Chapter 6: Problem 67
Express Hess's law in your own words.
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Chapter 6: Problem 67
Express Hess's law in your own words.
These are the key concepts you need to understand to accurately answer the question.
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High-purity benzoic acid (C \(_{6} \mathrm{H}_{3} \mathrm{COOH} ; \Delta H\) for combustion \(=\) \(-3227 \mathrm{~kJ} / \mathrm{mol}\) ) is used to calibrate bomb calorimeters. A \(1.221-\mathrm{g}\) sample burns in a calorimeter that has a heat capacity of \(6.384 \mathrm{~kJ} /{ }^{\circ} \mathrm{C}\). What is the temperature change?
You lift your textbook and drop it onto a desk. Describe the energy transformations (from one form to another) that occur, moving backward in time from a moment after impact.
Acetylene burns in air according to the following equation: $$\begin{array}{r}\mathrm{C}_{2} \mathrm{H}_{2}(g)+{ }_{2}^{5} \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g) \\ \Delta H_{\mathrm{ru}}^{\circ}=-1255.8 \mathrm{~kJ}\end{array}$$Given \(\Delta H_{\mathrm{f}}^{\circ}\) of \(\mathrm{CO}_{2}(g)=-393.5 \mathrm{~kJ} / \mathrm{mol}\) and \(\Delta H_{\mathrm{f}}^{\circ}\) of \(\mathrm{H}_{2} \mathrm{O}(g)=$$-241.8 \mathrm{~kJ} / \mathrm{mol},\) find \(\Delta H_{i}\) of \(\mathrm{C}_{2} \mathrm{H}_{2}(g)\)
Three of the reactions that occur when the paraffin of a candle (typical formula \(\mathrm{C}_{21} \mathrm{H}_{44}\) ) burns are as follows: (1) Complete combustion forms \(\mathrm{CO}_{2}\) and water vapor. (2) Incomplete combustion forms CO and water vapor. (3) Some wax is oxidized to elemental C (soot) and water vapor. (a) Find \(\Delta H_{\mathrm{rxn}}^{\circ}\) of each reaction \(\left(\Delta H_{\mathrm{f}}^{\circ}\right.\) of \(\mathrm{C}_{21} \mathrm{H}_{44}=-476 \mathrm{~kJ} / \mathrm{mol} ;\) use graphite for elemental carbon). (b) Find \(q\) (in \(\mathrm{kJ}\) ) when a 254 -g candle burns completely. (c) Find \(q\) (in kJ) when \(8.00 \%\) by mass of the candle burns incompletely and \(5.00 \%\) by mass of it undergoes soot formation.
The nutritional calorie (Calorie) is equivalent to 1 kcal. One pound of body fat is equivalent to about \(4.1 \times 10^{3}\) Calories. Express this quantity of energy in joules and kilojoules.
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