Chapter 8: Problem 65
What ions are possible for the two largest stable elements in Group \(4 \mathrm{~A}(14) ?\) How does each arise?
Short Answer
Expert verified
Tin forms Sn虏鈦 and Sn鈦粹伜 ions; Lead forms Pb虏鈦 and Pb鈦粹伜 ions, by losing two or four electrons, respectively.
Step by step solution
01
- Identify the Group 4A elements
Group 4A (14) of the periodic table contains the elements: Carbon (C), Silicon (Si), Germanium (Ge), Tin (Sn), and Lead (Pb). The two largest stable elements in this group are Tin (Sn) and Lead (Pb).
02
- Determine the common ionic charges
Elements in Group 4A typically form either +2 or +4 oxidation states. These are derived from losing electrons to achieve a stable electron configuration.
03
- Determine the Tin (Sn) ions
Tin (Sn) can form two common ions: Sn虏鈦 and Sn鈦粹伜. The Sn虏鈦 ion is formed when Tin loses two electrons, often associated with the +2 oxidation state. The Sn鈦粹伜 ion is formed when Tin loses four electrons, associated with the +4 oxidation state.
04
- Determine the Lead (Pb) ions
Lead (Pb) also forms two common ions: Pb虏鈦 and Pb鈦粹伜. The Pb虏鈦 ion is formed when Lead loses two electrons, corresponding to the +2 oxidation state. The Pb鈦粹伜 ion is formed when Lead loses four electrons, corresponding to the +4 oxidation state.
05
- Summarize the ions and their formation
For Tin (Sn), the possible ions are Sn虏鈦 and Sn鈦粹伜, arising from the loss of two or four electrons, respectively. For Lead (Pb), the possible ions are Pb虏鈦 and Pb鈦粹伜, also arising from the loss of two or four electrons, respectively.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxidation States
Elements can show different oxidation states, which indicate the number of electrons an atom can lose, gain, or share when forming compounds. The Group 4A elements, such as Tin (Sn) and Lead (Pb), commonly display +2 and +4 oxidation states.
An oxidation state of +2 means the element has lost two electrons, while an oxidation state of +4 means the element has lost four electrons. For instance, Tin (Sn) can be found in the +2 oxidation state as Sn虏鈦 and in the +4 state as Sn鈦粹伜.
Similarly, Lead (Pb) can form ions with +2 and +4 oxidation states, resulting in Pb虏鈦 and Pb鈦粹伜 ions, respectively. These oxidation states are crucial as they determine how these elements will react and form bonds with other elements.
An oxidation state of +2 means the element has lost two electrons, while an oxidation state of +4 means the element has lost four electrons. For instance, Tin (Sn) can be found in the +2 oxidation state as Sn虏鈦 and in the +4 state as Sn鈦粹伜.
Similarly, Lead (Pb) can form ions with +2 and +4 oxidation states, resulting in Pb虏鈦 and Pb鈦粹伜 ions, respectively. These oxidation states are crucial as they determine how these elements will react and form bonds with other elements.
Electron Configuration
Electron configuration describes the arrangement of electrons around an atom's nucleus. For any element, electrons are placed into atomic orbitals following the principles of quantum mechanics. This arrangement helps determine the element鈥檚 chemical properties.
Tin (Sn) has the electron configuration [Kr] 4d鹿鈦 5s虏 5p虏. When Tin loses two electrons to form Sn虏鈦, it loses the two 5p electrons first. Changing to Sn鈦粹伜 involves losing an additional two 5s electrons.
Lead (Pb) has the electron configuration [Xe] 4f鹿鈦 5d鹿鈦 6s虏 6p虏. The Pb虏鈦 ion forms when Lead loses the two 6p electrons, and the Pb鈦粹伜 ion forms when it also loses the two 6s electrons in addition to the 6p electrons.
Knowing the electron configuration helps us understand why elements form certain ions and their likely chemical behavior.
Tin (Sn) has the electron configuration [Kr] 4d鹿鈦 5s虏 5p虏. When Tin loses two electrons to form Sn虏鈦, it loses the two 5p electrons first. Changing to Sn鈦粹伜 involves losing an additional two 5s electrons.
Lead (Pb) has the electron configuration [Xe] 4f鹿鈦 5d鹿鈦 6s虏 6p虏. The Pb虏鈦 ion forms when Lead loses the two 6p electrons, and the Pb鈦粹伜 ion forms when it also loses the two 6s electrons in addition to the 6p electrons.
Knowing the electron configuration helps us understand why elements form certain ions and their likely chemical behavior.
Ion Formation
Ion formation is the process by which atoms gain or lose electrons to achieve a full outer shell, resulting in a stable electronic structure. This process often involves energy changes, as atoms strive to reach the stable electronic configuration of the nearest noble gas.
Tin (Sn) forms Sn虏鈦 by losing the two 5p electrons, resulting in a stable configuration similar to the noble gas Krypton (Kr). To form Sn鈦粹伜, Tin also loses the two 5s electrons, achieving an even more stable configuration.
Lead (Pb) forms Pb虏鈦 ions by losing its two 6p electrons, achieving stability similar to Xenon (Xe). For Pb鈦粹伜, Lead loses the two 6s electrons in addition to the 6p electrons, leading to an even more stable structure.
This loss of electrons to form positive ions (cations) is essential for understanding how these elements interact in chemical reactions and bonding processes.
Tin (Sn) forms Sn虏鈦 by losing the two 5p electrons, resulting in a stable configuration similar to the noble gas Krypton (Kr). To form Sn鈦粹伜, Tin also loses the two 5s electrons, achieving an even more stable configuration.
Lead (Pb) forms Pb虏鈦 ions by losing its two 6p electrons, achieving stability similar to Xenon (Xe). For Pb鈦粹伜, Lead loses the two 6s electrons in addition to the 6p electrons, leading to an even more stable structure.
This loss of electrons to form positive ions (cations) is essential for understanding how these elements interact in chemical reactions and bonding processes.