility ensures that the fluid's volume and, consequently, the height of the fluid column remain constant over time. Thermal stability means that the fluid properties do not significantly change with temperature variations, thereby providing consistent readings. The selection of silicon oil for the manometer in the exercise may be attributed to such ideal manometric properties, underscoring its ability to deliver accurate and reliable pressure measurements in the experimental setup.

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Most popular questions from this chapter

A rectangular block floats in pure water with 0.5 inch above the surface and 1.5 inches below the surface. When placed in an aqueous solution, the block of material floats with 1 inch below the surface. Estimate the specific gravities of the block and the solution. (Suggestion: Call the horizontal crosssectional area of the block \(A\). \(A\) should cancel in your calculations.)

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An open-end mercury manometer is connected to a low-pressure pipeline that supplies a gas to a laboratory. Because paint was spilled on the arm connected to the line during a laboratory renovation, it is impossible to see the level of the manometer fluid in this arm. During a period when the gas supply is connected to the line but there is no gas flow, a Bourdon gauge connected to the line downstream from the manometer gives a reading of 7.5 psig. The level of mercury in the open arm is \(900 \mathrm{mm}\) above the lowest part of the manometer. (a) When the gas is not flowing, the pressure is the same everywhere in the pipe. How high above the bottom of the manometer would the mercury be in the arm connected to the pipe? (b) When gas is flowing, the mercury level in the visible arm drops by \(25 \mathrm{mm}\). What is the gas pressure (psig) at this moment?

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