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Use the following information to answer questions 12-15. When heated in a closed container in the presence of a catalyst, potassium chlorate decomposes into potassium chloride and oxygen gas via the following reaction: \(2 \mathrm{KClO}_{3}(s) \rightarrow 2 \mathrm{KCl}(s)+3 \mathrm{O}_{2}(g)\) If 12.25 g of potassium chlorate decomposes, how many grams of oxygen gas will be generated? (A) 1.60 g (B) 3.20 g (C) 4.80 g (D) 18.37 g

Short Answer

Expert verified
The amount of oxygen gas produced when 12.25 g of potassium chlorate decomposes is (C) 4.80 g.

Step by step solution

01

Convert the mass of potassium chlorate to moles

To start with the stoichiometric calculations first need to convert the given mass of potassium chlorate (\(\mathrm{KClO}_3\)) into moles. Moles can be calculated by the mass of the substance divided by its molar mass. From the periodic table, the molar mass of potassium chlorate \(\mathrm{KClO}_3\) is 39.10 (potassium) + 35.45 (chlorine) + 3*16.00 (oxygen) = 122.55 g/mol. So, the moles of \(\mathrm{KClO}_3\) used is 12.25 g / 122.55 g/mol = 0.100 mol.
02

Use stoichiometry to find moles of oxygen

Now, using the balanced chemical equation, we find the stoichiometric ratio between potassium chlorate and oxygen. The equation is \(2 \mathrm{KClO}_{3}(s) \rightarrow 2 \mathrm{KCl}(s)+3 \mathrm{O}_{2}(g)\). This tells us that for every 2 moles of \(\mathrm{KClO}_3\) that react, 3 moles of oxygen gas \(\mathrm{O}_2\) are produced. So the moles of \(\mathrm{O}_2\) produced are \(0.100\, \mathrm{mol} \times \frac{3\, \mathrm{mol\, O_2}}{2\, \mathrm{mol\, KClO}_3} = 0.150\, \mathrm{mol}\).
03

Convert the moles of oxygen to grams

Finally, convert the moles of oxygen to grams to find out how much oxygen will be produced. The molar mass of oxygen is (16.00*2) = 32.00 g/mol. So, the mass of \(\mathrm{O}_2\) produced is \(0.150\, \mathrm{mol} \times 32.00\, \mathrm{g/mol} = 4.80\, \mathrm{g}\). So, the correct answer is (C) 4.80 g.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactions
Chemical reactions are processes where substances, known as reactants, transform into new substances, called products. During this transformation, the structure of the molecules is rearranged to form new compounds. One classic example is the decomposition of potassium chlorate into potassium chloride and oxygen gas. This process signifies a change at the molecular level, where original bonds are broken and new bonds are formed. Understanding chemical reactions involves recognizing different types, such as synthesis, decomposition, single replacement, and double replacement reactions.
  • Synthesis combines simple molecules to form a complex one.
  • Decomposition is where a complex molecule breaks down into simpler ones, as seen in potassium chlorate decomposition.
In a balanced chemical reaction, the number of each type of atom is conserved. This means all reactants and products must obey the law of conservation of mass. Exploring these concepts allows us to predict product amounts, understand reaction conditions, and identify reaction types.
Molar Mass
Molar mass is a key concept in chemistry that represents the mass of a single mole of a substance. It allows chemists to convert between the mass of a substance and the number of moles. Molar mass is expressed in grams per mole (g/mol) and can be calculated using the atomic masses from the periodic table. For example, to find the molar mass of potassium chlorate \( \mathrm{KClO}_3 \) used in the potassium chlorate decomposition, you sum up the atomic masses:
  • Potassium (K): 39.10 g/mol
  • Chlorine (Cl): 35.45 g/mol
  • Oxygen (O): 3 \(\times\) 16.00 g/mol
Combining these values gives 122.55 g/mol. Knowing the molar mass is crucial for stoichiometry, as it helps convert given masses to moles, which can be used in further calculations to determine the amounts of reactants consumed or products formed.
Balanced Equations
A balanced chemical equation is essential for accurately describing a chemical reaction. It ensures that the number of atoms for each element is the same on the reactants side as on the products side, aligning with the law of conservation of mass.In the decomposition of potassium chlorate, the balanced equation is\[2 \mathrm{KClO}_{3}(s) \rightarrow 2 \mathrm{KCl}(s) + 3 \mathrm{O}_{2}(g)\]Each molecule of \( \mathrm{KClO}_3 \) consists of one potassium, one chlorine, and three oxygen atoms. The equation tells us that two molecules of \( \mathrm{KClO}_3 \) produce two \( \mathrm{KCl} \) and three \( \mathrm{O}_2 \) molecules. This balance is crucial for stoichiometric calculations, where ratios of reactants and products are used to calculate quantities. A properly balanced equation provides the precise relationship between molecules involved, allowing for accurate predictions of mass and volume relationships in chemical processes.
Potassium Chlorate Decomposition
Potassium chlorate decomposition is a type of chemical reaction where potassium chlorate \( \mathrm{KClO}_3 \) breaks down into potassium chloride \( \mathrm{KCl} \) and oxygen gas \( \mathrm{O}_2 \). This reaction can be catalyzed by heating in the presence of substances like manganese dioxide.The equation representing this decomposition is:\[2 \mathrm{KClO}_{3}(s) \rightarrow 2 \mathrm{KCl}(s) + 3 \mathrm{O}_{2}(g)\]This equation shows that for every two moles of \( \mathrm{KClO}_3 \), three moles of \( \mathrm{O}_2 \) are produced.Understanding this reaction includes grasping the catalytic role, which speeds up the reaction without being consumed. The liberation of oxygen gas is a key reaction feature, and this particular decomposition is often used in demonstrations for generating oxygen in labs. Potassium chlorate decomposition exemplifies decomposition reactions and underscores the significance of catalysts in influencing reaction rates.

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Most popular questions from this chapter

A mixture of helium and neon gases has a total pressure of 1.2 atm. If the mixture contains twice as many moles of helium as neon, what is the partial pressure due to neon? (A) 0.2 atm (B) 0.3 atm (C) 0.4 atm (D) 0.8 atm

A sealed, rigid container contains three gases: 28.0 \(\mathrm{g}\) of nitrogen, 40.0 \(\mathrm{g}\) of argon, and 36.0 g of water vapor. If the total pressure exerted by the gases is \(2.0 \mathrm{atm},\) what is the partial pressure of the nitrogen? (A) 0.33 atm (B) 0.40 atm (C) 0.50 \(\mathrm{atm}\) (D) 2.0 \(\mathrm{atm}\)

Which compound, \(\mathrm{CaCl}_{2}\) or \(\mathrm{CaO}\) , would you expect to have a high melting point? Why? (A) \(\mathrm{CaCl}_{2}\) because there are more ions per lattice unit (B) \(\mathrm{CaCl}_{2}\) because a chlorine ion is smaller than an oxygen ion (C) Cao, because the charge of oxygen ion exceeds that of chlorine ion (D) CaO, because the common charges of calcium and oxygen ions are identical in magnitude

1.50 g of \(\mathrm{NaNO}_{3}\) is dissolved into 25.0 \(\mathrm{mL}\) of water, causing the temperature to increase by \(2.2^{\circ} \mathrm{C}\) . The density of the final solution is found to be 1.02 \(\mathrm{g} / \mathrm{mL}\) . Which of the following expressions will correctly calculate the heat gained by the water as the NaNO, dissolves? Assume the volume of the solution remains unchanged. (A) \((25.0)(4.18)(2.2)\) (B) \(\frac{(26.5)(4.18)(2.2)}{1.02}\) (C) \(\frac{(1.02)(4.18)(2.2)}{1.50}\) (D) \((25.0)(1.02)(4.18)(2.2)\)

Which of the substances would be soluble in water? (A) Ethylene glycol only, because it has the longest bond lengths (B) Acetone only, because it is the most symmetrical (C) Ethanol and ethylene glycol only, because of their hydroxyl (-OH) (D) All three substances would be soluble in water due to their permanent dipoles.

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