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A mixture of helium and neon gases has a total pressure of 1.2 atm. If the mixture contains twice as many moles of helium as neon, what is the partial pressure due to neon? (A) 0.2 atm (B) 0.3 atm (C) 0.4 atm (D) 0.8 atm

Short Answer

Expert verified
Therefore, the partial pressure due to neon is 0.4 atm. So, the correct answer is (C) 0.4 atm.

Step by step solution

01

Express the partial pressures in terms of variables

Let the partial pressure of neon be \(P_{Ne}\), then the partial pressure of Helium \(P_{He}\) would be 2\(P_{Ne}\). This is because according to Dalton's law, the ratio of the partial pressures would be the same as the ratio of the number of moles.
02

Sum up the partial pressures

Now, by Dalton's law, \(P_{total}\) = \(P_{Ne}\) + \(P_{He}\). Substituting the values, we have 1.2 = \(P_{Ne}\) + 2\(P_{Ne}\).
03

Solve for \(P_{Ne}\)

Solving the equation gives us \(P_{Ne}\) = 1.2 / 3 = 0.4 atm

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Partial Pressure
Partial pressure refers to the pressure exerted by a particular gas in a mixture. In a container with multiple gases, each gas behaves as though it is occupying the entire volume by itself and exerts its own pressure. This individual pressure is known as the partial pressure. Dalton's Law of Partial Pressures is the fundamental principle used to calculate it. It states that the total pressure of a mixture of gases is equal to the sum of the partial pressures of each individual gas. This law can be expressed mathematically as \( P_{total} = P_1 + P_2 + P_3 + \, ... \, + P_n \), where \( P_1, P_2, \, ..., P_n \) are the partial pressures of the gases in the mixture.Understanding partial pressure is crucial in chemistry because it helps predict how gases will behave in a mixture. It is especially important when dealing with reactions involving gases or predicting how changes in mixed gases' composition will affect the overall system's pressure. By considering the partial pressures, scientists can better understand and engineer processes like respiration, industrial gas reactions, and pressure control in closed environments.
Mixture of Gases
A mixture of gases is a collection of two or more different gases occupying the same volume. In these mixtures, each gas maintains its properties and exerts pressure independently of the others. The total pressure of the system can be determined using Dalton’s Law of Partial Pressures. Each gas can be examined separately by considering its amount in moles, which allows us to find its partial pressure. When studying a mixture of gases, one must note that the behavior of each gas is affected by the same conditions, like temperature and volume, and assumptions in behavior are often made using the Ideal Gas Law. This law simplifies calculations by assuming that gases behave ideally, meaning they have perfectly elastic collisions and occupy no volume. Yet, real gases deviate slightly from this ideal behavior, especially at high pressures or low temperatures.
Chemistry Problem Solving
Solving chemistry problems involving gases, like the problem in the original exercise, often requires a clear understanding of the principles such as Dalton's Law. By methodically applying these principles, you can find unknowns, such as the partial pressure of a gas in a mixture. Here's a simple method to approach it:
  • Identify what is given and what you need to find. In our exercise, the total pressure and the mole ratio of the gases are given, and we need to find the partial pressure of neon.
  • Set up an equation based on Dalton's Law. For instance, if you know the mole ratio of gases, express the partial pressures in terms of a single variable to incorporate their relationships.
  • Use algebra to solve for the unknown. Solve the system of equations derived from Dalton's law to determine the partial pressures of gases.
Approaching problems step-by-step minimizes errors and enhances comprehension. It's often helpful to sketch out what the problem is asking for, write down relevant formulas, and consider all known values before diving into calculations. This not only aids in solving the problem correctly but also increases your understanding of the underlying chemistry principles.

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Most popular questions from this chapter

A sample of water originally at \(25^{\circ} \mathrm{C}\) is heated to \(75^{\circ} \mathrm{C}\) . As the temperature increases, the vapor pressure of the water is also observed to increase. Why? (A) Water molecules are more likely to have enough energy to break free of the intermolecular forces holding them together. (B) The covalent bonds between the hydrogen and oxygen atoms within individual water molecules are more likely to be broken. (C) The strength of the hydrogen bonding between different water molecules will increase until it exceeds the covalent bond energy within individual water molecules. (D) The electron clouds surrounding each water molecule are becoming less polarizable, weakening the intermolecular forces between them.

The first ionization energy for a neutral atom of chlorine is 1.25 \(\mathrm{MJ} / \mathrm{mol}\) and the first ionization energy for a neutral atom of argon is 1.52 \(\mathrm{MJ} / \mathrm{mol}\) How would the first ionization energy value for a neutral atom of potassium compare to those values? (A) It would be greater than both because potassium carries a greater nuclear charge then either chlorine or argon. (B) It would be greater than both because the size of a potassium atom is smaller than an atom of either chlorine or argon. (C) It would be less than both because there are more electrons in potassium, meaning they repel each other more effectively and less energy is needed to remove one. (D) It would be less than both because a valence electron of potassium is farther from the nucleus than one of either chlorine or argon.

Directions: Questions 4-7 are short free-response questions that require about 9 minutes each to answer and are worth 4 points each. Write your response in the space provided following each question. Examples and equations may be included in your responses where appropriate. For calculations, clearly show the method used and the steps involved in arriving at your answers. You must show your work to receive credit for your answer. Pay attention to significant figures. Hyprobromous acid, HBrO, is a weak monoprotic acid with a \(K_{\mathrm{a}}\) value of \(2.0 \times 10^{-9} \mathrm{at} 25^{\circ} \mathrm{C} .\) (a) Write out the equilibrium reaction of hyprobromous acid with water, identifying any conjugate acid/based pairs present. (b) (i) What would be the percent dissociation of a 0.50 M solution of hyprobromous acid? (ii) If the 0.50 M solution were diluted, what would happen to the percent dissociation of the HBrO? Why?

Which of the following ions would have the most unpaired electrons? (A) \(\mathrm{Mn}^{2+}\) (B) \(\mathrm{Ni}^{3+}\) (C) \(\mathrm{Ti}^{2+}\) (D) \(\mathrm{Cr}^{6+}\)

In general, do metals or nonmetals from the same period have higher ionization energies? Why? (A) Metals have higher ionization energies because they usually have more protons than nonmetals. (B) Nonmetals have higher ionization energies because they are larger than metals and harder to ionize. (C) Metals have higher ionization energies because there is less electron shielding than there is in nonmetals. (D) Nonmetals have higher ionization energies because they are closer to having filled a complete energy level.

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