/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 The following \((x, y)\) data ar... [FREE SOLUTION] | 91Ó°ÊÓ

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The following \((x, y)\) data are recorded: $$\begin{array}{|c|c|c|c|}\hline x & 0.5 & 1.4 & 84 \\\\\hline y & 2.20 & 4.30 & 6.15 \\\\\hline \end{array}$$ (a) Plot the data on logarithmic axes. (b) Determine the coefficients of a power law expression \(y=a x^{b}\) using the method of least squares. (Remember what you are really plotting \(-\) there is no way to avoid taking logarithms of the data point coordinates in this case.) (c) Draw your calculated line on the same plot as the data.

Short Answer

Expert verified
The described process involves data plotting on logarithmic axes, conversion to linear form to apply least squares method, calculation and substitution of the coefficients to draw the best fit power law curve on the same plot.

Step by step solution

01

- Data Preparation

Plot the data on logarithmic axes using the coordinates provided. Convert each value into its logarithm, because of the logarithmic nature of the axes being used. Use a logarithmic scale on both \(x\) and \(y\) axes.
02

- Achieve Linear Form

We need a linear form for our data to apply the least squares method. Since our aim is to represent the power law \(y=a x^{b}\) in linear form, it'll become \(\log_{10}y = \log_{10}a + b \log_{10}x\) when taking logarithm on both sides. This is similar to the linear equation \(Y = mX + c\), where \(Y=\log_{10}y\), \(X=\log_{10}x\), \(m=b\), and \(c=\log_{10}a\). Hence, we can now apply the least squares method to derive \(a\) and \(b\).
03

- Application of Least Squares Method

The principle of the method of least squares is all about minimizing the sum of the squares of the vertical distances of points from the regression line (the smallest is the sum, the better is the fit). In linear form, \(b\) (slope) is calculated as \(b = \frac{n(\sum XY) - (\sum X)(\sum Y)}{n(\sum X^2) - (\sum X)^2}\) and \(a\) (intercept) is calculated as \(a = \frac{\sum Y - b(\sum X)}{n}\), where \(n\) is the number of points. Substitutes the logarithms of the given data points into the formulas to obtain \(b\) and \(a\).
04

- Plot the Power Law

Now, convert \(\log_{10}a\) back to \(a\) by taking antilog, and keep \(b\). Substitute these coefficients into the original power law equation \(y=a x^{b}\) to represent the line of best fit calculated through least squares. Draw this line on the same log-log plot. This curve with calculated \(a\) and \(b\) values will be the best fit for the given data points.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Logarithmic Data Plotting
In the realm of chemical processes and data analysis, logarithmic data plotting is an essential technique that allows us to visualize and analyze data sets that span multiple orders of magnitude. Unlike a linear scale, a logarithmic scale increases exponentially, meaning that each step on the scale represents a multiplication by a constant factor rather than a simple addition.

When plotting data on logarithmic axes, you convert the original data values into their logarithms. This can be especially useful when you're dealing with a power law relationship between two variables, which is common in chemical kinetics and other phenomena. By using logarithmic scales on both the x and y axes, you transform the curve of the power law into a straight line, where the exponent in the power law becomes the slope, and the coefficient becomes the y-intercept. This transformation simplifies analysis and, as is required for the method of least squares, makes the line easier to determine.
For example, given the data points with x-values of 0.5, 1.4, and 84, and corresponding y-values of 2.20, 4.30, and 6.15, you'd take the log of these numbers to correctly place them on log-log axes. Do not neglect this step, as it is crucial for the accurate representation of data in a log-log plot. This preparatory step is unmatched for highlighting patterns that may be undetected in untransformed data.
Power Law Expression
Understanding the power law expression is key to grasping how we interpret chemical process data. A power law is an algebraic equation of the form \(y = a x^{b}\), where \(a\) and \(b\) are constants, and \(x\) and \(y\) are the variables. The value \(b\) is known as the exponent, and \(a\) is the coefficient.

These expressions are particularly useful in science and engineering because they describe a variety of phenomena where one variable varies as a power of another. For instance, the rate of a reaction can be proportional to a power of reactant concentration. In the case of our exercise, to convert the power law relationship to a linear form, we take the logarithm of both sides, which yields \(\text{log} y = \text{log} a + b \text{log} x\). This linear form aligns with the straight line equation \(Y = mX + c\), simplifying the computation of the constants \(a\) and \(b\) from the data. Through this conversion, the interdependent nature of the variables becomes more apparent, and we set the stage for a linear regression approach using the least squares method.
Least Squares Method
The least squares method is a foundational statistical tool used in data analysis and curve fitting. It is particularly adept at finding the best-fitting curve or line to a given set of points by minimizing the sum of the squares of the offsets or residuals of points from the curve.

Our primary goal is to find the values of \(a\) and \(b\) in the power law expression that lead to a line that falls as close as possible to our logarithmic data points. To do this, you calculate the slope \(b\) and the y-intercept \(\text{log} a\) using the formulas derived from setting partial derivatives of the sum of squared residuals to zero.
These calculations involve sums of products and squares of the log-transformed x-values and y-values. Once you've determined the slope and y-intercept, you can convert the intercept back to find \(a\) by raising 10 to the power of the intercept. Consequently, we can express our original power law relationship with the computed variables, \(y=ax^b\), which represents the line of best fit. This line is then plotted on the logarithmic graph, visually demonstrating the relationship and enabling further interpretation and analysis of the dataset's trends and behaviors.

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Most popular questions from this chapter

A concentration \(C(\mathrm{mol} / \mathrm{L})\) varies with time (min) according to the equation \(C=3.00 \exp (-2.00 t)\) (a) What are the implicit units of 3.00 and 2.00? (b) Suppose the concentration is measured at \(t=0\) and \(t=1\) min. Use two- point linear interpolation or extrapolation to estimate \(C(t=0.6 \mathrm{min})\) and \(t(C=0.10 \mathrm{mol} / \mathrm{L})\) from the measured values, and compare these results with the true values of these quantities. (c) Sketch a curve of \(C\) versus \(t,\) and show graphically the points you determined in Part (b).

The following expression has occurred in a problem solution: $$R=\frac{(0.6700)(264,980)(6)\left(5.386 \times 10^{4}\right)}{(3.14159)\left(0.479 \times 10^{7}\right)}$$ The factor 6 is a pure integer. Estimate the value of \(R\) without using a calculator, following the procedure outlined in Section 2.5b. Then calculate \(R\), expressing your answer in both scientific and decimal notation and making sure it has the correct number of significant figures.

You arrive at your lab at 8 A.M. and add an indeterminate quantity of bacterial cells to a flask. At 11 A.M. you measure the number of cells using a spectrophotometer (the absorbance of light is directly related to the number of cells) and determine from a previous calibration that the flask contains 3850 cells, and at 5 P.M. the cell count has reached 36,530. (a) Fit each of the following formulas to the two given data points (that is, determine the values of the two constants in each formula): linear growth, \(C=C_{0}+k t ;\) exponential growth, \(C=C_{0} e^{k t} ;\) power-law growth, \(C=k t^{b} .\) In these expressions, \(C_{0}\) is the initial cell concentration and \(k\) and \(b\) are constants. (b) Select the most reasonable of the three formulas and justify your selection. (c) Estimate the initial number of cells present at 8 A.M. \((t=0)\). State any assumptions you make. (d) The culture needs to be split into two equal parts once the number of cells reaches 2 million. Estimate the time at which you would have to come back to perform this task. State any assumptions you make. If this is a routine operation that you must perform often, what does your result suggest about the scheduling of the experiment?

Sketch the plots described below and calculate the equations for \(y(x)\) from the given information. The plots are all straight lines. Note that the given coordinates refer to abscissa and ordinate values, not \(x\) and \(y\) values. [The solution of Part (a) is given as an example.] (a) A plot of In \(y\) versus \(x\) on rectangular coordinates passes through \((1.0,0.693)\) and \((2.0,0.0)\) (i.e., at the first point \(x=1.0\) and \(\ln y=0.693\) ). (b) A semilog plot of \(y\) (logarithmic axis) versus \(x\) passes through (1,2) and (2,1). (c) A log plot of \(y\) versus \(x\) passes through (1,2) and (2,1). (d) A semilog plot of \(x y\) (logarithmic axis) versus \(y / x\) passes through (1.0,40.2) and (2.0,807.0). (e) A log plot of \(y^{2} / x\) versus \((x-2)\) passes through (1.0,40.2) and (2.0,807.0).

A frustrated professor once claimed that if all the reports she had graded in her career were stacked on top of one another, they would reach from the Earth to the moon. Assume that an average report is the thickness of about 10 sheets of printer paper and use a single dimensional equation to estimate the number of reports the professor would have had to grade for her claim to be valid.

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