/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 82 Helium (He) is the lightest nobl... [FREE SOLUTION] | 91Ó°ÊÓ

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Helium (He) is the lightest noble gas component of air, and xenon (Xe) is the heaviest. [For this problem, use \(R=8.314 \mathrm{~J} /(\mathrm{mol} \cdot \mathrm{K})\) and express \(\mathscr{H}\) in \(\mathrm{kg} / \mathrm{mol} .]\) (a) Find the rms speed of He in winter \(\left(0 .^{\circ} \mathrm{C}\right)\) and in summer \(\left(30 .{ }^{\circ} \mathrm{C}\right)\). (b) Compare the rms speed of He with that of Xe at \(30 .^{\circ} \mathrm{C}\). (c) Find the average kinetic energy per mole of He and of Xe at \(30 .^{\circ} \mathrm{C}\). (d) Find the average kinetic energy per molecule of He at \(30 .^{\circ} \mathrm{C}\).

Short Answer

Expert verified
rms speed of He: 1258 m/s (winter), 1370 m/s (summer). rms speed of Xe: 244 m/s. KE per mole: 3.77 kJ. KE per molecule: 6.27 x 10^-21 J.

Step by step solution

01

Understanding Root Mean Square (rms) Speed

The rms speed of a gas can be calculated using the formula: \[\text{rms speed} = \sqrt{\frac{3RT}{M}}\] where \(R\) is the gas constant, \(T\) is the temperature in Kelvin, and \(M\) is the molar mass of the gas.
02

Convert Temperatures to Kelvin

Convert the given temperatures to Kelvin. \[ T_{winter} = 0 ^{\circ} \text{C} + 273.15 = 273.15 \text{ K} \]\[ T_{summer} = 30 ^{\circ} \text{C} + 273.15 = 303.15 \text{ K} \]
03

Calculate the rms Speed of Helium in Winter

Using the formula: \[\text{rms speed}_{He, winter} = \sqrt{\frac{3 \times 8.314 \times 273.15}{0.004}} \text{ m/s} \] where molar mass of He \(M = 4 \text{ g/mol} = 0.004 \text{ kg/mol} \). Calculate the value to find the rms speed of He in winter.
04

Calculate the rms Speed of Helium in Summer

Using the same formula with summer temperature: \[\text{rms speed}_{He, summer} = \sqrt{\frac{3 \times 8.314 \times 303.15}{0.004}} \text{ m/s} \]. Calculate the value to find the rms speed of He in summer.
05

Calculate the rms Speed of Xenon in Summer

Repeat the calculations for Xe with summer temperature: \[\text{rms speed}_{Xe, summer} = \sqrt{\frac{3 \times 8.314 \times 303.15}{0.1313}} \text{ m/s} \] where the molar mass of Xe \(M = 131.3 \text{ g/mol} = 0.1313 \text{ kg/mol} \). Calculate the value to find the rms speed of Xe in summer.
06

Compare the rms Speed of He and Xe

Compare the rms speeds calculated: \[\text{rms speed}_{He, summer} \text{ vs } \text{rms speed}_{Xe, summer} \]
07

Average Kinetic Energy per Mole Formula

The average kinetic energy per mole of a gas can be calculated using the formula: \[ \text{KE per mole} = \frac{3}{2}RT \]
08

Find the Average Kinetic Energy per Mole of He and Xe

Using the summer temperature: \[ \text{KE per mole}_{He} = \frac{3}{2} \times 8.314 \times 303.15 \text{ J/mol} \] \[ \text{KE per mole}_{Xe} = \frac{3}{2} \times 8.314 \times 303.15 \text{ J/mol} \] Calculate the values.
09

Find the Average Kinetic Energy per Molecule of He

Use the average kinetic energy formula per molecule: \[ \text{KE per molecule} = \frac{3}{2} k_B T \] where \(k_B = 1.38 \times 10^{-23} \text{ J/K} \) is the Boltzmann constant.Calculate with summer temperature: \[ \text{KE per molecule}_{He} = \frac{3}{2} \times 1.38 \times 10^{-23} \times 303.15 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Root Mean Square Speed
The root mean square (rms) speed of a gas is a measure of the speed of particles in a gas. It's calculated using the formula: \(\text{rms speed} = \sqrt{\frac{3RT}{M}}\).\(R\) is the gas constant, \(T\) is the temperature in Kelvin, and \(M\) is the molar mass of the gas. This formula helps understand how gas molecules move at different temperatures. For instance, the rms speed increases with temperature, meaning molecules move faster when it's warmer. The difference in rms speeds of different gases at the same temperature reflects the variation in their masses. Lighter gases like helium move faster than heavier gases like xenon.
Average Kinetic Energy
The average kinetic energy of gas particles is directly linked to temperature. It can be calculated per mole using the formula: \(\text{KE per mole} = \frac{3}{2}RT\). This formula shows that the kinetic energy is proportional to temperature. So as temperature increases, kinetic energy does too. This applies universally, meaning helium and xenon at the same temperature have the same average kinetic energy per mole. Per molecule, this translates to using Boltzmann constant \(k_B\) instead: \(\text{KE per molecule} = \frac{3}{2}k_BT\) with \(k_B ≈ 1.38 \times 10^{-23} \text{ J/K}\). This relationship highlights the consistency of thermal energy distribution across different gases.
Molar Mass Conversion
When working with the rms speed formula, molar mass must be converted to kg/mol for consistency with the gas constant \(R = 8.314 \text{ J} / (\text{mol} \text{ K})\). For instance, helium has a molar mass of 4 g/mol, which converts to 0.004 kg/mol by dividing by 1000. Similarly, xenon's molar mass of 131.3 g/mol becomes 0.1313 kg/mol. This conversion is crucial for accurate calculations in the rms speed formula, ensuring all units match up for a correct result.
Temperature Conversion
Temperatures often need converting to Kelvin for scientific calculations. This involves adding 273.15 to the Celsius measurement. For example, 0°C becomes 273.15 K and 30°C becomes 303.15 K. This conversion is essential as formulas like rms speed and kinetic energy use Kelvin directly. Kelvin ensures absolute values are used, reflecting true thermal energy levels in calculations. Always remember to convert temperatures to Kelvin first to maintain accuracy in your computations.

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Most popular questions from this chapter

Popcorn pops because the horny endosperm, a tough, elastic material, resists gas pressure within the heated kernel until the pressure reaches explosive force. A 0.25 -mL kernel has a water content of \(1.6 \%\) by mass, and the water vapor reaches \(170^{\circ} \mathrm{C}\) and 9.0 atm before the kernel ruptures. Assume that water vapor can occupy \(75 \%\) of the kernel's volume. (a) What is the mass (in g) of the kernel? (b) How many milliliters would this amount of water vapor occupy at \(25^{\circ} \mathrm{C}\) and 1.00 atm?

A 93-L sample of dry air cools from \(145^{\circ} \mathrm{C}\) to \(-22^{\circ} \mathrm{C}\) while the pressure is maintained at 2.85 atm. What is the final volume?

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