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A 22.0 gram sample of an unknown gas occupies 11.2 liters at standard temperature and pressure. Which of the following could be the identity of the gas? (A) \(\mathrm{CO}_{2}\) (B) \(\mathrm{SO}_{3}\) (C) \(\mathrm{O}_{2}\) (D) He

Short Answer

Expert verified
The identity of the gas could be CO2.

Step by step solution

01

Calculate the moles of the gas

Using Avogadro's law, that a gas at STP occupies a volume of 22.4 liters per mole, calculate the moles of the gas. In this case, \(11.2 \, \mathrm{liters} \, \times \, \frac{1 \, \mathrm{mole}}{22.4 \, \mathrm{liters}} = 0.5 \, \mathrm{mole}\) of gas.
02

Calculate the molar mass of the gas

Molar mass is calculated by dividing the mass of the gas by the moles of the gas. Here, the molar mass is \( \frac{22.0 \, \mathrm{g}}{0.5 \, \mathrm{mole}} = 44.0 \, \mathrm{g/mole}\).
03

Compare the calculated molar mass with the given gases

Looking at the molar masses of the given gases: CO2 = 44.0 g/mole, SO3 = 80.1 g/mole, O2 = 32.0 g/mole, He = 4.0 g/mole. The unknown gas could be CO2 because its molar mass matches with the calculated molar mass.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Avogadro's Law
Avogadro's law is a fundamental principle in chemistry that helps us understand the behavior of gases. It states that equal volumes of gases, at the same temperature and pressure, contain an equal number of molecules. This concept is crucial when dealing with gases, as it allows us to link volume with moles, a key unit in chemistry.

In practical terms, Avogadro's law tells us that at standard temperature and pressure (STP), one mole of any gas occupies 22.4 liters. This is a very useful benchmark when you need to find out how much space a certain amount of gas will occupy under these conditions.

To solve problems using Avogadro's law, you'll often follow these steps:
  • Identify the volume of the gas you are working with.
  • Use the relationship that one mole equals 22.4 liters at STP to determine the number of moles.
This method was used in the problem to find that the unknown gas sample contains 0.5 moles from its 11.2-liter volume.
Molar Mass Calculation
Molar mass is a measure of the mass of one mole of a substance. It is expressed in grams per mole (g/mol) and is a pivotal concept when identifying unknown substances by comparing calculated molar mass to known values.

In the provided problem, the molar mass calculation was key to solving the mystery of the unknown gas. With the number of moles found using Avogadro's law, you can easily compute molar mass using the formula:
  • Molar Mass = Mass of the gas (g) / Number of moles
This formula allowed the calculation of a molar mass of 44.0 g/mol for the unknown gas. By comparing this to known molar masses of candidate gases, the identity of the unknown gas was confirmed to be carbon dioxide (COâ‚‚).

Such calculations are essential in chemistry, facilitating the identification and study of chemicals.
Standard Temperature and Pressure (STP)
Standard temperature and pressure (STP) is a standardized condition used in chemistry to make fair comparisons between different gas scenarios. At STP, the temperature is set at 0°C (273.15 K) and pressure at 1 atmosphere (atm).

These conditions are used widely to simplify the calculation and comparison of gases. For example, at STP, we already know that 1 mole of gas occupies exactly 22.4 liters, thanks to Avogadro's law.

Understanding STP is important for:
  • Calculating gas volumes and moles accurately.
  • Ensuring consistency across various experiments and computations.
  • Allowing scientists to predict gas behavior in different conditions.
In the textbook problem, STP provided the baseline for calculating the moles of gas from the given volume, ultimately leading to the identification of the unknown gas. Knowing and utilizing STP can significantly ease the process of gas calculations and comparisons.

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Most popular questions from this chapter

A 2.0 L flask holds 0.40 g of helium gas. If the helium is evacuated into a larger container while the temperature is held constant, what will the effect on the entropy of the helium be? (A) It will remain constant because the number of helium molecules does not change. (B) It will decrease because the gas will be more ordered in the larger flask. (C) It will decrease because the molecules will collide with the sides of the larger flask less often than they did in the smaller flask. (D) It will increase because the gas molecules will be more dispersed in the larger flask.

Use the following information to answer questions 12-15. When heated in a closed container in the presence of a catalyst, potassium chlorate decomposes into potassium chloride and oxygen gas via the following reaction: \(2 \mathrm{KClO}_{3}(s) \rightarrow 2 \mathrm{KCl}(s)+3 \mathrm{O}_{2}(g)\) If 12.25 g of potassium chlorate decomposes, how many grams of oxygen gas will be generated? (A) 1.60 g (B) 3.20 g (C) 4.80 g (D) 18.37 g

Nitrogen’s electronegativity value is between those of phosphorus and oxygen. Which of the following correctly describes the relationship between the three values? (A) The value for nitrogen is less than that of phosphorus because nitrogen is larger, but greater than that of oxygen because nitrogen has a greater effective nuclear charge. (B) The value for nitrogen is less than that of phosphorus because nitrogen has fewer protons, but greater than that of oxygen because nitrogen has fewer valence electrons. (C) The value for nitrogen is greater than that of phosphorus because nitrogen has fewer electrons, but less than that of oxygen because nitrogen is smaller. (D) The value for nitrogen is greater than that of phosphorus because nitrogen is smaller, but less than that of oxygen because nitrogen has a smaller effective nuclear charge.

Which substance would have the highest boiling point? (A) Ethanol, because it is the most asymmetrical (B) Acetone, because of the double bond (C) Ethylene glycol, because it has the most hydrogen bonding (D) All three substances would have very similar boiling points because their molar masses are similar.

The wavelength range for infrared radiation is \(10^{-5} \mathrm{m},\) while that of ultraviolet radiation is \(10^{-8} \mathrm{m}\) . Which type of radiation has more energy, and why? (A) Ultraviolet has more energy because it has a higher frequency. (B) Ultraviolet has more energy because it has a longer wavelength. (C) Infrared has more energy because it has a lower frequency. (D) Infrared has more energy because it has a shorter wavelength.

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